SBA 6th Grade Math Practice Test Exhaustive Study Notes

SBA Practice Test Chunk #1: Basic Coordinates and Rational Numbers

  • Calculator Usage Restriction: Please note that you will NOT have access to a calculator for questions 1 through 10.

  • Question 1: Grid Coordinates and Distance

    • Task: Determine the distance, in units, between point A and point C on the provided grid.
    • Coordinates: The grid shows Points arranged in a coordinate plane.
    • Result: The distance between Point A and Point C is 55 units.
  • Question 2: Points on a Number Line

    • Task: Consider points A, B, C, and D plotted on a horizontal number line ranging from 5-5 to 55.
    • Relative Positions: Moving to the right ("Right") on the number line means the value is "greater," while moving to the left ("Left") means the value is "less."
  • Question 3: Truth of Statements regarding Number Line Points

    • Statement 1: The value of Point A is less than 3-3. (Evaluation based on visual placement on number line).
    • Statement 2: The value of Point B is greater than the value of point A. (True, because Point B is to the right of Point A: 2>3-2 > -3 and 1>2-1 > -2).
    • Statement 3: The value of Point D is 4-4. (False, visual assessment indicates Point D is at +4+4).
  • Cookie Recipe Conversion Problem

    • Given: A recipe requires 1121 \frac{1}{2} cups of flour for every batch of cookies.
    • Scenario: You have 161216 \frac{1}{2} cups of flour.
    • Calculation: How many full batches of cookies can be made?
      • Method 1 (Division of Fractions): Calculate 1612÷11216 \frac{1}{2} \div 1 \frac{1}{2}.
      • Step 1: Convert to improper fractions: 332÷32\frac{33}{2} \div \frac{3}{2}.
      • Step 2: Apply "Keep, Change, Flip": 332×23\frac{33}{2} \times \frac{2}{3}.
      • Step 3: Multiply: 666=11\frac{66}{6} = 11 batches.
      • Method 2 (Visual/Pictorial Logic): If 1 batch=1.5 cups1 \text{ batch} = 1.5 \text{ cups}, you can count the half-cups. 16.5 cups16.5 \text{ cups} contains 3333 half-cups. Since 11 batch uses 33 half-cups (1.5 cups1.5 \text{ cups}), then 33÷3=1133 \div 3 = 11 batches.

Mathematical Operations, Inequalities, and Expressions

  • Question 4: Inequalities and Number Comparison

    • Task: Determine if specific values of xx make the inequality x>1.5x > -1.5 true.
    • Evaluations:
      • Value x=212x = -2 \frac{1}{2}: No. On a number line, 2.5-2.5 is to the left of 1.5-1.5, meaning 2.5<1.5-2.5 < -1.5.
      • Value x=1.5x = 1.5: Yes. 1.5>1.51.5 > -1.5.
      • Value x=0.2x = 0.2: Yes. 0.2>1.50.2 > -1.5.
      • Value x=4x = 4: Yes. 4>1.54 > -1.5.
  • Question 5: Algebraic Expressions and Distribution

    • Task: Find an expression equivalent to 7(10a+3b)7(10a + 3b) that shows the sum of exactly two terms.
    • Process: Apply the distributive property.
      • 7×10a=70a7 \times 10a = 70a
      • 7×3b=21b7 \times 3b = 21b
    • Equivalent Expression: 70a+21b70a + 21b.
    • Important Note: Do NOT combine terms after distribution because aa and bb are "not like terms."
  • Question 6: Long Division

    • Task: Divide 21,900÷2521,900 \div 25.
    • Execution:
      • 219÷25=8219 \div 25 = 8 with a remainder of 1919 (8×25=2008 \times 25 = 200).
      • Bring down 00 to get 190190.
      • 190÷25=7190 \div 25 = 7 with a remainder of 1515 (7×25=1757 \times 25 = 175).
      • Bring down the final 00 to get 150150.
      • 150÷25=6150 \div 25 = 6 (6×25=1506 \times 25 = 150).
    • Exact Quotient: 876876.
  • Question 7: Equation Modeling and Variables

    • Scenario: Paul could play 1616 songs. He learns ss new songs. Now he can play 2323 songs.
    • Possible Equations:
      • 16+s=2316 + s = 23
      • s=2316s = 23 - 16
    • Solution: Paul learned 77 new songs (s=7s = 7).

