IB Applications & Interpretations Topic 3 - Functions (SL and HL)
Equations of a straight line: y=mx c; ax+by+d=0; y-y1=m(x -x1)
Gradient formula: m=y2-y1×2-x1
Axis of symmetry of the graph of a quadratic function: f(x)=ax2+bx+c
Axis of symmetry is x= -b/(2a)
Logistic Function: f(x)=L/(1+Ce-kx), where L, k, and C>0
Refers to straight lines and can be expressed in various forms:
slope-intercept form
point-slope form
standard form.
y = mx + c, where m is the gradient (slope) of the line and c is the y-intercept.
Useful for its simplicity; allows easy identification of slope and y-intercept.
Example:y=(2/3)x+2
y - y₁=m(x -x₁), where (x₁, y₁) is a point on the line and m is the slope.
useful when the y-intercept is not given, requiring a specific point on the line.
example: y-4=23(x-3)
Ax + By = C, where A, B, and C are constants, and A and B are not both zero.
all terms must be on one side of the equation and integer coefficients.
example: -2x+3y-6=0
Often, questions in IB exams may ask for the final answer in standard form, necessitating rearrangement from other forms.
The process for converting from point-slope or slope-intercept to standard form involves expansion, grouping like terms, and sometimes multiplication to eliminate fractions.
Both slope-intercept and standard forms represent the same equation, just arranged differently.
Depending on the question's requirements, either form may be suitable for the final answer.
Represents the steepness of the line.
Analogous to the slope of a hill; steepness determines the rate of change.
Gradient (m) = rise/run m=y2-y1x2-x1
Δy represents the change in y and Δx represents the change in x between two points on the line.
X-intercept: Where the line intersects the horizontal axis (x-axis).
Y-intercept: Where the line intersects the vertical axis (y-axis).
A straight line will have only one x-intercept and one y-intercept.
Positive gradient: Line slopes upwards from left to right. Negative gradient: The line slopes downwards from left to right.
Lines that are always equidistant and never intersect, resembling train tracks.
The gradients of parallel lines are equal to each other.
Example: If Line 1 has a gradient of 2, then Line 2, parallel to Line 1, also has a gradient of 2.
Lines that intersect at a right angle (90 degrees), forming a "T" shape.
The gradients of perpendicular lines are negative reciprocals of each other.
Negative reciprocal means taking the negative of the reciprocal of the gradient of one line.
Example: If Line 1 has a gradient of 2, then Line 2, perpendicular to Line 1, has a gradient of -1/2.
Application primarily appears in Voronoi diagrams.
Definition: A line segment that cuts another line segment into two equal parts at a right angle.
The midpoint of the line segment defines the point through which the perpendicular bisector passes.
Given a line segment AB, find the equation of the perpendicular bisector.
Step 1: Find the midpoint of AB using the midpoint formula.
Step 2: Determine the gradient of AB using the gradient formula.
Step 3: Apply the concept of perpendicular lines to find the gradient of the perpendicular bisector.
Step 4: Use the point-slope form of a linear equation to find the equation of the perpendicular bisector.
Example Solution:
Given line segment AB with A(-1,1) and B(3,3).
Step 1: Midpoint = (1,2)
Step 2: Gradient of AB = ½
Step 3: Gradient of perpendicular bisector = -1 / (1/2) = -2
Step 4: Equation of perpendicular bisector = y = -2x + 4
A function is described as a mathematical rule denoted by f(x)=something
It represents the relationship between two variables, where:
x is the input (independent variable) and
y is the output (dependent variable).
Example:
Throwing a rock down a ditch
Time (input) influences height (output).
Modelled with a linear function:
H(t)=10a+50
Linear Functions: Have a constant rate of change, forming straight lines.
Quadratic Functions: Involve squares of the variable, often representing parabolic curves.
Exponential Functions: Involve a constant raised to a variable power, used for growth or decay processes.
Logarithmic Functions: The inverse of exponential functions, used to model decreasing growth rates.
Sinusoidal Functions: Represent periodic oscillations, such as waves or tides.
Logistic Functions: Combine exponential and logarithmic functions, useful for modelling growth that levels off.
Piecewise Functions: Combinations of different functions defined over specific intervals, useful for modeling complex scenarios with changing behaviors.
