Module 1 ─ Orbit Dynamics I Study Notes

Introduction

  • Orbital mechanics extends celestial mechanics to artificial satellites.
  • Ideal (Keplerian) vs. real (perturbed) orbits:
    • Perturbations (non-spherical gravity, atmospheric drag, third-body effects, solar radiation pressure, etc.) can hinder or aid orbit control.
  • Historical context:
    • Johannes Kepler (1571–1630) supplied empirical laws.
    • Isaac Newton (1643–1727) provided physical derivations via differential equations and universal gravitation.

Developing the Model: Kepler & Newton

  • Johannes Kepler
    • Assistant to Tycho Brahe to obtain precise planetary data (esp. Mars).
    • Derived three planetary laws geometrically, no dynamics.
    • Hypothesized a central force toward the Sun.
    • Corrected tidal theory, yet ignored by contemporaries (Galileo, Descartes).
    • Waited ~60 years for Newtonian explanation.
  • Isaac Newton
    • Invented differential calculus; modeled nature with equations.
    • Derived Kepler’s laws from F=Gm<em>1m</em>2/r2F=Gm<em>1m</em>2/r^2 and F=maF=ma.

Kepler’s Three Laws (Empirical)

  1. Law of Orbits
    • Planets travel in ellipses with the Sun at one focus.
    • Ellipse parameters:
      aa – semi-major axis
      bb – semi-minor axis
      ee – eccentricity.
  2. Law of Areas (Constant Areal Velocity)
    • Equal areas swept in equal times ⇒ A˙=const\dot A = \text{const} for a given body.
    • Quantitative form (derivable later): A˙=μ(1e2)2h=const\dot A = \frac{\mu(1-e^2)}{2h} = \text{const}.
  3. Law of Periods
    • T2/a3=4π2/μT^2/a^3 = 4\pi^2/\mu ((\mu\equiv G M_{central})).
    • Indicates sweep rate differs between orbits (larger (a) ⇒ longer (T)).

Newton’s Four Fundamental Laws (Applied to Orbital Motion)

  1. Inertia: constant velocity (or rest) unless external force acts.
  2. Force–Momentum: F=dpdt,  p=mv\mathbf F = \dfrac{d\mathbf p}{dt},\; \mathbf p=m\mathbf v; for constant (m): F=ma\mathbf F = m\mathbf a.
  3. Action–Reaction: F<em>12=F</em>21\mathbf F<em>{12} = -\mathbf F</em>{21}.
  4. Universal Gravitation: F=Gm<em>1m</em>2r2F = G\dfrac{m<em>1 m</em>2}{r^2}, with G=6.67×1011m3kg1s2G = 6.67\times10^{-11}\,\text{m}^3\,\text{kg}^{-1}\,\text{s}^{-2}.

Work & Energy in Gravitational Fields

  • Differential work: dW=FdrdW = \mathbf F\cdot d\mathbf r (only component along motion contributes).
  • Total work over path (c): W<em>12=</em>r<em>1r</em>2!FdrW<em>{12}=\int</em>{r<em>1}^{r</em>2}!\mathbf F\cdot d\mathbf r.
  • Work–Kinetic-Energy theorem:
    W<em>12=12mv</em>2212mv12=ΔKE.W<em>{12}=\tfrac12 m v</em>2^2 - \tfrac12 m v_1^2 = \Delta KE.
  • Conservative field ⇒ potential energy (U): F=U\mathbf F = -\nabla U.
    • Gravitational potential between two masses (zero at (\infty)):
      U(r)=Gm<em>1m</em>2r.U(r) = -\dfrac{G m<em>1 m</em>2}{r}.
  • Conservation of mechanical energy: ΔKE+ΔPE=0\Delta KE + \Delta PE = 0KE+PE=constant.KE+PE = \text{constant}.

Two-Body Problem (Idealized)

  • Only two masses interact by inverse-square gravity; third-body forces neglected.
  • Equations in vector form for masses 1 & 2:
    F<em>1=Gm</em>1m<em>2r3r,F</em>2=+Gm<em>1m</em>2r3r.\mathbf F<em>1 = -G\dfrac{m</em>1 m<em>2}{r^3}\mathbf r,\quad \mathbf F</em>2 = +G\dfrac{m<em>1 m</em>2}{r^3}\mathbf r.

Angular (Moment of) Momentum

  • For a particle of mass (m) in orbit:
    h=r×mv\mathbf h = \mathbf r\times m\mathbf v.
  • Magnitude (scalar) for planar motion:
    h=mrv<em>t=mr2θ˙,h = m r v<em>t = m r^2 \dot\theta, where (vt) is transverse component.
  • In a central force field, h\mathbf h is conserved (direction & magnitude).