SBA Practice Test Chunk #2: Expressions, Equations, and Ratios

  • Question 8: Equivalent Expressions Distributive Analysis

    • Target Expression: 4(5x+2y)4(5x + 2y).
    • Correct Selections:
      • 4(5x)+4(2y)4(5x) + 4(2y)
      • 20x+8y20x + 8y
    • Incorrect logic examples:
      • 9x+6y9x + 6y (Incorrectly added the multiplier 44 to the coefficients instead of multiplying).
      • 20x+2y20x + 2y (Forgot to distribute the 44 to the second term).
      • 4(7xy)4(7xy) (Cannot combine 5x5x and 2y2y; they are NOT like terms).
  • Question 9: Solving for Variable n

    • Task: Identify all equations where n=6n = 6 is a valid solution.
    • Evaluations:
      • 2+n=62+6=82 + n = 6 \rightarrow 2 + 6 = 8 (Not a solution).
      • n+6=126+6=12n + 6 = 12 \rightarrow 6 + 6 = 12 (Correct solution).
      • 4n=2446=244 \cdot n = 24 \rightarrow 4 \cdot 6 = 24 (Correct solution).
      • n3=263=18n \cdot 3 = 2 \rightarrow 6 \cdot 3 = 18 (Not a solution).
  • Question 10: Ratios and Proportions

    • Scenario: A quiz has history and geography questions. The ratio of history questions to total questions is 4:54 : 5.
    • Data Derivation:
      • History questions = 44
      • Total questions = 55
      • Geography questions = 54=15 - 4 = 1
    • True Statements:
      • The ratio of total questions to history questions is 5:45 : 4.
      • The ratio of history questions to geography questions is 4:14 : 1.
    • False Statement: "There is 1 more history question than geography questions." (False; there are 33 more history questions because 41=34 - 1 = 3).

Calculator Allowed Operations: Data and Proportions

  • Question 11: Ratio Tables (Punch Recipe)

    • Task: Fill in missing values for Ginger Ale (L) and Fruit Juice (oz).
    • Known Ratio: 3 L3 \text{ L} of Ginger Ale to 18 oz18 \text{ oz} of Fruit Juice.
    • Unit Rate: 1 L1 \text{ L} of Ginger Ale per 6 oz6 \text{ oz} of Fruit Juice (18÷3=618 \div 3 = 6).
    • Missing Table Entries:
      • For 5 L5 \text{ L} Ginger Ale: 5×6=30 oz5 \times 6 = 30 \text{ oz} Fruit Juice.
      • For 9 L9 \text{ L} Ginger Ale: 9×6=54 oz9 \times 6 = 54 \text{ oz} Fruit Juice.
  • Question 12: Creating a Histogram

    • Data Set: Texts per day: 0,5,39,29,0,30,14,23,25,220, 5, 39, 29, 0, 30, 14, 23, 25, 22.
    • Frequency Distribution:
      • Range 090 - 9: 33 values (0,5,00, 5, 0).
      • Range 101910 - 19: 11 value (1414).
      • Range 202920 - 29: 44 values (29,23,25,2229, 23, 25, 22).
      • Range 303930 - 39: 22 values (39,3039, 30).
  • Question 13: Multi-Step Financial Planning

    • Scenario: Allison saves for a $500\$500 bicycle. She earns $8\$8 per hour, works 2020 hours per week, for 44 weeks.
    • Step 1 (Weekly Earnings): $8×20=$160\$8 \times 20 = \$160 per week.
    • Step 2 (Total Earnings): $160×4=$640\$160 \times 4 = \$640 total.
    • Step 3 (Surplus): $640$500=$140\$640 - \$500 = \$140 remaining.
  • Question 14: Tape Diagrams and Ratios

    • Scenario: Sam and Tyrone built 4242 model cars altogether. The ratio of Sam to Tyrone is 33 units to 44 units.
    • Step 1: Total units = 3+4=73 + 4 = 7 units.
    • Step 2: Calculate value per unit square: 42÷7=642 \div 7 = 6.
    • Conclusion: Each square in the tape diagram represents 66 cars.

SBA Practice Test Chunk #3: Geometry and Logic

  • Question 15: Coordinate Park Map (Area Calculation)

    • Part A: Rectangle ABCDABCD coordinates: A(4,4)A(-4, 4), B(3,4)B(3, 4), C(3,2)C(3, -2), D(4,2)D(-4, -2).
    • Part B (Total Area):
      • Base (bb) = 77 units (from 4-4 to 33).
      • Height (hh) = 66 units (from 44 to 2-2).
      • Area=b×h=7×6=42 square yardsArea = b \times h = 7 \times 6 = 42 \text{ square yards}.
    • Part C (Red Flowers Area):
      • Triangle ABDABD is half the rectangle: Area=422=21 square yardsArea = \frac{42}{2} = 21 \text{ square yards}.
      • Red flowers occupy 13\frac{1}{3} of triangle ABDABD.
      • Area with red flowers=13 of 21=7 square yards\text{Area with red flowers} = \frac{1}{3} \text{ of } 21 = 7 \text{ square yards}.
  • Question 16: Decimals and Place Value Logic