Functions can be represented in various ways, such as:
(x)=x2−2, f:x↦x2−2 f:x↦x2−2, or y=x2−2y=x2−2.
All these representations convey the same meaning, depending on the context or textbook used.
Domain refers to the set of possible input values (X), while range refers to the set of possible output values (Y).
For example, for f(x)=x2−2
Domain: x∈R, where x∈R means all real numbers
Range: y ≥-2 (all real numbers greater than or equal to -2).
Composite functions, denoted as
f∘g, or g∘f, involve applying one function within another function.
For example, if f(x)=x2−2 and g(x)=x+3
f∘g: Replace x in f(x) with g(x), i.e., (x+3)2−2
g∘f Replace x in g(x) with f(x), i.e., (x2−2)+3
The inverse function, denoted as f-1, reverses the action of the original function.
To find the inverse of a function:
Rewrite the function in the form y=f(x)
Swap x and y and solve for y.
The resulting equation is the inverse function.
For example, if f(x)=x2−2
Rewrite as y=x2−2
Swap x and y to get x=y2−2
Solve for y to get f-1(x)=x+2
Composite functions and inverse functions have deeper meanings and are essential in understanding the behavior and relationships between functions.
Inverse functions represent reflections across the line y=x, while composite functions involve applying one function's output as another function's input.
Functions are often represented as f(x), where x is the input variable and f(x) is the output.
Knowing a coordinate on the function, such as (2,2), helps understand its behavior.
Translations involve shifting the function horizontally or vertically.
Horizontal shift: f(x±a)
f(x±a) shifts a units left or right.
Vertical shift: f(x)±a
f(x)±a shifts a units up or down.
Remember that signs inside and outside the function bracket indicate horizontal and vertical shifts, respectively.
Stretches involve making the function skinnier or wider.
Vertical stretch: a⋅f(x)
a⋅f(x) multiplies all y values by a.
Horizontal stretch: f(ax)
f(ax) stretches the function horizontally by a factor of 1a
Horizontal stretch by 1a means compressing if a>1 or stretching if 0<a<1.
Reflections involve flipping the function over the x-axis or y-axis.
Reflection in the x-axis: −f(x)
−f(x) reflects all y values vertically.
Reflection in the y-axis: f(−x)
f(−x) reflects all
x values horizontally.
Horizontal shifts affect x values inside the function.
Vertical shifts affect y values outside the function.
Stretches scale the function vertically or horizontally.
Reflections flip the function over the x-axis or y-axis.
Example: Height of a cannonball over time.
Enter function:
−2x2+20x+8
Adjust zoom settings for accurate visualization. (I suggest [ZOOM] -> 0)
Analysis Tools:
Maximum Height:
Use "Maximum" tool.
After 5 seconds, cannonball reaches 58 meters.
Time to Reach Ground:
Utilize "Zero" tool by pressing [2ND] + [TRACE] + 2
“Left bound?” -> Move “blinky” to left side of line from where it touches at zero
“Right bound?” -> move “blinky” to right side from where it touches at zero
“Guess?” -> place “blinky” on top of where it touches zero
Result: 10.38 (round up by three sig-figs) -> 10.4
Interpretation: Cannonball touches ground at 10.4 seconds
Initial Height:
Plug in 0 for function; in most cases, getting an initial height can be found by isolating the constant alone.
In context: initial height is 8 meters.
Time to Reach Specific Height:
Plot horizontal line (e.g., at 40 meters).
Use "Intersection" tool.
Cannonball reaches 40 meters in 2 seconds.
Numeric Solver (N Solve) is a valuable function on TI-84 for solving equations quickly and accurately.
It's particularly essential for topics like exponential, logarithmic, quadratic, and cubic functions.
Access the function by navigating to [MATH] > [C:Numeric Solver]
Input the equation directly into the calculator, ensuring correct syntax and using 'X' as the variable.
Specify appropriate bounds to narrow down the search range for the solution.
Bounds should be close to the expected solution for faster convergence.
Press [GRAPH] button when ready to start “guessing”
Input any value for X (as long as it fits in context to problem)
Result will be displayed in the same area you input a value in
The calculator displays the approximate solution once the calculation is complete.
REMEMBER TO USE THREE SIG-FIGS
Numeric Solver provides the left-hand solution for equations with multiple solutions.
For equations with multiple solutions or complex functions, consider using other analysis tools like plotting functions and intersection analysis.
