Adding and Subtracting Rational Expressions
Adding and Subtracting Rational Expressions
Objectives
- Adding and subtracting rational expressions with like denominators.
- Adding and subtracting rational expressions with unlike denominators.
- Always write the fraction in the simplest form.
Adding and Subtracting with Like Denominators
- If the denominators of fractions are the same, add or subtract the numerators.
Example with Rational Numbers
- Adding fractions
- 51+57=51+7=58
- 51 is a proper fraction (numerator < denominator).
- 57 is an improper fraction (numerator > denominator).
- Subtracting fractions
- 51−57=51−7=5−6
- Integers: negative counting numbers, zero, and positive counting numbers.
Example with Algebraic Expressions
- Example 1:
- 4x+45−x
- Denominators are the same.
- Add the numerators: 4x+5−x
- Simplify: 45
- Domain: All real numbers because the denominator (4) is different than zero, and there is no x in the denominator.
- Interval notation: (−∞,∞)
- Example 2:
- x2−2x−3x−x2−2x−33
- Factor the denominator: x2−2x−3=(x−3)(x+1)
- Possible combinations for -3: -3 and 1, since −3+1=−2
- Rewrite the expression:
- (x−3)(x+1)x−(x−3)(x+1)3
- Subtract the numerators: (x−3)(x+1)x−3
- Simplify: x+11
- Domain: Use the original factored form of the denominator, (x−3)(x+1)=0
- x=3 and x=−1
- Interval notation: (−∞,−1)∪(−1,3)∪(3,∞)
Least Common Multiple (LCM)
Finding the LCM of Algebraic Expressions
- Monomials: Find the LCM of the coefficients and the highest power of the variable.
- Example: Find the LCM of 6x,2x2,9x3
- Variable: x3
- Coefficients: 6, 2, and 9.
- Multiples of 6: 6, 12, 18, 24, …
- Multiples of 2: 2, 4, 6, 8, 10, 12, 14, 16, 18, …
- Multiples of 9: 9, 18, 27, …
- LCM of coefficients: 18
- LCM of the algebraic expressions: 18x3
- Binomials: Factorize the expressions first.
- Example: Find the LCM of x2−x and 2x−2
- Factorization:
- x2−x=x(x−1)
- 2x−2=2(x−1)
- Factors: 2, x, and x - 1.
- LCM: 2∗x∗(x−1)=2x(x−1)
- Trinomials: Factorize the expressions first.
- Example: Find the LCM of 3x2+6x and x2+4x+4
- Factorization:
- 3x2+6x=3x(x+2)
- x2+4x+4=(x+2)(x+2)=(x+2)2
- Factors: 3x and x + 2.
- LCM: 3x(x+2)2
Adding and Subtracting with Unlike Denominators
- Find the least common multiple (LCM) of the denominators.
- Convert each fraction to an equivalent fraction with the LCM as the denominator.
- Add or subtract the numerators.
- Simplify the result.
Example 1
- 6x7+8x5
- LCM of 6x and 8x:
- LCM of 6 and 8: 24
- LCM of x and x: x
- LCM: 24x
- Convert fractions:
- 6x7∗44=24x28
- 8x5∗33=24x15
- Add the fractions: 24x28+24x15=24x28+15=24x43
Example 2
- x+12x−x+2x
- x cannot be -1 and -2 (given).
- LCM of x + 1 and x + 2: (x + 1)(x + 2)
- Convert fractions:
- x+12x∗x+2x+2=(x+1)(x+2)2x(x+2)=(x+1)(x+2)2x2+4x
- x+2x∗x+1x+1=(x+1)(x+2)x(x+1)=(x+1)(x+2)x2+x
- Subtract the fractions:
- (x+1)(x+2)2x2+4x−(x+1)(x+2)x2+x=(x+1)(x+2)2x2+4x−(x2+x)=(x+1)(x+2)2x2+4x−x2−x=(x+1)(x+2)x2+3x
- Domain: x cannot be -1 or -2.
Example 3
- x2−13+x2+2x+1x
- Factorize denominators:
- x2−1=(x+1)(x−1)
- x2+2x+1=(x+1)2
- LCM: (x+1)2(x−1)
- Convert fractions:
- (x+1)(x−1)3∗x+1x+1=(x+1)2(x−1)3(x+1)
- (x+1)2x∗x−1x−1=(x+1)2(x−1)x(x−1)
- Add the fractions:
- (x+1)2(x−1)3(x+1)+(x+1)2(x−1)x(x−1)=(x+1)2(x−1)3x+3+x2−x=(x+1)2(x−1)x2+2x+3
- Domain: x cannot be -1 or 1.
Example 4
- x2−x1−4x2−4x3x
- Simplify 4x2−4x=4x(x−1)
- LCM between x2−x=x(x−1) and 4x(x−1) is 4x(x−1)2
- x must be different than 0 and 1.
- Simplify the expression to find the original form: 4x(x−1)2x2+4x−8
Complex Fractions
- A fraction over another fraction.
- Represents the division of fractions.
- Example: 2xx2−421+x1
Simplifying Complex Fractions
- Simplify the numerator and denominator separately.
- Rewrite the complex fraction as a division problem.
- Multiply by the reciprocal of the denominator.
- Simplify the result.
Example
- 2xx2−421+x1
- Simplify the numerator:
- 21+x1=2xx+2x2=2xx+2
- Rewrite the complex fraction as a division problem:
- 2xx+2÷2xx2−4
- Multiply by the reciprocal of the denominator:
- 2xx+2∗x2−42x=2xx+2∗(x+2)(x−2)2x
- Simplify the result:
- 2xx+2∗(x+2)(x−2)2x=x−21
- Restrictions: x cannot be 0, -2, or 2.