Introduction to Mathematics for Electronic Systems

Course Overview and Logistics

  • Instructors:
    • Prirak Deep
    • Dr. Shivakrishna Dasi
  • Session Schedule: Friday, Sunday, and Tuesday.
  • Session Types:
    • Instructor Sessions: Focused on summarizing the weekly content.
    • TA (Teaching Assistant) Sessions: Primarily focused on problem-solving exercises.
  • Eligibility and Grading Criteria:
    • Final Course Grade Eligibility: The student must attend the Final Exam.
    • Final Exam Writing Eligibility:
      • The average score of the best 5 out of the first 7 weekly assignments must be greater than or equal to $40/100$.
      • Completion of at least one of the two scheduled quizzes.
  • Score Calculation Formula (TT):
    • T=max(0.6×F+0.3×max(Qz1,Qz2),0.45×F+0.25×Qz1+0.3×Qz2)T = \max(0.6 \times F + 0.3 \times \max(Qz1, Qz2), 0.45 \times F + 0.25 \times Qz1 + 0.3 \times Qz2)
    • Where FF is the Final Exam score, and Qz1,Qz2Qz1, Qz2 are the scores for Quiz 1 and Quiz 2 respectively.

Importance of Mathematics in Electronic Systems

  • Role of Numbers and Relationships: Quantitative data and the functional relationships between them are essential for specifying and designing electronic systems.
  • Case Study: Travel Adapter (Model: PEM-2134):
    • Input: 100240 VAC100-240\text{ VAC}, 5060 Hz50-60\text{ Hz}, 0.5 A0.5\text{ A}.
    • Output: 5 V5\text{ V}, 2.0 A2.0\text{ A}.
  • Case Study: Audio System Specifications:
    • Power Output: 75 Watts75\text{ Watts} per channel at 1 kHz1\text{ kHz} into 8Ω8\Omega.
    • Input Impedance: >14 kΩ>14\text{ k}\Omega, line input.
    • Input Sensitivity: 250 mV250\text{ mV}.
    • Pre-amplifier Output Gain: +18 dB+18\text{ dB}.
    • Frequency Response: 20 Hz20 kHz±0.5 dB20\text{ Hz}-20\text{ kHz} \pm 0.5\text{ dB}.
    • Total Harmonic Distortion: <0.05%<0.05\% at rated output, ref. 1 kHz1\text{ kHz}.
    • Signal to Noise Ratio: >100 dB>100\text{ dB}, A weighted, ref. rated output.
    • Channel Separation: >60 dB>60\text{ dB}, 20 Hz20 kHz20\text{ Hz}-20\text{ kHz}.
    • Mains Supply: 110/120 V110/120\text{ V} or 220/240 V220/240\text{ V}, 50/60 Hz50/60\text{ Hz}.
    • Power Consumption: <200 VA<200\text{ VA}, 8Ω8\Omega load, both channels driven.
    • Dimensions: 90 mm (h)×440 mm (w)×310 mm (d)90\text{ mm (h)} \times 440\text{ mm (w)} \times 310\text{ mm (d)}.
    • Weight: Net 7 kg7\text{ kg}, Gross 9 kg9\text{ kg}.
  • Case Study: Elevator (Lift) Design Parameters:
    • Number of Floors: 1616.
    • Number of Shafts (Cages): 6(12)6(12).
    • Floor Distance: 4.5 m4.5\text{ m}.
    • Max Velocity: 2.5 m/s2.5\text{ m/s}.
    • Max Acceleration: 0.7 m/s20.7\text{ m/s}^2.
    • Jerk: 0.7 m/s30.7\text{ m/s}^3.
    • Cage Capacity: 20 persons20\text{ persons}.
    • Time for Opening Door: 2.0 s2.0\text{ s}.
    • Time for Closing Door: 2.3 s2.3\text{ s}.
    • Time for Riding: 1.0 s/person1.0\text{ s/person}.
    • Passenger Density (Regular/Up-peak/Down-peak): 3000,2700,3300 persons/h3000, 2700, 3300\text{ persons/h}.

Mathematical Frameworks in Electronics

  • Electronic Circuit Problems: The goal is to find precise relationships between voltages and currents at various points in a circuit.
  • Key Mathematical Concepts:
    • Linear Equations: Used for DC (Direct Current) circuits.
    • Functions of One Variable: Voltage and current are treated as signals, which are functions of time (tt).
    • Calculus (Differentiation and Integration): Essential because physical properties like the current through a capacitor depend on the rate of change of voltage (I=CdVdtI = C \frac{dV}{dt}).
    • Differential Equations: Used for circuits containing time-varying voltages and currents.
    • Complex Numbers: Utilized to analyze AC (Alternating Current) circuits in a steady state.