    • Claim: Will states, "There is no number greater than 0.590.59 that has a 55 in the tenths place."
    • Counterexample: The statement is False. A number like 0.5910.591 is greater than 0.590.59 and correctly maintains a 55 in the tenths place. The thousandths place can be any digit other than zero to satisfy the "greater than" condition.
  • Question 17: Volume of Compound Solids

    • Task: Calculate the volume of a solid made of two right rectangular prisms.
    • Prism 1 Volume: 12cm×5cm×4cm=240cm312 \, \text{cm} \times 5 \, \text{cm} \times 4 \, \text{cm} = 240 \, \text{cm}^3 (Calculation note: 12×5=60,60×4.5=270cm312 \times 5 = 60, 60 \times 4.5 = 270 \, \text{cm}^3 if interpreted as 4.54.5, but visual notes suggest splitting to 9090 and 270270).
    • Segmented Calculation according to Transcript Notes:
      • Volume 1: 5×4×4.5=90cm35 \times 4 \times 4.5 = 90 \, \text{cm}^3.
      • Volume 2: 12×5×4.5=270cm312 \times 5 \times 4.5 = 270 \, \text{cm}^3.
    • Total Volume: 90+270=360cm390 + 270 = 360 \, \text{cm}^3.

Unit Rates and Proportial Reasoning

  • Question 18: Constant Rate of Cost

    • Variable ss: Number of songs.
    • Variable dd: Cost in dollars.
    • Ratio: 2 songs2 \text{ songs} cost $2.58\$2.58.
    • Unit Price: $2.58÷2=$1.29\$2.58 \div 2 = \$1.29 per song.
    • Calculated Table values:
      • 4 songs=4×1.29=$5.164 \text{ songs} = 4 \times 1.29 = \$5.16
      • 7 songs=7×1.29=$9.037 \text{ songs} = 7 \times 1.29 = \$9.03
      • 11 songs=11×1.29=$14.1911 \text{ songs} = 11 \times 1.29 = \$14.19
      • Correct number of songs for $21.93\$21.93: 21.93÷1.29=17 songs21.93 \div 1.29 = 17 \text{ songs}.
  • Question 19: Percentages

    • Given: Ethan answers 80%80\% (or 3232 questions) correctly.
    • Find: Total questions (xx).
    • Equation Setup:
      • 80100=32x\frac{80}{100} = \frac{32}{x}
      • 80x=320080x = 3200
      • x=40x = 40 questions.
  • Question 20: Volume and Dimensions

    • Given: Volume V=243in3V = 243 \, \text{in}^3, Height h=3inh = 3 \, \text{in}.
    • Formula: V=l×w×h243=l×w×3l×w=81V = l \times w \times h \rightarrow 243 = l \times w \times 3 \rightarrow l \times w = 81.
    • Part A (Equal Dimensions): Length = 99, Width = 99 (9×9=819 \times 9 = 81).
    • Part B (Unequal Dimensions): Length = 33, Width = 2727 (3×27=813 \times 27 = 81).
  • Question 21: Absolute Value Claims

    • Claim: "If x>y|x| > |y|, then x>yx > y."
    • Definition: Absolute value is always positive.
    • Supports Claim: Not shown for negative integers.
    • Does Not Support (Counterexamples):
      • x=15,y=14x = -15, y = 14: 15>14|-15| > |14| (15>1415 > 14) is true, but 15>14-15 > 14 is false.
      • x=0.9,y=0.8x = -0.9, y = -0.8: 0.9>0.8|-0.9| > |-0.8| (0.9>0.80.9 > 0.8) is true, but 0.9>0.8-0.9 > -0.8 is false (it is smaller on number line).

