Course Information
Course Code: STT 200
Course Name: Statistical Methods
Learning Goals
Parametric Confidence Intervals for a Mean
Determining sample size
Parametric Hypothesis Test for a Mean
Announcements
Exam Date: April 1, 2026 (Wednesday)
Time: 7:45 PM to 9:00 PM
Arrival: 7:30 PM at the testing venue
Venues for Exam:
Sections 49-58: Business N130
Sections 59-60: Wells Hall B117
What to Bring to the Exam:
MSU ID (needed for building access)
A #2 pencil
Graphing calculator
Exam 2 Topics
Topics Covered: Same as HWs 5, 6, and 7:
4.1 The Central Limit Theorem
4.2 The normal distribution
4.3 Mathematical model for the sampling distribution of a single proportion
4.4 Parametric hypothesis test for a single proportion
4.5 Bootstrap confidence interval for a single proportion
4.6 Parametric confidence interval for a single proportion
4.7 Chi-squared goodness of fit (GOF) test
4.8 Chi-squared independence test
5.1 Bootstrap confidence interval for a single mean
5.2 Mathematical model for the sampling distribution of a single mean and t-distributions
5.3 Parametric confidence interval for a single mean
5.3 Parametric Confidence Intervals for a Single Mean
Example: The Campus That Never Sleeps
A random sample of 50 STT 200 students at MSU was surveyed about their nightly sleep.
Statistical Summary of Responses:
Sample mean, 𝑥̄: 7.19
Sample standard deviation, s: 1.19
Sample size, n: 50
Minimum sleep reported: 5 hours
Maximum sleep reported: 10 hours
Constructing a 95% Confidence Interval
Method: Use TInterval function from the calculator's STATS>TESTS menu
Accessing More Decimal Places with TInterval
To view more decimal places:
Press VARS key, select Statistics (option 5)
Scroll to TEST menu, select H (lower) for lower bound, I (upper) for upper bound
True or False Questions for Confidence Intervals
The 95% confidence interval for sleep is approximately (6.85, 7.53).
Assessing Statements:
False: "95% of STT 200 students get between 6.85 and 7.53 hours of sleep."
True: "We are 95% sure the average number of hours STT 200 students sleep is between 6.85 and 7.53."
Additional True or False:
True: "If we take 1000 random samples, about 950 confidence intervals will contain the true average sleep hours."
False: "About 950 of the sample means will fall between 6.85 and 7.53."
Deconstructing a Confidence Interval
Form: point estimate ± margin of error (ME)
Margin of Error Equation:
ME = t^* imes rac{s}{
}To Reduce Margin of Error:
Lower the confidence level (making t* smaller)
Increase sample size
Determining Sample Size Given Margin of Error (ME)
Margin of Error Equation:
ME = t^* imes rac{s}{n}Solve for n:
n = rac{(t^*s)}{ME^2}Estimation: Use previous sample to estimate s and the degrees of freedom for t^*
Rounding: Always round n up to the next integer value
Example: The City That Never Sleeps
Revisit the previous sample of 50 STT 200 students to determine necessary sample size for estimating average sleep within 0.25 hours at 95% confidence:
Data:
Sample mean, 𝑥̄: 7.19
Sample standard deviation, s: 1.19
Sample size, n: 50
5.4 Parametric Hypothesis Tests for a Population Mean
General Steps in Hypothesis Testing
State Hypotheses:
Null Hypothesis (H0): 𝜇 = 𝜇0
Alternative Hypothesis (HA): 𝜇 ≠ 𝜇0 or < or >
Check Conditions:
Observations must be independent.
Sample size sufficient: n ≥ 30 (can relax for normal populations)
Compute Test Statistic and p-value:
Test Statistic Formula:
t = rac{ar{x} - ext{μ}_0}{ rac{s}{
}}p-value: Area beyond t in t-distribution with n - 1 degrees of freedom
Find area using tcdf() function
Evaluate Results:
Interpret p-value:
p > 0.10: Little evidence
0.05 < p ≤ 0.10: Some evidence
0.01 < p ≤ 0.05: Strong evidence
0.001 < p ≤ 0.01: Very strong evidence
p ≤ 0.001: Extremely strong evidence
Example: Classical Music
Research Objective: Test if high school students complete a maze faster while listening to classical music.
Assumed mean completion time for the general population: 40 seconds.
Sample Size: 100 HS students; Mean: 39.1 seconds; Standard Deviation: 4 seconds.
Step 1: Stating Hypotheses
Parameter of Interest: Let 𝜇 represent the average time to complete the maze while listening to classical music.
Hypotheses:
H0: \ 𝜇 = 40
HA: \ 𝜇 < 40
Step 2: Checking Conditions
Observations: Independent? Yes
Sample size: n > 30? Yes, n = 100
Step 3: Computing Test Statistic and Finding p-value
Test Statistic Calculation:
t = rac{39.1 - 40}{ rac{4}{ ext{√}100}} = -2.25Finding p-value:
Use t-distribution with 99 degrees of freedom:
p ext{-value} = ext{tdf}(-10^10, -2.25, 99) = 0.0133
Step 4: Evaluating Results
Interpret p-value: Strong evidence for HA.
Using the Calculator
T-Test Input:
X̄: 39.1
Sx: 4
n: 100
t-statistic: -2.25
p-value: 0.0133