Physical Quantities and Linear Relations

  • Relationship Examples:
    1. Ohm's Law: Voltage=Resistance×Current\text{Voltage} = \text{Resistance} \times \text{Current} (V=RIV = RI). In a graph of VV vs II, the slope tan(θ)=R\tan(\theta) = R.
    2. Newton's Second Law: Force=Mass×Acceleration\text{Force} = \text{Mass} \times \text{Acceleration} (F=ma=mdvdtF = ma = m \frac{dv}{dt}). In a graph of FF vs aa, the slope tan(θ)=m\tan(\theta) = m.
  • Equation of a Straight Line:
    • Passing through origin: y=mxy = mx, where m=tan(θ)m = \tan(\theta) is the slope.
    • General form: y=mx+by = mx + b, where bb is the y-axis intercept.
  • Slope Comparisons:
    • For three lines passing through the origin with slopes a,b,ca, b, c and angles θ3>θ2>θ1\theta_3 > \theta_2 > \theta_1:
    • a=tan(θ3)a = \tan(\theta_3), b=tan(θ2)b = \tan(\theta_2), c=tan(θ1)c = \tan(\theta_1).
    • If θ1<θ2<θ3\theta_1 < \theta_2 < \theta_3, then tan(θ1)<tan(θ2)<tan(θ3)\tan(\theta_1) < \tan(\theta_2) < \tan(\theta_3), which implies c<b<ac < b < a.
  • Identifying Non-Linear Relationships:
    • y=4x+7y = 4x + 7: Linear (y=mx+by = mx + b).
    • y=3x+1y = \frac{3}{x} + 1: Non-linear (reciprocal relationship).
    • y=x(x2)y=x22xy = x(x - 2) \rightarrow y = x^2 - 2x: Non-linear (Quadratic).
    • y=3(x4)2y=3(x28x+16)y = 3(x - 4)^2 \rightarrow y = 3(x^2 - 8x + 16): Non-linear (Quadratic).

Quadratics and Exponentials

  • Quadratics:
    • General form: y=ax2+bx+cy = ax^2 + bx + c.
    • Shape: Parabolic.
    • Applications: MOSFET current-voltage characteristics, area computations, and distance calculations under constant acceleration.
  • Exponentials:
    • General forms: y=P(1+r)ty = P(1 + r)^t or y=kaxy = k a^x.
    • Applications: Diode current characteristics, compound interest calculations, and iterative computations.

Function Notation and Definitions

  • Definition: A function ff maps a real number xx (from domain) to a unique real number f(x)f(x) (in codomain).
  • Notation: f:RRf: \mathbb{R} \rightarrow \mathbb{R}. The symbol xRx \in \mathbb{R} means "x is a real number".
  • Specifying Values:
    • Constant Function: f(x)=cf(x) = c (same value for every xx).
    • Linear Function: f(x)=mxf(x) = mx.
    • Quadratic Function: f(x)=ax2+bx+cf(x) = ax^2 + bx + c.
    • Exponential Function: f(x)=P(1+r)xf(x) = P(1 + r)^x.
  • Function Composition: Functions can be combined. For example, if f(x)=x2f(x) = x^2 and h(x)=ax2+bh(x) = ax^2 + b:
    • f(h(x))=(ax2+b)2f(h(x)) = (ax^2 + b)^2
    • h(f(x))=a(x2)2+b=ax4+bh(f(x)) = a(x^2)^2 + b = ax^4 + b
  • Identifying Quadratic Functions:
    • f(x)=7x+10f(x) = 7x + 10 (Linear)
    • f(x)=3x2+9x+19f(x) = 3x^2 + 9x + 19 (Quadratic)
    • f(x)=x3+x2+x+1f(x) = x^3 + x^2 + x + 1 (Cubic / Polynomial)
    • f(x)=(x+1)2(x+1)=x2+2x+1x1=x2+xf(x) = (x+1)^2 - (x+1) = x^2 + 2x + 1 - x - 1 = x^2 + x (Quadratic)

Functions from Graphs

  • Vertical Line Test: A graph represents a function if any vertical line crosses the plot at exactly one point. If it crosses at more than one point, it is a relationship but not a function.
  • Range:
    • If f(x)=3f(x) = 3, the range is the set 3R{3} \subset \mathbb{R}.
    • If f(x)=x2f(x) = x^2, the range is the set yy0R{y \mid y \ge 0} \subset \mathbb{R}.

Operations with Functions

  • Arithmetic Operations:
    • Addition/Subtraction: f(x)+g(x)f(x) + g(x) or f(x)g(x)f(x) - g(x).
    • Multiplication: f(x)g(x)f(x)g(x).
    • Division: f(x)g(x)\frac{f(x)}{g(x)}.
  • Example Calculations:
    • Let f(x)=x2f(x) = x^2, g(x)=2x+1g(x) = 2x + 1, and h(x)=5h(x) = 5.
    • f(x)+g(x)=x2+2x+1=(x+1)2f(x) + g(x) = x^2 + 2x + 1 = (x + 1)^2.
    • f(x)g(x)=x2(2x+1)=2x3+x2f(x)g(x) = x^2(2x + 1) = 2x^3 + x^2.
    • g(x)h(x)=2x+15\frac{g(x)}{h(x)} = \frac{2x + 1}{5}.

Word Problem Formulations

  • Problem 1: Vaccine Manufacturing Cost:
    • yy = Number of vaccines per day.
    • Manufacturing cost per vaccine = 100+y100 + y.
    • Total manufacturing cost = 10,00010,000.
    • Equation: y(100+y)=10,000y2+100y=10,000y(100 + y) = 10,000 \rightarrow y^2 + 100y = 10,000.
  • Problem 2: Mango Distribution:
    • Let Mahesh have xx mangoes and Sandhya have yy mangoes.
    • Total mangoes: x+y=20y=20xx + y = 20 \rightarrow y = 20 - x.
    • Mahesh loses 3 (x3x - 3) and Sandhya loses 4 (y4y - 4).
    • The product of the remaining mangoes is 42: (x3)(y4)=42(x - 3)(y - 4) = 42.
    • Substitute yy: (x3)(20x4)=42(x3)(16x)=42(x - 3)(20 - x - 4) = 42 \rightarrow (x - 3)(16 - x) = 42.
    • Expand: 16xx248+3x=42x2+19x48=42x219x+90=016x - x^2 - 48 + 3x = 42 \rightarrow -x^2 + 19x - 48 = 42 \rightarrow x^2 - 19x + 90 = 0.
    • Factor: (x9)(x10)=0(x - 9)(x - 10) = 0.
    • Solutions: x=9x = 9 or x=10x = 10.