General Orbit Equation (Conic Section)

  • From Newtonian dynamics:
    r=h2/μ1+ecos(θθ<em>0)r = \frac{h^2/\mu}{1+e\cos(\theta-\theta<em>0)} or equivalently r=p1+ecosν,r = \frac{p}{1+e\cos\nu}, with semilatus rectum p=h2/μp = h^2/\mu and true anomaly (\nu\equiv\theta-\theta0).
  • The parameter ee determines conic type:
    • e=0e=0 ⇒ circle.
    • 0<e<1 ⇒ ellipse.
    • e=1e=1 ⇒ parabola.
    • e>1 ⇒ hyperbola.

Analysis of Specific Keplerian Orbits

Circular Orbit (e = 0)

  • Radius constant r=a=p=h2/μr=a=p=h^2/\mu.
  • Orbital speed: vc=μ/r.v_c = \sqrt{\mu/r}.
  • Period: Tc=2πr3/μ.T_c = 2\pi\sqrt{r^{3}/\mu}.

Elliptical Orbit (0 < e < 1)

  • Periapsis (closest): (\nu=0^\circ) ⇒
    rp=p1+e=a(1e).r_p = \dfrac{p}{1+e} = a(1-e).
  • Apoapsis (farthest): (\nu=180^\circ) ⇒
    ra=p1e=a(1+e).r_a = \dfrac{p}{1-e} = a(1+e).
  • Velocity at an arbitrary (r):
    v2=μ(2r1a).v^2 = \mu\left(\dfrac{2}{r}-\dfrac{1}{a}\right).
  • Period from Kepler III: T=2πa3/μ.T = 2\pi\sqrt{a^{3}/\mu}.

Parabolic Orbit (e = 1)

  • Specific energy = 0.
  • Radius relation: r=p1+cosν=h2/μ1+cosν.r=\dfrac{p}{1+\cos\nu} = \dfrac{h^2/\mu}{1+\cos\nu}.
  • Periapsis distance: rp=p/2.r_p = p/2.

Hyperbolic Orbit (e > 1)

  • Open trajectory; excess specific energy (>0).
  • Approach asymptote defined by eccentricity and semi-major axis (a < 0).

Activity 1 (Practice Problems)

  1. Circular Earth orbit with speed v=7km/sv=7\,\text{km/s}.
    • Use v<em>c=μ</em>E/(RE+h)v<em>c=\sqrt{\mu</em>E/(R_E+h)}.
    • Solve for altitude (h). ((\muE = 3.986\times10^{14}\,\text{m}^3\,\text{s}^{-2}); (RE=6378\,\text{km})).
  2. Mars elliptical orbit, major axis 2a=40,000kma=20,000km2a=40,000\,\text{km}\Rightarrow a=20,000\,\text{km}.
    • Period: T=2πa3/μ<em>MarsT=2\pi\sqrt{a^{3}/\mu<em>{Mars}}, with μ</em>Mars=4.282×1013m3s2\mu</em>{Mars}=4.282\times10^{13}\,\text{m}^3\,\text{s}^{-2}.
  3. Derive velocities:
    • Start from general equation r=h2/μ1+ecosνr=\dfrac{h^2/\mu}{1+e\cos\nu} along with energy v2=μ(2r1a).v^2=\mu\left(\dfrac{2}{r}-\dfrac{1}{a}\right). Specialize to:
      • Circle: set e=0,  a=re=0,\;a=rvc=μ/rv_c=\sqrt{\mu/r}.
      • Ellipse: retain ee, use vis-viva result above.

Reference Constants

  • G=6.6743×1011m3kg1s2G = 6.6743\times10^{-11}\,\text{m}^3\,\text{kg}^{-1}\,\text{s}^{-2}.
  • Earth radius: RE=6378kmR_E = 6378\,\text{km}.
  • Earth mass: ME=5.9722×1024kgM_E = 5.9722\times10^{24}\,\text{kg}.
  • Sun mass: M=1.9891×1030kgM_\odot = 1.9891\times10^{30}\,\text{kg}.
  • Mars mass: MMars=6.41693×1023kgM_{Mars}=6.41693\times10^{23}\,\text{kg}.
  • Standard gravitational parameters:
    μ<em>E=GM</em>E,  μ<em>Mars=GM</em>Mars.\mu<em>E = G M</em>E, \; \mu<em>{Mars}=G M</em>{Mars}.

Next Topic

  • Detailed derivation of the general equation of motion for a body in a Keplerian orbit (start from Newton’s second law in polar coordinates, apply conservation of angular momentum, integrate).