Acid-Base Titration: Standardization and Estimation of Sodium Bicarbonate in Antacid

Preparation of Standard Oxalic Acid Solution and Standardization of NaOH

  • Objective and Overview:

    • Preparation of a 100 mL100\,\text{mL} standard solution of 0.1 M0.1\,\text{M} oxalic acid (H2C2O4\text{H}_2\text{C}_2\text{O}_4) as a primary standard.

    • Standardization of sodium hydroxide (NaOH\text{NaOH}) solution using the prepared oxalic acid solution.

  • Quantitative Weighing and Solution Preparation Procedure:

    • Turn on the analytical balance and wait until the digital display reads zero.

    • Place a piece of creased weighing paper on the balance pan and press the tare button to subtract the mass of the paper.

    • Slowly transfer oxalic acid salt onto the paper using a spatula until the target mass is reached.

    • Precaution: Do not add excess salt and attempt to return it to the original container, as this risks contaminating the bulk reagent and causing laboratory spills.

    • Quantitatively transfer the weighed oxalic acid salt into a 100 mL100\,\text{mL} volumetric flask ( standard measuring flask, SMF) using a funnel.

    • Wash down any residual salt adhering to the funnel and the inner neck of the volumetric flask using distilled water to guarantee complete transfer.

    • Dissolve the oxalic acid salt completely by swirling/shaking the flask.

    • Add distilled water up to the etched calibration mark on the neck of the flask.

    • Stopper the flask securely with a lid and invert it repeatedly to ensure complete concentration homogeneity throughout the solution.

    • Label the flask clearly with its determined concentration (e.g., "…. M Oxalic Acid").

  • Molarity and Mass Formulas:

    • Molarity (MM) equation:   M=W×1000M′×VmLM = \frac{W \times 1000}{M' \times V_{\text{mL}}}

    • Mass (WW) calculation formula:   W=M×M′×VmL1000W = \frac{M \times M' \times V_{\text{mL}}}{1000}

    • Variable Definitions:

    • MM = molarity of the solution (mol dm−3\text{mol\,dm}^{-3} or M\text{M})

    • M′M' = molar mass of the solute (g mol−1\text{g\,mol}^{-1})

    • WW = mass/weight of the solute (g\text{g})

    • VmLV_{\text{mL}} = volume of the solution in milliliters (mL\text{mL})

  • Standardization Setup and Procedure for NaOH:

    • Setup Configuration:

    • Burette: Filled with sodium hydroxide (NaOH\text{NaOH}) solution of unknown concentration (? M?\,\text{M}).

    • Pipette: Used to measure exactly 10 mL10\,\text{mL} of the prepared 0.1 M0.1\,\text{M} oxalic acid solution into a conical flask.

    • Indicator: Suitable acid-base indicator added to the conical flask.

    • Titration Method:

    • Titrate 10 mL10\,\text{mL} of oxalic acid solution against NaOH\text{NaOH} from the burette until the endpoint color change is attained.

  • Chemical Reaction:   2NaOH+H2C2O4→Na2C2O4+2H2O2\text{NaOH} + \text{H}_2\text{C}_2\text{O}_4 \rightarrow \text{Na}_2\text{C}_2\text{O}_4 + 2\text{H}_2\text{O}

  • Stoichiometry and Mole Relations (nn\text{-factor}):

    • Molarity definition: Molarity=Number of MolesVolume in Liters\text{Molarity} = \frac{\text{Number of Moles}}{\text{Volume in Liters}}

    • Moles of NaOH\text{NaOH}:   nNaOH=MNaOH×VNaOHn_{\text{NaOH}} = M_{\text{NaOH}} \times V_{\text{NaOH}}

    • Moles of Oxalic Acid (ox\text{ox}):   nox=Mox×Voxn_{\text{ox}} = M_{\text{ox}} \times V_{\text{ox}}

    • Stoichiometric mole ratio from balanced chemical equation:   nNaOHnox=21=MNaOH×VNaOHMox×Vox\frac{n_{\text{NaOH}}}{n_{\text{ox}}} = \frac{2}{1} = \frac{M_{\text{NaOH}} \times V_{\text{NaOH}}}{M_{\text{ox}} \times V_{\text{ox}}}

    • Rearranging to find NaOH\text{NaOH} molarity:   MNaOH=2×Mox×VoxVNaOHM_{\text{NaOH}} = \frac{2 \times M_{\text{ox}} \times V_{\text{ox}}}{V_{\text{NaOH}}}

Standardization of Hydrochloric Acid (HCl)

  • Objective and Overview:

    • Accurate determination of the concentration of a dilute hydrochloric acid (HCl\text{HCl}) solution using the standardized NaOH\text{NaOH} solution.

  • Experimental Setup and Materials:

    • Burette: 50 mL50\,\text{mL} burette filled with aqueous NaOH\text{NaOH} up to the 0 mL0\,\text{mL} mark using a filter funnel.

    • Pipette: 10 mL10\,\text{mL} graduated pipette, pre-rinsed with distilled water and subsequently rinsed with the provided HCl\text{HCl} solution.

