Comprehensive Notes on Function Transformations, Parent Functions, Piecewise Functions, and Function Composition

General Study Advice and Graphing Fundamentals

  • Exam and Homework Preparation Strategy:

    • Even when homework assignments are completed online, always maintain written notes on paper.

    • Write down each problem statement fully, solve or sketch the graph on paper step-by-step, and then enter the final response into the online portal.

    • Understanding paper-based graphical methods is essential for mastery on paper-based exams.

  • Linear Equations Review:

    • An equation is classified as linear when both variables (xx and yy) are raised to the first power (e.g., y=xy = x or y=mx+by = mx + b).

    • Graphing a Line using Slope: For a linear function with an ordered pair at (0,1)(0, -1) and a slope of 44 (41\frac{4}{1}), start at (0,1)(0, -1), move 44 units up and 11 unit to the right to locate the next point (1,3)(1, 3), and connect the points with a straight line.

  • Table of Values Method for Graphing:

    • If the general shape of any parent function or transformed graph is forgotten, select arbitrary xx-values across the domain, substitute them into the function to find corresponding yy-values, plot the resulting ordered pairs (x,y)(x, y), and connect them to reveal the graph's curve.

Basic Tool Field (Parent) Functions

  • Constant Function:

    • Equation: y=cy = c

    • Graph: A horizontal line passing through (0,c)(0, c).

  • Identity Function:

    • Equation: y=xy = x

    • Graph: A straight line passing through the origin (0,0)(0, 0) with a slope of 11, bisecting the first and third quadrants.

  • Absolute Value Function:

    • Equation: y=xy = |x|

    • Graph: A V-shaped graph composed of two linear rays joining at a central point called the vertex (0,0)(0, 0).

    • Behavior: The left branch has a negative slope (y=xy = -x for x<0x < 0) and the right branch has a positive slope (y=xy = x for x0x \neq 0).

    • Range: [0,1)[0, \frac{\infty}{1}) (or [0, \text{\infty})), because absolute value outputs can never be negative.

  • Quadratic Function:

    • Equation: y=x2y = x^2

    • Graph: A U-shaped curve called a parabola opening upward with its vertex at (0,0)(0, 0).

  • Cubic Function:

    • Equation: y=x3y = x^3

    • Graph: An S-shaped curve passing through the origin (0,0)(0, 0), extending into the first and third quadrants.

  • Square Root Function:

    • Equation: y=xy = \sqrt{x}

    • Graph: A curve representing the upper half of a sideways parabola, starting at (0,0)(0, 0) and extending into quadrant I.

    • Domain and Range: [0,)[0, \infty).

  • Cube Root Function:

    • Equation: y=x3y = \sqrt[3]{x}

    • Graph: An origin-symmetric curve extending infinitely in both positive and negative directions across all real numbers.

  • Reciprocal Function:

    • Equation: y=1xy = \frac{1}{x}

    • Domain Restriction: x0x \neq 0 (division by zero is undefined).

    • Vertical Asymptote: The line x=0x = 0 (coinciding with the y-axis). The graph approaches this line infinitely close but never touches or crosses it.

    • Horizontal Asymptote: The line y=0y = 0 (coinciding with the x-axis), because 11 divided by any real number yields a non-zero value.

  • Reciprocal Square Function:

    • Equation: y=1x2y = \frac{1}{x^2}

    • Domain Restriction: x0x \neq 0

    • Behavior: Similar asymptotes to the reciprocal function at x=0x = 0 and y=0y = 0, but because x2>0x^2 > 0 for all non-zero xx, both branches lie entirely above the x-axis in quadrants I and II.

Transformations of Functions

  • General Transformation Formula Notation:     y=af(b(x+c))+dy = a \cdot f(b(x + c)) + d

  • Vertical Stretch and Compress (aa):

    • aa is multiplied outside the parent function ff

    • Vertical Stretch: Occurs when a>1|a| > 1. The graph is elongated vertically, making it narrower. All yy-coordinates of the parent function are multiplied by aa

    • Vertical Compression (Shrink): Occurs when 0<a<10 < |a| < 1. The graph is flattened vertically, making it wider

  • Vertical Reflection (aa):

    • Positive aa (a>0a > 0): Graph opens/remains in its standard vertical orientation

    • Negative aa (a<0a < 0): Graph reflects vertically across the x-axis (flips upside down)

  • Horizontal Stretch and Compress (bb):

