AB Unit 8: Applications of Integration

Applications of Integration

8.1 Finding the Average Value of a Function on an Interval

  • Concept Overview: The average value of a function over an interval [a, b] is calculated based on the area under the curve divided by the width of the interval.
    • If f(x) is a constant function, then it is represented as:
      f(x)=kf(x) = k
    • The area of the rectangle is given by: R=k(ba)R = k(b - a)
      • Therefore, the average value formula is:
        ext{Average Value} = rac{1}{b - a} ext{´} \int_{a}^{b} f(x) dx
Example 1: Average value of f(x) over [0, 3], where f(x) = x² + 2
  • To find the average value: ext{Average} = rac{1}{3 - 0} \int_{0}^{3} (x^2 + 2) \,dx
    • Solve the integral:
      = rac{1}{3} \left[ rac{x^3}{3} + 2x
      ight]_{0}^{3} (After evaluating at bounds this would yield the average value)
Example 2: Average value of f(x) over [π/2, π], where f(x) = 2cos(x)
  • Similar procedure will be applied with integrating from π/2 to π:
    • First set up the integral:
      ext{Average} = rac{1}{ rac{ au}{2} - rac{ au}{2}} \int_{ rac{ au}{2}}^{ au} 2 \cos(x) \, dx

Practice Problems

  • Problem 1: Find the average value of y=x2x3+1y = x^2 \sqrt{x^3 + 1} over the interval [0, 2].
  • Problem 2: A variable rate of water draining modeled by: r(t)={600t,amp;0t5 1000e0.21(t5),amp;tgt;5r(t) = \begin{cases} 600t, & 0 \leq t \leq 5 \ 1000e^{-0.21(t - 5)}, & t > 5 \end{cases}
    • Find the average drainage rate between t = 0 and t = 8 hours.

Connecting Position, Velocity, and Acceleration Functions

  • Definitions:
    • Position (s(t)): The location of a particle over time
    • Velocity (v(t)): The rate of change of position: v(t)=s(t)v(t) = s'(t)
    • Acceleration (a(t)): The rate of change of velocity: a(t)=v(t)a(t) = v'(t)
  • Displacement Calculation:
    If the acceleration is given by a(t)=4ta(t) = 4t, determine the final position with initial values.
Examples related to motion
  • Velocity and Position:
    • If v(t)v(t) is defined by integration of a(t)a(t) and initial conditions such as v(0)=2v(0) = -2, integrate to find the position at specific times.
    • Example: If the velocity model yields positions like:
    • Total Distance: abv(t)dt\int_{a}^{b} |v(t)| \,dt

Interpretation of Results

  • Average height of a function is represented as the area divided by the interval width, emphasizing the fundamental relationship in calculus linking area under a curve and average value.