SBA Practice Test Chunk #4: Statistics and Applications

  • Question 22: Statistical Histograms and Measures of Center

    • Data Shape: The histogram is "skewed to the right" (tail on the right).
    • Calculations: Total students surveyed = 5+8+6+1=205 + 8 + 6 + 1 = 20.
    • Median: For 2020 pieces of data, the median is between the 10th10^{th} and 11th11^{th} values. These fall in the 2.03.9 mile2.0 - 3.9 \text{ mile} interval.
    • IQR Logic: Since Q3Q_3 must be less than 66, the Interquartile Range cannot be greater than 6.06.0.
  • Question 23: Rate and Time

    • Rate: 36 miles36 \text{ miles} in 45 minutes45 \text{ minutes}.
    • Simplified Rate: 3645=4 miles5 minutes\frac{36}{45} = \frac{4 \text{ miles}}{5 \text{ minutes}}.
    • Prediction for 60 mins: 60÷5=12 sets of 5 minutes60 \div 5 = 12 \text{ sets of 5 minutes}. 12×4 miles=48 miles12 \times 4 \text{ miles} = 48 \text{ miles}.
  • Question 24: Factory Efficiency

    • Production Rate: 1,200 shirts÷6 hours=200 shirts per hour1,200 \text{ shirts} \div 6 \text{ hours} = 200 \text{ shirts per hour}.
    • Total Production Needed: 12,600 shirts12,600 \text{ shirts}.
    • Total Hours Needed: 12,600÷200=63 hours12,600 \div 200 = 63 \text{ hours}.
    • Workday Conversion: 63 hours÷9 hours/day=7 workdays63 \text{ hours} \div 9 \text{ hours/day} = 7 \text{ workdays}.
  • Question 25: Geometric Expressions for Area

    • Scenario: Field width = 5.5m5.5 \, \text{m}. Length = 2m2 \, \text{m} (tulips) + xmx \, \text{m} (lilies).
    • Valid Equations for Total Area:
      • A=5.5(x+2)A = 5.5(x + 2)
      • A=5.5x+11A = 5.5x + 11 (distributed form).
    • Invalid Forms: A=x2(5.5)A = x^2(5.5) or A=2x+5.5xA = 2x + 5.5x.
  • Question 26: Budget Constraint Analysis

    • Goal: Spend between $18\$18 and $20\$20.
    • Prices:
      • Potato Salad: $2.25\$2.25 per 1.5lb1.5 \, \text{lb} ($1.50lb\$1.50 \, \text{lb} calculated from 3.5lbs$5.253.5 \, \text{lbs} \rightarrow \$5.25).
      • Ham: $2.00/lb\$2.00 / \text{lb}.
      • Cheese: $0.60/lb\$0.60 / \text{lb}.
      • Turkey: $3.50/lb\$3.50 / \text{lb}.
      • Shrimp Salad: $5.50/lb\$5.50 / \text{lb}.
    • Combination 4 Example: 2lbs2 \, \text{lbs} Shrimp Salad ($11\$11) + $2\$2 Ham ($4\$4 for 2lbs2 \, \text{lbs}?) + Turkey + Potato Salad results in $19.50\$19.50, which is within range.
  • Question 27: Spatial Packing (Volume Optimization)

    • Containers: 19.5in×39in×19.5in19.5 \, \text{in} \times 39 \, \text{in} \times 19.5 \, \text{in}.
    • Tissue Boxes: 6.5in×6.5in×6.5in6.5 \, \text{in} \times 6.5 \, \text{in} \times 6.5 \, \text{in}.
    • Boxes per dimension:
      • Width: 19.5÷6.5=3 boxes19.5 \div 6.5 = 3 \text{ boxes}.
      • Length: 39÷6.5=6 boxes39 \div 6.5 = 6 \text{ boxes}.
      • Height: 19.5÷6.5=3 boxes19.5 \div 6.5 = 3 \text{ boxes}.
    • Total Capacity: 3×6×3=54 tissue boxes3 \times 6 \times 3 = 54 \text{ tissue boxes}.

Final Chunk: Number Comparisons and Error Analysis

  • Question 28: Comparing Fractions

    • Inequality: n5>420\frac{n}{5} > \frac{4}{20}.
    • Simplification: 420=0.2\frac{4}{20} = 0.2. n5=n×0.2\frac{n}{5} = n \times 0.2.
    • Iteration:
      • If n=1n=1, 0.2=0.20.2 = 0.2 (Not greater).
      • If n=2n=2, 0.4>0.20.4 > 0.2 (True).
    • Lowest Whole Number Numerator: 22.
  • Question 29: Ratio Error Analysis

    • Analysis: The table shows apples in relation to boxes. The relationship is 1 box=15 apples1 \text{ box} = 15 \text{ apples}.
    • Check:
      • Row 2: 5×15=755 \times 15 = 75 (Correct).
      • Row 3: 7×15=1057 \times 15 = 105 (Correct).
    • Error Detection: In Row 1, the table indicates 2 apples2 \text{ apples} in 2 boxes2 \text{ boxes}.
    • Correction:
      • Part A (Error Row): Row 11.
      • Part B (Correct Value): 2×15=30 apples2 \times 15 = 30 \text{ apples}.