Equations of a straight line: y=mx c; ax+by+d=0; y-y1=m(x -x1)
Gradient formula: m=y2-y1×2-x1
Axis of symmetry of the graph of a quadratic function: f(x)=ax2+bx+c
Axis of symmetry is x= -b/(2a)
Logistic Function: f(x)=L/(1+Ce-kx), where L, k, and C>0
Refers to straight lines and can be expressed in various forms:
slope-intercept form
point-slope form
standard form.
y = mx + c, where m is the gradient (slope) of the line and c is the y-intercept.
Useful for its simplicity; allows easy identification of slope and y-intercept.
Example:y=(2/3)x+2
y - y₁=m(x -x₁), where (x₁, y₁) is a point on the line and m is the slope.
useful when the y-intercept is not given, requiring a specific point on the line.
example: y-4=23(x-3)
Ax + By = C, where A, B, and C are constants, and A and B are not both zero.
all terms must be on one side of the equation and integer coefficients.
example: -2x+3y-6=0
Often, questions in IB exams may ask for the final answer in standard form, necessitating rearrangement from other forms.
The process for converting from point-slope or slope-intercept to standard form involves expansion, grouping like terms, and sometimes multiplication to eliminate fractions.
Both slope-intercept and standard forms represent the same equation, just arranged differently.
Depending on the question's requirements, either form may be suitable for the final answer.
Represents the steepness of the line.
Analogous to the slope of a hill; steepness determines the rate of change.
Gradient (m) = rise/run m=y2-y1x2-x1
Δy represents the change in y and Δx represents the change in x between two points on the line.
X-intercept: Where the line intersects the horizontal axis (x-axis).
Y-intercept: Where the line intersects the vertical axis (y-axis).
A straight line will have only one x-intercept and one y-intercept.
Positive gradient: Line slopes upwards from left to right. Negative gradient: The line slopes downwards from left to right.
Lines that are always equidistant and never intersect, resembling train tracks.
The gradients of parallel lines are equal to each other.
Example: If Line 1 has a gradient of 2, then Line 2, parallel to Line 1, also has a gradient of 2.
Lines that intersect at a right angle (90 degrees), forming a "T" shape.
The gradients of perpendicular lines are negative reciprocals of each other.
Negative reciprocal means taking the negative of the reciprocal of the gradient of one line.
Example: If Line 1 has a gradient of 2, then Line 2, perpendicular to Line 1, has a gradient of -1/2.
Application primarily appears in Voronoi diagrams.
Definition: A line segment that cuts another line segment into two equal parts at a right angle.
The midpoint of the line segment defines the point through which the perpendicular bisector passes.
Given a line segment AB, find the equation of the perpendicular bisector.
Step 1: Find the midpoint of AB using the midpoint formula.
Step 2: Determine the gradient of AB using the gradient formula.
Step 3: Apply the concept of perpendicular lines to find the gradient of the perpendicular bisector.
Step 4: Use the point-slope form of a linear equation to find the equation of the perpendicular bisector.
Example Solution:
Given line segment AB with A(-1,1) and B(3,3).
Step 1: Midpoint = (1,2)
Step 2: Gradient of AB = ½
Step 3: Gradient of perpendicular bisector = -1 / (1/2) = -2
Step 4: Equation of perpendicular bisector = y = -2x + 4
A function is described as a mathematical rule denoted by f(x)=something
It represents the relationship between two variables, where:
x is the input (independent variable) and
y is the output (dependent variable).
Example:
Throwing a rock down a ditch
Time (input) influences height (output).
Modelled with a linear function:
H(t)=10a+50
Linear Functions: Have a constant rate of change, forming straight lines.
Quadratic Functions: Involve squares of the variable, often representing parabolic curves.
Exponential Functions: Involve a constant raised to a variable power, used for growth or decay processes.
Logarithmic Functions: The inverse of exponential functions, used to model decreasing growth rates.
Sinusoidal Functions: Represent periodic oscillations, such as waves or tides.
Logistic Functions: Combine exponential and logarithmic functions, useful for modelling growth that levels off.
Piecewise Functions: Combinations of different functions defined over specific intervals, useful for modeling complex scenarios with changing behaviors.
Functions can be represented in various ways, such as:
(x)=x2−2, f:x↦x2−2 f:x↦x2−2, or y=x2−2y=x2−2.
