Basic Probability: The Multiplication Rule
Introduction to the Multiplication Rule
Assumes familiarity with conditional probability and independent events.
Suggests a review of these topics if needed.
Conditional Probability
Formula: P(A|B) = P(A ∩ B) / P(B)
P(A|B): Probability of A given B is true.
Intersection: P(A ∩ B) is the probability both events occur.
P(B) must be greater than zero for the formula to be valid.
Independence:
If A and B are independent, P(A|B) = P(A).
The roles of A and B can be switched arbitrarily.
The Multiplication Rule for Two Events
Formula:
P(A ∩ B) = P(A) * P(B|A)
Alternatively: P(A ∩ B) = P(B) * P(A|B).
Intuition: Multiply the probability of one event by the conditional probability of the other given the first occurs.
Independence case simplifies to:
P(A ∩ B) = P(A) * P(B) (only true if A and B are independent).
Example: Probability of Drawing Two Red Balls
Problem: An urn contains 3 blue and 5 red balls; draw 2 balls without replacement.
Events defined:
A = First ball is red,
B = Second ball is red.
Steps to Find P(A ∩ B):
Calculate P(A): Drawing a red ball first
P(A) = 5/8.
Calculate P(B|A): Probability the second ball is red given the first is red
P(B|A) = 4/7 (1 red ball removed, leaving 4 red out of 7 total).
Multiply: P(A ∩ B) = (5/8) * (4/7) = 20/56 = 5/14 ≈ 0.357.
Example: Inability to Calculate Intersection
Given: P(A) = 0.4, P(B) = 0.3.
Issue: Cannot find P(A ∩ B) due to insufficient information.
Attempted but not useful:
Trying to use P(B|A) and P(A|B) but lacking necessary probabilities.
Conclusion: Need extra information (like independence) or union probabilities to solve accurately.
Multiplication Rule for Three or More Events
Formula:
P(A ∩ B ∩ C) = P(A) * P(B|A) * P(C|A ∩ B).
Generalization: Continues to work for any number of events by multiplying the conditional probabilities progressively.
Example: Probability of a Randomly Selected Canadian
Given Information:
Probability of being male (M) = 0.5
Probability of living in Ontario (O) = 0.39
Probability of being 65 or older given living in Ontario (E|O) = 0.18
Probability of being male given 65+ and living in Ontario (M|E ∩ O) = 0.45.
To find the intersection: P(M ∩ O ∩ E).
Calculation:
Use the provided information in the order:
P(M ∩ O ∩ E) = P(O) * P(E|O) * P(M|E ∩ O)= 0.39 * 0.18 * 0.45 ≈ 0.032.
Conclusion: Approximately 3% of Canadians are senior males living in Ontario.
Summary
Multiplication rule allows for calculating probabilities involving intersections of events based on conditional probabilities.
Understanding independence is crucial to simplifying calculations.
Useful to recognize when sufficient information is not available to apply these rules.