    • bb is multiplied inside the function argument directly next to xx

    • Horizontal Compression (Shrink): Occurs when b>1b > 1

    • Horizontal Stretch: Occurs when 0<b<10 < b < 1

  • Horizontal Reflection (bb):

    • Negative bb (b<0b < 0): Graph reflects horizontally across the y-axis (flips left-to-right)

  • Vertical Shift (dd):

    • dd is added or subtracted outside the main function

    • +d+d: Shifts the entire graph UP by dd units

    • d-d: Shifts the entire graph DOWN by dd units

  • Horizontal Shift (cc):

    • cc is added or subtracted inside the function argument directly to xx

    • Opposite Sign Rule: The shift direction is opposite to the sign of cc (the value that brings the argument back to zero)

    • +c+c (e.g., f(x+c)f(x + c)): Shifts the graph LEFT by cc units

    • c-c (e.g., f(xc)f(x - c)): Shifts the graph RIGHT by cc units

Transformation Examples and Graphing Applications

  • Identification Examples:

    • f(x)=(x+18)2f(x) = (x + 18)^2 compared to f(x)=x2f(x) = x^2: Shifted 18 units to the left because +18+18 is inside the function.

    • f(x)=x2+18f(x) = x^2 + 18 compared to f(x)=x2f(x) = x^2: Shifted 18 units up because +18+18 is outside the function.

    • f(x)=18xf(x) = 18\sqrt{x} compared to f(x)=xf(x) = \sqrt{x}: Vertical stretch by a factor of 1818 because 18>118 > 1 is outside the square root.

    • f(x)=18xf(x) = \sqrt{18x} compared to f(x)=xf(x) = \sqrt{x}: Horizontal compression (shrinking) by a factor of 1818 because 18>118 > 1 is inside the square root.

  • Absolute Value Transformations:

    • y=xy = -|x|: Reflects the standard absolute value graph vertically over the x-axis (V-shape opening downward).

    • y=x+4+3y = |x + 4| + 3:

      • Shift 4 units left and 3 units up.

      • Parent vertex (0,0)(0, 0) moves to (4,3)(-4, 3).

      • Parent point (1,1)(1, 1) transforms to (3,4)(-3, 4) via xnew=14=3x_{\text{new}} = 1 - 4 = -3 and ynew=1+3=4y_{\text{new}} = 1 + 3 = 4

  • Graph Matching Equations:

    • Absolute value vertex located at (1,3)(1, -3): Equation is y=x13y = |x - 1| - 3

    • Absolute value vertex shifted to (3,0)(-3, 0): Equation is y=x+3y = |x + 3|

  • Advanced Parabola Transformation Example: y=2(x1)2+3y = -2(x - 1)^2 + 3

    • Parent function: f(x)=x2f(x) = x^2

    • Shift right by 11 unit (1-1 inside) and shift up by 33 units (+3+3 outside).

    • New vertex: (1,3)(1, 3).

