Comprehensive Study Guide for Redox Reactions
Learning Objectives for Redox Reactions
- Oxidation Numbers: Use Roman numerals to indicate the oxidation number of an element in a compound.
- Simultaneous Reactions: Define redox reactions as processes involving simultaneous oxidation and reduction.
- Oxygen Transfer:
- Oxidation: Defined as the gain of oxygen.
- Reduction: Defined as the loss of oxygen.
- Electron Transfer and Oxidation Numbers:
- Oxidation: Defined as the loss of electrons or an increase in oxidation number.
- Reduction: Defined as the gain of electrons or a decrease in oxidation number.
- Identification of Redox: Identify redox reactions based on the gain and loss of oxygen, gain and loss of electrons, or changes in oxidation numbers.
- Rules for Oxidation Numbers:
- The oxidation number of elements in their uncombined state is 0.
- The oxidation number of a monatomic ion is equal to the charge on the ion.
- The sum of oxidation numbers in a neutral compound is 0.
- The sum of oxidation numbers in a polyatomic ion is equal to the charge on the ion.
- Chemical Agents:
- Oxidising Agent: A substance that oxidises another substance and is itself reduced.
- Reducing Agent: A substance that reduces another substance and is itself oxidised.
- Laboratory Tests: Identify redox reactions by colour changes when using acidified aqueous potassium manganate(VII) or aqueous potassium iodide.
Oxidation and Reduction via Oxygen Transfer
- Basic Definition: A redox reaction is where oxidation and reduction take place together at the same time in the same reaction.
- Oxidation (Oxygen Gain):
- Example: Magnesium burning in air.
- Reaction: 2Mg(s)+O2(g)→2MgO(s)
- Observation: Magnesium burns with a dazzling white flame to form white ash (magnesium oxide). The magnesium has gained oxygen and is therefore oxidised.
- Example: Heating copper in air.
- Reaction: 2Cu(s)+O2(g)→2CuO(s)
- Observation: Surface of the copper becomes coated with black copper(II) oxide. This is an oxidation reaction even though it is not highly exothermic and produces no flame.
- Reduction (Oxygen Loss):
- Example: Passing hydrogen over heated copper(II) oxide.
- Reaction: CuO(s)+H2(g)→Cu(s)+H2O(l)
- Observation: The black copper(II) oxide turns pink as it loses oxygen to become copper metal. The copper(II) oxide is reduced.
- Example: Reaction between zinc oxide and carbon.
- Zinc oxide is reduced (loses oxygen) and carbon is oxidised (gains oxygen).
- Specific Examples and Reasons:
- Reaction: 2Mg+CO2→2MgO+C (Magnesium is oxidised; Carbon dioxide is reduced because it lost oxygen).
- Metal Extraction: When Co3O4 is heated in hydrogen to form cobalt metal (Co3O4+4H2→3Co+4H2O), the Co3O4 is reduced because it loses oxygen.
- Nitric Acid Production: In the reaction 4NH3+5O2→4NO+6H2O, the substance oxidised is NH3 because it gains oxygen to become NO.
Oxidation and Reduction via Electron Transfer (OIL RIG)
- Definitions:
- OIL: Oxidation Is Loss of electrons.
- RIG: Reduction Is Gain of electrons.
- Example: Magnesium Oxide Formation:
- Equation: 2Mg(s)+O2(g)→2MgO(s)
- Process: Each magnesium atom loses two electrons (Mg→Mg2++2e−) and each oxygen atom gains two electrons per atom (O+2e−→O2−).
- Magnesium is oxidised (electron loss) and oxygen is reduced (electron gain).
- Redox Without Oxygen:
- Sodium and Chlorine: 2Na(s)+Cl2(g)→2NaCl(s)
- Sodium half-equation (Oxidation): 2Na→2Na++2e−
- Chlorine half-equation (Reduction): Cl2+2e−→2Cl−
- Sodium acts as the electron donor and is oxidised; chlorine acts as the electron acceptor and is reduced.
- Displacement of Bromine: Cl2(g)+2KBr(aq)→2KCl(aq)+Br2(aq)
- Chlorine half-equation (Reduction): Cl2+2e−→2Cl−
- Bromide ion half-equation (Oxidation): 2Br−→Br2+2e−
- Ionic Equation: Cl2+2Br−→2Cl−+Br2
Oxidation States and Numbers
- Definition: Oxidation state indicates how many electrons each atom of an element has gained, lost, or shared in forming a compound. It shows the degree of oxidation or reduction.