All these representations convey the same meaning, depending on the context or textbook used.
Domain refers to the set of possible input values (X), while range refers to the set of possible output values (Y).
For example, for f(x)=x2−2
Domain: x∈R, where x∈R means all real numbers
Range: y ≥-2 (all real numbers greater than or equal to -2).
Composite functions, denoted as
f∘g, or g∘f, involve applying one function within another function.
For example, if f(x)=x2−2 and g(x)=x+3
f∘g: Replace x in f(x) with g(x), i.e., (x+3)2−2
g∘f Replace x in g(x) with f(x), i.e., (x2−2)+3
The inverse function, denoted as f-1, reverses the action of the original function.
To find the inverse of a function:
Rewrite the function in the form y=f(x)
Swap x and y and solve for y.
The resulting equation is the inverse function.
For example, if f(x)=x2−2
Rewrite as y=x2−2
Swap x and y to get x=y2−2
Solve for y to get f-1(x)=x+2
Composite functions and inverse functions have deeper meanings and are essential in understanding the behavior and relationships between functions.
Inverse functions represent reflections across the line y=x, while composite functions involve applying one function's output as another function's input.
Functions are often represented as f(x), where x is the input variable and f(x) is the output.
Knowing a coordinate on the function, such as (2,2), helps understand its behavior.
Translations involve shifting the function horizontally or vertically.
Horizontal shift: f(x±a)
f(x±a) shifts a units left or right.
Vertical shift: f(x)±a
f(x)±a shifts a units up or down.
Remember that signs inside and outside the function bracket indicate horizontal and vertical shifts, respectively.
Stretches involve making the function skinnier or wider.
Vertical stretch: a⋅f(x)
a⋅f(x) multiplies all y values by a.
Horizontal stretch: f(ax)
f(ax) stretches the function horizontally by a factor of 1a
Horizontal stretch by 1a means compressing if a>1 or stretching if 0<a<1.
Reflections involve flipping the function over the x-axis or y-axis.
Reflection in the x-axis: −f(x)
−f(x) reflects all y values vertically.
Reflection in the y-axis: f(−x)
f(−x) reflects all
x values horizontally.
Horizontal shifts affect x values inside the function.
Vertical shifts affect y values outside the function.
Stretches scale the function vertically or horizontally.
Reflections flip the function over the x-axis or y-axis.
Example: Height of a cannonball over time.
Enter function:
−2x2+20x+8
Adjust zoom settings for accurate visualization. (I suggest [ZOOM] -> 0)
Analysis Tools:
Maximum Height:
Use "Maximum" tool.
After 5 seconds, cannonball reaches 58 meters.
Time to Reach Ground:
Utilize "Zero" tool by pressing [2ND] + [TRACE] + 2
“Left bound?” -> Move “blinky” to left side of line from where it touches at zero
“Right bound?” -> move “blinky” to right side from where it touches at zero
“Guess?” -> place “blinky” on top of where it touches zero
Result: 10.38 (round up by three sig-figs) -> 10.4
Interpretation: Cannonball touches ground at 10.4 seconds
Initial Height:
Plug in 0 for function; in most cases, getting an initial height can be found by isolating the constant alone.
In context: initial height is 8 meters.
Time to Reach Specific Height:
Plot horizontal line (e.g., at 40 meters).
Use "Intersection" tool.
Cannonball reaches 40 meters in 2 seconds.
Numeric Solver (N Solve) is a valuable function on TI-84 for solving equations quickly and accurately.
It's particularly essential for topics like exponential, logarithmic, quadratic, and cubic functions.
Access the function by navigating to [MATH] > [C:Numeric Solver]
Input the equation directly into the calculator, ensuring correct syntax and using 'X' as the variable.
Specify appropriate bounds to narrow down the search range for the solution.
Bounds should be close to the expected solution for faster convergence.
Press [GRAPH] button when ready to start “guessing”
Input any value for X (as long as it fits in context to problem)
Result will be displayed in the same area you input a value in
The calculator displays the approximate solution once the calculation is complete.
REMEMBER TO USE THREE SIG-FIGS
Numeric Solver provides the left-hand solution for equations with multiple solutions.
For equations with multiple solutions or complex functions, consider using other analysis tools like plotting functions and intersection analysis.