Chemical Reactions and Stoichiometry Essentials

Stoichiometry

  • Area of study examining quantities of substances in chemical reactions.
  • Based on the Law of Conservation of Mass.

Chemical Equations

  • Represent chemical reactions on paper.
  • Reactants (left) separated from products (right) by an arrow.
  • "+" separates multiple reactants or products.
  • States of matter: (g)=extgas(g) = ext{gas}, (l)=extliquid(l) = ext{liquid}, (s)=extsolid(s) = ext{solid}, (aq)=extaqueoussolution.(aq) = ext{aqueous solution.}
  • Symbols like extΔext{Δ} over the arrow indicate heat is needed.

Balancing Equations

  • Follows the Law of Conservation of Mass.
  • Balance by changing coefficients, not subscripts.
  • Start with elements appearing in only one reactant and product.
  • Check all elements at the end.

Types of Chemical Reactions

  • Combination Reactions: Two or more substances form one product.
    • Example: metal + nonmetal forming an ionic compound.
  • Decomposition Reactions: One substance breaks down into two or more substances.
    • Example: metal carbonate decomposing into a metal oxide and carbon dioxide upon heating.
  • Combustion Reactions: Rapid reactions producing a flame, often involving oxygen as a reactant.
    • Compounds with C and H burn to produce CO<em>2CO<em>2 and H</em>2OH</em>2O.

Formula Weight (FW)

  • Sum of atomic weights for atoms in a chemical formula.
  • For H<em>2SO</em>4H<em>2SO</em>4: FW=2(extAWofH)+1(extAWofS)+4(extAWofO)FW = 2( ext{AW of H}) + 1( ext{AW of S}) + 4( ext{AW of O}).

Molecular Weight (MW)

  • Formula weight for a molecule.
  • Sum of atomic weights of atoms in a molecule.

Percent Composition

  • Percentage of mass of a compound from each element.
  • \% \text{Element} = \frac{\text{(# atoms of element)} \times (\text{atomic weight})}{\text{formula weight of compound}} \times 100

Avogadro's Number and The Mole

  • Mole (mol): Amount of particles in exactly 12 g12 \text{ g} of C-12.
  • Avogadro's Number: 6.022×10236.022 \times 10^{23} particles per mole.

Molar Mass

  • Mass of 1 mol1 \text{ mol} of a substance (g/mol).
  • Numerically equal to formula weight (in amu).

Mole Relationships and Conversions

  • Moles bridge molecular scale to real-world scale.
  • Convert between mass and atoms/molecules using molar mass and Avogadro's number.

Determining Empirical and Molecular Formulas

  • Empirical Formula: Simplest whole-number ratio of atoms in a compound.
    1. Convert percent composition to grams (assuming 100 g100 \text{ g} sample).
    2. Convert grams to moles.
    3. Divide by the smallest number of moles to find mole ratios.
    4. If not whole numbers, multiply by suitable integer.
  • Molecular Formula: Actual number of atoms in a molecule.
    • Ratio of (Molar Mass / Empirical Formula Weight) gives the whole-number multiple for the empirical formula subscripts.

Combustion Analysis

  • Analyzes C, H, and O compounds by burning in oxygen.
  • Mass of C determined from CO2CO_2 produced.
  • Mass of H determined from H2OH_2O produced.
  • Mass of O determined by mass difference from original compound.

Stoichiometric Calculations

  • Use coefficients in balanced equations as mole ratios to convert between amounts of different substances.
  • Steps: Grams A \rightarrow Moles A \rightarrow Moles B \rightarrow Grams B.

Limiting Reactants

  • Reactant present in the smallest stoichiometric amount; consumed first.
  • Determines the maximum amount of product that can be formed.
  • The other reactant(s) are in excess.

Theoretical and Percent Yield

  • Theoretical Yield: Maximum product calculable from stoichiometry.
  • Actual Yield: Amount of product experimentally obtained.
  • Percent Yield: %Yield=Actual YieldTheoretical Yield×100\% \text{Yield} = \frac{\text{Actual Yield}}{\text{Theoretical Yield}} \times 100