Group WBs: Semester 1 Review Study Notes
Group WBs: Semester 1 Review
1. Inverse of Functions
- Find the inverse of each function:
- 1) Function: f(x) = -2x - 4
- Inverse Steps:
- Solve for x:
- x = -2y - 4
- y = -1/2(x + 4)
- Inverse Function: f⁻¹(x) = -1/2(x + 4)
- 2) Function: f(x) = -2/3 * (-x - 2)
- Inverse Steps:
- Solve for x:
- Multiply both sides by -3/2;
- y = -3/2(x + 2)
- Inverse Function: Anti-correlation function
- 3) Function: g(x) = -4x + 16
- Inverse Steps:
- Solve for x:
- x = -4y + 16
- conveys direct inverse depending on slope which leads to 16 -4x
- Inverse Function: g⁻¹(x) = (16 - x)/4
- 4) Function: g(x) = -(-x - 2)
- Inverse Function:
- Creates overlap with original as it satisfies inverse conditions
2. Rate of Change
- Find the rate of change for specific intervals of x:
- 5) From x = 1 to x = 4
- Data Points:
- x: 0, 1, 2, 3, 4, 5
- f(x): 1, 5, 10, 8, 3, 14
- Calculation:
- Rate of Change = (f(4) - f(1)) / (4 - 1) = (3 - 5) / (4 - 1) = -2/3
- 6) From x = 3 to x = 5
- Data Points:
- X: 3 -> 5
- f(3): 8, f(5): 14
- Calculation:
- Rate of Change = (f(5) - f(3)) / (5 - 3) = (14 - 8) / (5 - 3) = 6/2 = 3
- 7) From x = -3 to x = -1
- 18) From x = 10 to x = 20
- Recall the quadratic formula:
- The quadratic formula is used to find the solutions of ax² + bx + c = 0. This can be expressed as
- x=2a−b±b2−4ac
4. Graphing Equations
- Graph each equation:
- 10) Equation: y = |x + 2| + 4
- 11) Equation: y = 2x - 4
5. Solving Equations
- Solve each equation:
- 12) Equation: |106 - 11| = 31
- Solve absolute equation systematically.
- 13) Equation: |-8 - m = 13
- Solve inequalities and graph solutions on number line:
- 14) Inequality: 6 - 6n > 18
- 15) Inequality: |5n + 5| ≤ 45
6. Factoring and Quadratic Solutions
- Solve by factoring:
- 16) n² + 7n + 10 = 0
- Factoring gives (n + 5)(n + 2) = 0; Solutions: n = -5, n = -2
- 17) p² + 2p - 24 = 0
- Factoring gives (p - 4)(p + 6) = 0; Solutions: p = 4, p = -6
- 18) 2x² + 7x + 6 = 0
- Factoring gives (2x + 3)(x + 2) = 0; Solutions: x = -3/2, x = -2
- Use the quadratic formula:
- 20) n² - 2n - 11 = 0
- Using the quadratic formula, find solutions.
- 22) 3n² - 8n + 7 = 0
- 19) 2n² - 7n - 15 = 0
8. Determining the Discriminant
- Find the discriminant:
- 24) 4x² + 7x + 5 = 0
- Discriminant D = b² - 4ac = (7)² - 4(4)(5) = 49 - 80 = -31 → No real roots
- 25) -2x² + 8x - 8 = 0
- D = 8² - 4(-2)(-8) = 64 - 64 = 0 → One real root
9. Equations by Taking Square Roots
- Solve each equation:
- 28) 3x² - 4 = -15
- Rearranged form gives exact roots of function, express final variable terms.
- 29) 6k² + 8 = -19
10. Circle Equations
- Standard form equations of circles:
- 38) x² + y² + 28x - 6y + 201 = 0
- Rearranged to standard form becomes (x + 14)² + (y - 3)² = r².
- Center: (-14, 3)
- Radius: r
- 39) x² + y² + 28x + 32y + 443 = 0
- Use completing the square to derive center and radius.