(455) HL Length contraction [IB Physics HL]
Length Contraction
Length contraction: occurs in fast-moving objects; they appear shorter relative to an observer at rest.
Example: When moving in a spaceship, you won't notice your ship's contraction, but observers on Earth will.
Proper Length: The length of an object as measured when at rest, denoted as ( L_0 ).
Observed Length: The length measured by someone for whom the object is not at rest, denoted as ( L ).
Length contraction formula: ( L = \frac{L_0}{\gamma} ) where ( \gamma = \frac{1}{\sqrt{1 - \frac{v^2}{c^2}}} )
Example Calculation
While traveling at ( 0.8c ):
Proper Length of spaceship: ( L_0 = 18 \text{ m} )
Calculate ( \gamma ):
( \gamma = \frac{1}{\sqrt{1 - (0.8)^2}} = \frac{1}{\sqrt{0.36}} = \frac{1}{0.6} \approx 1.67 )
Observed Length: ( L = \frac{18 m}{1.67} \approx 10.8 m )
To Earth observers, the spaceship appears contracted to ( 10.8 m ).
Magical Barn Example
A spaceship is ( 2 m ) long and a magical barn is ( 1.6 m ).
Question: What speed is needed for the spaceship to fit in the barn with both doors closed?
Use length contraction formula:
( L = \frac{L_0}{\gamma} ) where ( L = 1.6 m ) (for barn), ( L_0 = 2 m ) (for spaceship).
Solve for ( \gamma ):
( 1.6 = \frac{2}{\gamma} ) gives ( \gamma = \frac{2}{1.6} = 1.25 )
Set ( \gamma = \frac{1}{\sqrt{1 - \frac{v^2}{c^2}}} ):
Squaring and rearranging yields ( \frac{v^2}{c^2} = 1 - (\frac{1}{1.25})^2).
Find ( V ):
Result: ( V \approx 0.6c )
Conclusion: At ( 0.6c ), the ( 2 m ) spaceship will appear ( 1.6 m ) and can fit in the barn.