Measurement of metabolism (indirect calorimetry); Energy expenditure calculations

Energy Expenditure Calculations

  • Focus on determining how much fat and carbohydrate are burned during various exercise scenarios.

  • Refer to Chapter 4, "Exercise Metabolism," specifically page 93 for text discussion.

Bomb Calorimeter Components

  • Components:

    • Thermometer

    • Lid

    • Stirrer

    • Water Sample (23.00 bath)

    • Temperature Reader

    • Stirring Motor

    • Fuse Wires

    • Wire

    • Ignition Box

    • Bomb Cell

Whole-room Calorimeter

  • Overview and function not provided, but indicates an additional method for measuring calorimetry.

Measuring Oxygen Uptake and Carbon Dioxide Production

  • Measuring VO2 and VCO2:

    • Measuring oxygen uptake (VO₂) and carbon dioxide production (VCO₂) is essential for calculating the Respiratory Quotient (RQ).

    • RQ and VO₂ can be used to calculate fuel utilization during exercise.

Indirect Calorimetry

  • Components of the system:

    • Expired air

    • Subject being tested

    • Volume analyzer

    • Mixing chamber

    • O₂ analyzer

    • CO₂ analyzer

    • Computer

Example Calculation Using VO2 and RQ Table

Example 1: Carbohydrate Burn Rate Calculation

  • Scenario: How long would it take to burn 200 grams of carbohydrate while exercising at a VO2 of 2.0 liters/min and an RQ of 0.86?

    • Assumptions: 4 kcal/gram for carbohydrate.

    • At RQ = 0.86, 2.64 kcal/L O₂ from carbohydrate is utilized.

    • VO₂ of 2.0 liters/min results in:

    • Energy burned = (2.0extliters/minimes2.64extkcal/literO2)=5.28extkcal/min(2.0 ext{ liters/min} imes 2.64 ext{ kcal/liter O₂}) = 5.28 ext{ kcal/min}.

    • 200 grams of carbohydrate equals:

    • Energy = (200extgimes4extkcal/g)=800extkcals(200 ext{ g} imes 4 ext{ kcal/g}) = 800 ext{ kcals}.

    • Time to burn 800 kcals:

    • (800extkcalsextdividedby5.28extkcal/min)<br>ightarrow151.5extmin<br>ightarrow2exthours,32extmin(800 ext{ kcals} ext{ divided by } 5.28 ext{ kcal/min}) <br>ightarrow 151.5 ext{ min} <br>ightarrow 2 ext{ hours, } 32 ext{ min}.

RQ Table for Carbohydrate and Fat Oxidation

  • RQ Values:

    • Sequence of RQ values from 1.00 down to 0.70, displaying the corresponding VCO₂/VO₂, kcal/liter O₂ for both carbohydrate and fat, and the percentage of total kcal from each fuel source.

    • Example Row:

    • At RQ = 0.90:

      • (extVCO2/VO2=4.92)( ext{VCO₂/VO₂} = 4.92)

      • (extkcal/literO2fromcarbohydrate=3.32,extkcal/literO2fromfat=1.60)( ext{kcal/liter O₂ from carbohydrate} = 3.32, ext{kcal/liter O₂ from fat} = 1.60)

      • % of total kcal from carbohydrate = 67.5%, from fat = 32.5%.

Solving Energy Expenditure Problems

  • Steps:

    1. Determine the focus of the question (e.g., total kcals, carbohydrate, fat).

    2. Utilize the appropriate kcal/Liter O₂ consumed column based on the question type:

    • Total kcals: kcal/Liter O₂

    • Carbohydrate: kcal/Liter O₂ from carbohydrate

    • Fat: kcal/Liter O₂ from fat

    • Mixed questions: use both columns accordingly.

Example 2: Energy Expenditure Calculation

  • Scenario: Calculate time to burn 400 grams of carbohydrate at VO2 of 2.5 L/min and RQ of 0.90.

    • For RQ = 0.90, (3.32extkcal/LO2)(3.32 ext{ kcal/L O₂}) for carbohydrate.