- Notation: Usually written with the sign first followed by the number (e.g., +7) or using Roman numerals (e.g., (VII)).
- Standard Oxidation States in Compounds:
- Group I metals (e.g., sodium): +I
- Group II metals (e.g., calcium): +II
- Aluminium: +III
- Hydrogen: +1
- Oxygen: −II (except in peroxides)
- Group VII non-metals (without oxygen): −1
- Transition Metal Variability:
- Iron: +II and +III
- Copper: +I and +II
- Manganese: +II,+IV,+V,+VII
- Chromium: +III and +VI
- Trend Identification:
- A rise in oxidation number signifies oxidation.
- A fall in oxidation number signifies reduction.
- Example: 2FeCl2+Cl2→2FeCl3
- Fe changes from +II to +III (Oxidation).
- Cl changes from 0 to −I (Reduction).
Oxidising and Reducing Agents
- Oxidising Agent:
- Definition: A substance that provides oxygen for another substance or takes electrons from another substance.
- The agent itself is reduced.
- Common Examples: Oxygen, Chlorine, Potassium manganate(VII), hydrogen peroxide.
- Reducing Agent:
- Definition: A substance that removes oxygen from another substance or gives electrons to another substance.
- The agent itself is oxidised.
- Common Examples: Hydrogen, Carbon, Carbon monoxide, reactive metals (e.g., sodium).
- Summary of Roles:
- Electron donor = Reducing agent (is oxidised).
- Electron acceptor = Oxidising agent (is reduced).
Laboratory Tests and Colour Changes
- Potassium Manganate(VII) (Acidified):
- Function: Used as a test for reducing agents.
- The manganese atom in KMnO4 is in oxidation state +VII. It is strongly driven to move to the more stable +II state.
- Equation: MnO_4^-_{(aq)} (purple) + 5e^- \rightarrow Mn^{2+}_{(aq)} (colourless)
- Result: If a reducing agent is present, the purple solution turns colourless.
- Potassium Iodide (KI):
- Function: Used as a test for oxidising agents.
- The iodide ion (I−) is oxidised to iodine (I2).
- Equation: 2I(aq)−(colourless)→I2(aq)(yellow−brown)+2e−
- Result: If an oxidising agent is present, the colourless solution turns yellow-brown (or red-brown). If starch is added, it turns dark blue.
Everyday and Industrial Applications of Redox
- Corrosion: Reactive metals attacked by air and water. The rusting of iron/steel in damp air produces iron(III) oxide (rust), which weakens structures like bridges and ships.
- Rancid Food: Oxidation of fats and oils in butter/margarine leads to unpleasant tastes and smells. Antioxidants or airtight containers are used to prevent this.
- Metal Extraction (Blast Furnace):
- Carbon dioxide is reduced to carbon monoxide: CO2+C→2CO
- Iron(III) oxide (Fe2O3) is reduced to iron by carbon monoxide: Fe2O3+3CO→2Fe+3CO2
- Household Cleaners: Often contain oxidising agents (like bleach) to kill bacteria.
Questions & Discussion
- Question 1: Which reactions involve oxidation and reduction? (List provided: A. Hexane combustion, B. Magnesium burning, C. Calcium carbonate decomposition, D. Magnesium + Copper oxide, E. HCl + NaOH).
- Answer: A, B, and D. (C is thermal decomposition; E is neutralisation).
- Question 2: Which reactions usually involve burning?
- Question 3: What type of reaction happened to copper(II) oxide in equation D (Mg+CuO→MgO+Cu)?
- Question 4: Is it possible to have oxidation without reduction in a chemical reaction?
- Answer: No. Even in magnesium burning, magnesium is oxidised while oxygen is reduced (it is no longer a free element).
- Question 5: Which definition of redox is more useful: oxygen transfer or electron transfer?
- Answer: While oxygen transfer is simpler to understand, the electron-based definition is more useful because it includes more types of reactions.
- Question 6: Calculate oxidation numbers for underlined elements:
- Al3+: +3
- ClO3−: +5 (since Cl+3(−2)=−1→Cl−6=−1).
- O3: 0 (uncombined element).
- PCl3: +3
- Cr2O72−: +6 (since 2Cr+7(−2)=−2→2Cr−14=−2→2Cr=12).
- Question 7: Describe the colour change when bromine reacts with potassium iodide.
- Answer: Colourless to yellow-brown.