Addition Rule and Rule of Complements
Compound Events and the General Addition Rule
- A compound event combines two or more events.
- The event A or B occurs if A occurs, B occurs, or both occur.
- The general addition rule computes probabilities of events in the form A or B.
General Addition Rule
- For any two events A and B, the probability of A or B is:
P(A or B)=P(A)+P(B)−P(A and B)
Example
- 1,000 adults were asked about favoring a law for higher education support and their likelihood to vote.
- Classified as "likely to vote" or "not likely to vote."
Data:
- Likely to vote: 372
- Favor the law: 151
- Both likely to vote and favor the law: 20
- Only likely to vote: 262
- Only Favor the law: 87
Calculations:
- Probability of likely to vote:
- Total people likely to vote = 372 + 262 + 87 = 721
- P(likely to vote)=1000721=0.721
- Probability of favoring the law:
- Total people who favor the law = 372 + 151 = 523
- P(favors the law)=1000523=0.523
- Probability of both likely to vote and favoring the law:
- P(likely to vote and favors the law)=1000372=0.372
- Using the general addition rule:
- P(likely to vote or favors the law)=P(likely to vote)+P(favors the law)−P(likely to vote and favors the law)
- P(likely to vote or favors the law)=0.721+0.523−0.372=0.872
Mutually Exclusive Events
- Two events are mutually exclusive if it is impossible for both events to occur simultaneously.
Examples
- Rolling a die:
- Event A: Die comes up as 3.
- Event B: Die comes up as an even number.
- These are mutually exclusive because the die cannot be both 3 and an even number at the same time.
- Tossing a coin twice:
- Event A: One of the tosses is heads.
- Event B: One of the tosses is tails.
- These are NOT mutually exclusive because it's possible to get heads, tails or tails, heads.
- If events A and B are mutually exclusive, then P(A and B)=0
- Simplified general addition rule:
- P(A or B)=P(A)+P(B)
Example
- Olympics example with 10,735 athletes.
- 530 from the US
- 277 from Canada
- 102 from Mexico
- What is the probability that an athlete chosen at random represents the US or Canada?
Solution:
- Events are mutually exclusive (cannot compete for both US and Canada).
- P(US or Canada)=P(US)+P(Canada)
- P(US or Canada)=10735530+10735277=10735807≈0.07517
Complements
- The complement of an event A is the event that A does not occur, denoted as AC
- Example: If there is a 60% chance of rain, there is a 40% chance it will not rain.
Examples: Statistics Class
- 200 students enrolled.
- Event: Exactly 50 are business majors.
- Complement: The number of business majors is not 50.
- Event: More than 50 are business majors.
- Complement: 50 or fewer are business majors.
- Event: At least 50 of them are business majors.
- Complement: Fewer than 50 are business majors.
Rule of Complements
- P(AC)=1−P(A)
- Example: Wall Street Journal reports 40% of cars sold were small cars.
- Probability that a randomly chosen car is not a small car:
- P(not a small car)=1−P(small car)=1−0.4=0.6 or 60%.
Application Example: Foundry Manufacturing
- 500 cast aluminum parts manufactured.
- Some with major flaws.
- Some with minor flaws.
- Some with both.
Table Results:
- Major flaw only = 35
- Minor flaw only = 75
- Both major and minor flaws = 20
- No flaw = 370
Probability Calculations:
- A. Probability of a major flaw:
- Total with major flaw = 20 + 35 = 55
- P(major flaw)=50055=0.11
- B. Probability of a minor flaw:
- Total with minor flaw = 20 + 75 = 95
- P(minor flaw)=50095=0.19
- C. Probability of a major or minor flaw:
- Using the general addition rule:
- P(major flaw or minor flaw)=P(major flaw)+P(minor flaw)−P(major flaw and minor flaw)
- P(major flaw and minor flaw)=50020=0.04
- P(major flaw or minor flaw)=0.11+0.19−0.04=0.26
- D. Probability of no major flaw:
- Using the complement rule:
- P(no major flaw)=1−P(major flaw)=1−0.11=0.89