    • Negative sign (-$action) reflects parabola downward across x-axis.\n * Coefficient 2stretchesgraphverticallybyafactorofstretches graph vertically by a factor of2 (making it narrower).\n\n# Piecewise Functions\n\n* **Definition**: A piecewise function is a function defined by multiple sub-functions, each applying to a distinct interval of the domain (x-values).\n\n* **Endpoint Conventions**:\n * **Filled (Solid) Circle**: Used when an endpoint is included in the domain interval (indicated by \leoror\ge).\n * **Open Circle**: Used when an endpoint is excluded from the domain interval (indicated by strict inequalities <oror>).\n\n* **Comprehensive Piecewise Example**:\n         f(x) = \begin{cases} -x - 6 & \text{if } x \le -4 \ 2 & \text{if } -4 < x \le 3 \ 2x - 4 & \text{if } x > 3 \end{cases}     \n\n * **Piece 1 (y = -x - 6forforx \le -4)**:\n * Evaluate endpoint at x = -4::y = -(-4) - 6 = -2 \rightarrow (-4, -2).Plotwithasolidcirclebecauseinequalityis. Plot with a **solid circle** because inequality is\le.\n * Evaluate secondary point at x = -5::y = -(-5) - 6 = -1 \rightarrow (-5, -1).\n * Graph shape: A ray starting at (-4, -2) extending upward to the left.\n\n * **Piece 2 (y = 2forfor-4 < x \le 3)**:\n * Horizontal line segment at constant height y = 2\n * Left endpoint at x = -4::(-4, 2)plottedwithanopencirclebecauseinequalityisstrictlyplotted with an **open circle** because inequality is strictly> -4\n * Right endpoint at x = 3::(3, 2)plottedwithasolidcirclebecauseinequalityisplotted with a **solid circle** because inequality is\le 3\n\n * **Piece 3 (y = 2x - 4forforx > 3)**:\n * Evaluate boundary at x = 3::y = 2(3) - 4 = 2 \rightarrow (3, 2). Plot with an **open circle** (overlaps the solid endpoint from Piece 2).\n * Evaluate secondary point at x = 4::y = 2(4) - 4 = 4 \rightarrow (4, 4).\n * Graph shape: A ray extending upward to the right starting from (3, 2).\n\n# Composition of Functions\n\n* **Definition & Notation**:\n * Composition notation: (f \circ g)(x) = f(g(x))\n * The output of the inside function g(x)becomestheinputdomainfortheoutsidefunctionbecomes the input domain for the outside functionf(x).\n\n* **Real-World Application (Successive Discounts)**:\n * Scenario: A pair of \$50jeansisdiscountedbyjeans is discounted by50\%,withanadditional, with an additional10\% discount applied at checkout when using a store credit card.\n * Step 1 (First function g(x)):Apply): Apply50\%discounttodiscount to\$50::g(50) = 50 \times (1 - 0.50) = \$25\n * Step 2 (Second function f(x)):Apply): Apply10\%creditcarddiscounttothediscountedpriceofcredit card discount to the discounted price of\$25::f(25) = 25 - (25 \times 0.10) = \$22.50\n * Composite Result: f(g(50)) = \$22.50(Note:Thisisnotequaltoaflat(Note: This is not equal to a flat60\%discount,whichwouldyielddiscount, which would yield\$20).\n\n* **Numerical Evaluation Example**:\n * Given f(x) = 4x - 3andandg(x) = 4x^2 + 8x + 7,evaluate, evaluatef(g(-3)):\n * Step 1: Evaluate inside function g(-3):\n        g(-3) = 4(-3)^2 + 8(-3) + 7 = 4(9) - 24 + 7 = 36 - 24 + 7 = 19\n * Step 2: Substitute 19intooutsidefunctioninto outside functionf(x):\n        f(19) = 4(19) - 3 = 76 - 3 = 73\n * Final Answer: f(g(-3)) = 73\n\n* **Algebraic Composition Example 1 (f(g(x)))**:\n * Given f(x) = \frac{1}{x - 3}andandg(x) = \frac{1}{x} - 3:\n * Substitute g(x)intointof(x):\n        f(g(x)) = \frac{1}{\left(\frac{1}{x} - 3\right) - 3} = \frac{1}{\frac{1}{x} - 6}\n * Find a common denominator for the denominator expression:\n        \frac{1}{x} - 6 = \frac{1 - 6x}{x}\n * Invert and multiply to simplify the complex fraction:\n        f(g(x)) = \frac{x}{1 - 6x}\n\n* **Algebraic Composition Example 2 (g(f(x)))**:\n * Given f(x) = \frac{1}{x - 3}andandg(x) = \frac{1}{x} - 3:\n * Substitute f(x)intointog(x):\n        g(f(x)) = \frac{1}{\left(\frac{1}{x - 3}\right)} - 3\n * Simplify the complex fraction:\n        \frac{1}{\frac{1}{x - 3}} = x - 3\n * Subtract 3:\n        g(f(x)) = (x - 3) - 3 = x - 6\n\n# Questions & Discussion\n\n* **Question**: Can formula sheets or specific transformation notes be brought into exams?\n * **Answer**: Yes, notes summarizing general transformation formulas (such as the roles of a,,b,,c,and, andd) are permitted for exam reference.\n\n* **Question**: Is the constant d in function transformations always equivalent to the y-intercept?\n * **Answer**: No. For linear functions, dcorrespondstotheyintercept.However,fornonlinearfunctions(suchasquadraticorabsolutevaluefunctions),corresponds to the y-intercept. However, for non-linear functions (such as quadratic or absolute value functions),drepresentsverticalshifting,andtheyinterceptmustbefoundseparatelybyevaluatingrepresents vertical shifting, and the y-intercept must be found separately by evaluatingf(0).\n\n* **Question**: Does multiplying a function by a constant factor greater than 1 make the graph wider?\n * **Answer**: No. A coefficient |a| > 1causesverticalstretching,makingthegraphnarrower.Agraphbecomeswiderwhenthecoefficientliesbetweencauses vertical stretching, making the graph narrower. A graph becomes wider when the coefficient lies between0andand1(e.g.,(e.g.,a = \frac{1}{2}$$).