    • Energy burned per minute = (2.5extL/minimes3.32extkcal/LO2)=8.3extkcal/min(2.5 ext{ L/min} imes 3.32 ext{ kcal/L O₂}) = 8.3 ext{ kcal/min}.

    • Total energy in 400 grams = (400extgimes4extkcal/g)=1,600extkcals(400 ext{ g} imes 4 ext{ kcal/g}) = 1,600 ext{ kcals}.

    • Time = (1,600extkcalsextdividedby8.3extkcal/min)<br>ightarrow193extmin(1,600 ext{ kcals} ext{ divided by } 8.3 ext{ kcal/min}) <br>ightarrow 193 ext{ min}.

Example 3: Fat Loss during Marathon

  • Scenario: A woman runs 26.2 miles in 4 hours with an average VO₂ of 2.0 L/min and average RER (RQ) of 0.88.

    • For RQ = 0.88, (1.92extkcal/LO2)(1.92 ext{kcal/L O₂}) for fat.

    • Energy burned per minute from fat: (2.0extL/minimes1.92extkcal/LO2)=3.84extkcal/min(2.0 ext{ L/min} imes 1.92 ext{ kcal/L O₂}) = 3.84 ext{ kcal/min}.

    • Total fat burned in 240 min = (240extminimes3.84extkcal/min)=921.6extkcals(240 ext{ min} imes 3.84 ext{ kcal/min}) = 921.6 ext{ kcals}.

    • Total fat mass loss = (921.6extkcalsextdividedby9extkcal/g)=102.4extgrams(921.6 ext{ kcals} ext{ divided by } 9 ext{ kcal/g}) = 102.4 ext{ grams}.

    • Fat burned per mile = (102.4extgextdividedby26.2)<br>ightarrow3.9extgrams/mile(102.4 ext{ g} ext{ divided by } 26.2) <br>ightarrow 3.9 ext{ grams/mile}.

Example 4: Carbohydrate to Fat Ratio Calculation

  • Scenario: A woman exercises at low intensity for 1 hour at VO₂ of 1.6 L/min with RQ of 0.84.

    • RQ = 0.84: 2.29 kcal/L O₂ for carbohydrate, 2.56 kcal/L O₂ for fat.

    • Carbohydrate grams burned/L O₂ = (rac2.294)<br>ightarrow0.57extgrams( rac{2.29}{4}) <br>ightarrow 0.57 ext{ grams}.

    • Fat grams burned/L O₂ = (rac2.569)<br>ightarrow0.28extgrams( rac{2.56}{9}) <br>ightarrow 0.28 ext{ grams}.

    • Ratio of carbohydrate to fat burned = (rac0.570.28)<br>ightarrow2.04( rac{0.57}{0.28}) <br>ightarrow 2.04.

Total Energy Expenditure Calculation

  • Scenario: A woman exercises for 1 hour at VO₂ of 1.9 L/min with RQ of 0.87.

    • For RQ = 0.87, (4.89extkcal/LO2)(4.89 ext{kcal/L O₂}).

    • Energy burned in 1 hour = $(1.9 ext{ L/min} imes 4.89 ext{ kcal/L O₂} imes 60 ext{ min}) = 557 ext{ kcals}$.

    • She consumes a pastry with 500 kcals.

    • Determination: The woman expended more kcals (557) than the kcal in the pastry (500).

Oxygen Consumption for Fat Burning

  • Scenario: While exercising at a constant RQ of 0.80, calculate the liters of oxygen required to burn 20 grams of fat (9 kcal/gram).

    • Total kcal to burn 20 grams of fat = (20extgimes9extkcal/g)=180extkcals(20 ext{ g} imes 9 ext{ kcal/g}) = 180 ext{ kcals}.

    • For RQ = 0.80, (3.20extkcal/LO2)(3.20 ext{kcal/L O₂}) is needed for fat.

    • Total liters of O₂ required = (180extkcalsextdividedby3.20extkcal/LO2)<br>ightarrow56.3extliters(180 ext{ kcals} ext{ divided by } 3.20 ext{kcal/L O₂}) <br>ightarrow 56.3 ext{ liters}.