Compound Interest Calculation

Compound Interest Problem

Given Data

  • Principal (P): $3,000
  • Time (t): 7 years
  • Interest Rate (r): 7% per annum
  • Compounding Frequency: Monthly
  • Withdrawals: None assumed

Formulas

  1. Compound Interest Formula:
    • The formula to calculate the amount A accumulated after a certain time when interest is compounded is given by:
      A=P(1+rn)ntA = P \left(1 + \frac{r}{n}\right)^{nt}
    • Where:
      • A = the amount of money accumulated after n years, including interest.
      • P = principal amount (the initial amount of money).
      • r = annual interest rate (decimal).
      • n = number of times that interest is compounded per year.
      • t = the number of years the money is invested for.

Variable Substitution

  • Convert the interest rate from percentage to decimal:
    • r=7%=0.07r = 7\% = 0.07
  • Since interest is compounded monthly,
    • n=12ext(months)n = 12 ext{ (months)}
  • Substitute the values into the formula:

Calculation

  1. Substitute values into the formula:
    A=3000(1+0.0712)12×7A = 3000 \left(1 + \frac{0.07}{12}\right)^{12 \times 7}
  2. Calculate the monthly interest rate:
    0.0712=0.00583333\frac{0.07}{12} = 0.00583333 (approx.)
  3. Calculate the exponent term:
    nt=12×7=84nt = 12 \times 7 = 84
  4. Rewrite the formula with calculated values:
    A=3000(1+0.00583333)84A = 3000 \left(1 + 0.00583333\right)^{84}
  5. Simplify further:
    • Calculate:
      A=3000(1.00583333)84A = 3000 \left(1.00583333\right)^{84}
  6. Find the value of (1.00583333)84\left(1.00583333\right)^{84}:
    • This value is approximately 1.747422.
  7. Final computation for A: A=3000×1.747422A = 3000 \times 1.747422
    • Thus,
      A5242.27A \approx 5242.27 (rounding to the nearest cent).

Conclusion

  • The amount accumulated after investing $3,000 for 7 years at an interest rate of 7% compounded monthly is approximately $5,242.27.