CLASS 8

Chapter 5: Normal Distribution (Part I)
Normal Distribution
  • Definition: A continuous random variable with a symmetric, bell-shaped distribution centered at the mean (μ\mu).

    • Probability Density Function (PDF): f(x)=1σ2πe12(xμσ)2f(x) = \frac{1}{\sigma\sqrt{2\pi}} e^{-\frac{1}{2}(\frac{x-\mu}{\sigma})^2}

    • μ\mu = population mean

    • σ\sigma = population standard deviation

Properties of Normal Distribution Curve:

  • Total Area: Equals 11.

  • Bell-Shaped: Characteristic curve shape.

  • Symmetric: Around the mean ($\mu$).

  • Centering: At the mean ($\mu$).

  • Asymptotic: Tails approach, but never touch, the x-axis.

Graph Characteristics:

  • Determined by μ\mu and σ\sigma.

  • Change in σ\sigma: Wider (larger σ\sigma) or narrower (smaller σ\sigma).

  • Change in μ\mu: Shifts graph left or right.

Empirical Rule for Bell-Shaped Distributions (68-95-99.7)
  • Valid for approximately normal distributions:

    • 68% Rule: Approximately 68%68\% of values lie within ±1\pm 1 standard deviation of the mean [μσ,μ+σ][\mu - \sigma, \mu + \sigma].

    • 95% Rule: Approximately 95%95\% of values fall within ±2\pm 2 standard deviations of the mean [μ2σ,μ+2σ][\mu - 2\sigma, \mu + 2\sigma]. (Usual values)

    • 99.7% Rule: Approximately 99.7%99.7\% of values are within ±3\pm 3 standard deviations of the mean [μ3σ,μ+3σ][\mu - 3\sigma, \mu + 3\sigma]. (Almost all values)

Standard Normal Distribution
  • Definition: A special normal distribution with μ=0\mu = 0 and σ=1\sigma = 1, denoted as ZN(0,1)Z \sim N(0, 1).

  • Characteristics: Always centered at 00, horizontal axis values are z-scores.

  • Z-Score Formula: Z=XμσZ = \frac{X - \mu}{\sigma}

    • Positive z-score: above the mean.

    • Negative z-score: below the mean.

    • Z-score of 00: at the mean.

  • Probability: Area under the density curve corresponds to probabilities.

Types of Problems:

  1. Given z-score: Find probability (area).

  2. Given probability (area): Find z-score.

Case 1: Finding Probability Using z-Scores
  • Example 1 (P(z < 1)): For z=1z = 1, area from z-table is 0.84130.8413. So, P(z < 1) = 0.8413.

  • Example 2 (P(z > -1.02)): P(z > -1.02) = 1 - P(z < -1.02) = 1 - 0.1539 = 0.8461.

Case 2: Finding z-Score Given Probability
  • Example (85th85^{th} percentile): For an area of 0.850.85, the z-score is approximately 1.0361.036 (looking up 0.85000.8500 in the z-table).

Example 4: Calculate Probabilities for N(0,1)N(0, 1)
  1. P(Z > 3.58) = 1 - P(Z < 3.58) = 1 - 0.9998 = 0.0002.

  2. P(Z > -1.73) = 1 - P(Z < -1.73) = 1 - 0.0418 = 0.9582.

  3. P(1.24 < Z < 2.58) = P(Z < 2.58) - P(Z < 1.24) = 0.9951 - 0.8925 = 0.1026.

Important Formulas:
  • P(Z < +a) = \text{use positive table}

  • P(Z < -a) = \text{use negative table}

  • P(Z > a) = 1 - P(Z < a)

  • P(a < Z < b) = P(Z < b) - P(Z < a)

Test Your Knowledge
  1. Calculate Area (P(Z > -2.72)): 1 - P(Z < -2.72) = 1 - 0.0033 = 0.9967.

  2. Determine z-score (for 0.120.12 area): Approximately z=1.175z = -1.175.

  3. Find Probabilities:

    • P(Z < 1.72) = 0.9573

    • P(Z < -2.10) = 0.0179

    • P(Z < 0.89) = 0.8133

  4. Calculate Probabilities:

    • P(Z > 1) = 1 - P(Z < 1) = 1 - 0.8413 = 0.1587

    • P(Z > 2.54) = 1 - P(Z < 2.54) = 1 - 0.9945 = 0.0055

    • P(-0.52 < Z < 1.80) = P(Z < 1.80) - P(Z < -0.52) = 0.9641 - 0.3015 = 0.6626

  5. Determine z-score for areas (Critical Values):

    • ±1.645\pm 1.645 (for central $$90\