Solving Linear Equations Step-by-Step

Example 1: Algebraic Solution of the Linear Equation
  • Initial Equation: 2x+5=12x(2+4)2x + 5 = \frac{1}{2}x(2 + 4)

  • Step 1: Isolate the Variable Term on the Left Side

    • Subtract 55 from both sides of the equation: 2x+5−5=12x(2+4)−52x + 5 - 5 = \frac{1}{2}x(2 + 4) - 5

    • Result after subtraction: 2x=12x(2+4)−52x = \frac{1}{2}x(2 + 4) - 5

  • Step 2: Simplify Terms Inside the Parentheses

    • Evaluate the arithmetic addition inside the parentheses: 2+4=62 + 4 = 6

    • Substitute 66 back into the expression: 2x=12x(6)−52x = \frac{1}{2}x(6) - 5

  • Step 3: Simplify the Coefficient Product

    • Multiply the fraction 12\frac{1}{2} by the constant factor 66: 12x(6)=62x=3x\frac{1}{2}x(6) = \frac{6}{2}x = 3x

    • Substitute 3x3x back into the equation: 2x=3x−52x = 3x - 5

  • Step 4: Apply the Symmetric Property of Equality

    • Rearrange the equation by swapping the left and right sides: 3x−5=2x3x - 5 = 2x

  • Step 5: Isolate Constant Terms

    • Add 55 to both sides of the equation: 3x=2x+53x = 2x + 5

  • Step 6: Combine Like Variable Terms

    • Subtract 2x2x from both sides of the equation: 3x−2x=2x+5−2x3x - 2x = 2x + 5 - 2x

  • Step 7: Final Computation

    • Subtract coefficients on the left-hand side: 3x−2x=1x=x3x - 2x = 1x = x

    • Obtain the final value for xx: x=5x = 5

Example 2: Linear Equation with Fractional Coefficient and Constant Terms
  • Initial Equation: 4x−3=13x(1+8)+24x - 3 = \frac{1}{3}x(1 + 8) + 2

  • Step 1: Simplify Terms Inside Parentheses

    • Evaluate addition inside parentheses: 1+8=91 + 8 = 9

    • Substitute 99 back into the expression: 4x−3=13x(9)+24x - 3 = \frac{1}{3}x(9) + 2

  • Step 2: Simplify Coefficient Product

    • Multiply fraction by factor: 13x(9)=3x\frac{1}{3}x(9) = 3x

    • Substitute 3x3x back into equation: 4x−3=3x+24x - 3 = 3x + 2

  • Step 3: Combine Like Variable Terms

    • Subtract 3x3x from both sides: 4x−3x−3=3x−3x+24x - 3x - 3 = 3x - 3x + 2

    • Result after subtraction: x−3=2x - 3 = 2

  • Step 4: Isolate the Variable

    • Add 33 to both sides: x−3+3=2+3x - 3 + 3 = 2 + 3

    • Obtain final value: x=5x = 5

Example 3: Linear Equation with Rearrangement
  • Initial Equation: 25x(3+2)+7=3x−2\frac{2}{5}x(3 + 2) + 7 = 3x - 2

  • Step 1: Simplify Terms Inside Parentheses

    • Evaluate parentheses: 3+2=53 + 2 = 5

    • Equation becomes: 25x(5)+7=3x−2\frac{2}{5}x(5) + 7 = 3x - 2

  • Step 2: Simplify Coefficient Product

    • Multiply coefficient and factor: 25×5x=2x\frac{2}{5} \times 5x = 2x

    • Equation simplifies to: 2x+7=3x−22x + 7 = 3x - 2

  • Step 3: Apply Symmetric Property of Equality

    • Rearrange sides: 3x−2=2x+73x - 2 = 2x + 7

  • Step 4: Isolate Constant Terms

    • Add 22 to both sides: 3x=2x+93x = 2x + 9

  • Step 5: Combine Like Variable Terms

    • Subtract 2x2x from both sides: 3x−2x=2x−2x+93x - 2x = 2x - 2x + 9

    • Final result: x=9x = 9

Core Mathematical Principles
  • Addition and Subtraction Properties of Equality:

    • Adding or subtracting the same quantity from both sides of an equation preserves equality: If A=B then A−C=B−C\text{If } A = B \text{ then } A - C = B - C

    • Used when isolating terms across the equal sign.

  • Order of Operations (PEMDAS):

    • Perform operations inside parentheses prior to multiplying external coefficients.

  • Multiplication of Rational Numbers and Variables:

    • Scaling a variable expression by a fraction: 12×6x=62x=3x\frac{1}{2} \times 6x = \frac{6}{2}x = 3x

  • Symmetric Property of Equality:

    • If A=BA = B, then B=AB = A. This allows equivalent swapping of left and right expressions.