    • Reaction Vessel: Clean conical flask containing 10 mL10\,\text{mL} of dilute HCl\text{HCl} measured via pipette bulb.

    • Indicator: 22 to 33 drops of phenolphthalein indicator added directly to the HCl\text{HCl} solution.

  • Titration Procedure:

    • Swirl the conical flask to thoroughly mix HCl\text{HCl} and phenolphthalein indicator.

    • Dispense NaOH\text{NaOH} dropwise from the burette while continuously swirling the flask.

    • Terminate the titration immediately upon the first appearance of a persistent pale pink color throughout the solution.

    • Record the final burette volume reading.

    • Repeat the titration procedure to obtain concordant burette readings.

    • Dispose of the post-titration solution safely in the designated base waste container.

  • Chemical Reaction and Equivalence Formula:

    • Neutralization Reaction:   HCl+NaOH→NaCl+H2O\text{HCl} + \text{NaOH} \rightarrow \text{NaCl} + \text{H}_2\text{O}

    • Equivalence relation (1:11:1 stoichiometric ratio):   MHCl×VHCl=MNaOH×VNaOHM_{\text{HCl}} \times V_{\text{HCl}} = M_{\text{NaOH}} \times V_{\text{NaOH}}

    • Calculation of HCl\text{HCl} concentration:   MHCl=MNaOH×VNaOHVHClM_{\text{HCl}} = \frac{M_{\text{NaOH}} \times V_{\text{NaOH}}}{V_{\text{HCl}}}

    • Note: The calculated value of MHClM_{\text{HCl}} is utilized as a fixed parameter in subsequent antacid analysis calculations.

Antacid Sample Analysis: Estimation of NaHCO3 via Back-Titration

Why Back-Titration Principle
  • Theoretical Principle of Back-Titration:

    • Rationale: Sodium bicarbonate (NaHCO3\text{NaHCO}_3) is a weak base that reacts slowly with titrants, making direct titration to a sharp endpoint difficult.

    • Strategy: A known, precise excess of standard strong acid (HCl\text{HCl}) is added to react completely with all NaHCO3\text{NaHCO}_3 in the sample.

    • Measurement: The leftover, unreacted excess HCl\text{HCl} is subsequently back-titrated using standard NaOH\text{NaOH} solution.

  • Chemical Reaction:   NaHCO3+HCl→NaCl+H2O+CO2↑\text{NaHCO}_3 + \text{HCl} \rightarrow \text{NaCl} + \text{H}_2\text{O} + \text{CO}_2\uparrow

  • Step-by-Step Laboratory Procedure:

    • Refill the 50 mL50\,\text{mL} burette with standard NaOH\text{NaOH} solution up to the 0 mL0\,\text{mL} mark using a funnel.

    • Pipette exactly 25 mL25\,\text{mL} of prepared 0.2 M HCl0.2\,\text{M}\,\text{HCl} solution into a 250 mL250\,\text{mL} conical flask.

    • Add 10 mL10\,\text{mL} of the unknown antacid solution containing NaHCO3\text{NaHCO}_3 into the flask containing the acid.

    • Stir the solution with a glass rod until the NaHCO3\text{NaHCO}_3 powder is completely dissolved.

    • Allow the mixture to rest for 10 minutes10\,\text{minutes} to ensure full reaction between NaHCO3\text{NaHCO}_3 and HCl\text{HCl}.

    • Add 22 drops of phenolphthalein indicator to the mixture.

    • Commence back-titration by delivering NaOH\text{NaOH} solution from the burette (adding 1 mL1\,\text{mL} at a time initially, then dropwise near the endpoint).

    • Swirl the conical flask vigorously throughout the titration.

    • Stop the titration immediately when the solution turns from colorless to a permanent pale pink color.

    • Record the final burette volume of NaOH\text{NaOH}.

    • Repeat the complete determination procedure to obtain consistent, reproducible values.

  • Mathematical Calculation Sequence:

Calculation Sequence Flowchart
  1. Volume of Unreacted HCl (xx\text{ in mL}):

    • Calculated from the Step III back-titration endpoint volume of NaOH\text{NaOH}:      x=VNaOH×MNaOHMHClx = \frac{V_{\text{NaOH}} \times M_{\text{NaOH}}}{M_{\text{HCl}}}

  2. Volume of Reacted HCl (yy\text{ in mL}):

    • Total volume of HCl\text{HCl} added minus leftover unreacted volume xx:      y=25−xy = 25 - x

  3. Equivalents / Moles of Antacid (zz\text{ in mol}):

    • Moles of antacid equal the moles of HCl\text{HCl} consumed during the primary reaction:      z=(y1000)×MHClz = \left(\frac{y}{1000}\right) \times M_{\text{HCl}}

  4. Mass of NaHCO3 in Sample (g\text{g}\text{):

    • Multiply the mole quantity zz by the molar mass of NaHCO3\text{NaHCO}_3 (84 g mol−184\,\text{g\,mol}^{-1}):      Mass of NaHCO3=z×84 g\text{Mass of } \text{NaHCO}_3 = z \times 84\,\text{g}