Displacement, Time, and Average Velocity Exercise

Exercises

Section 2.1: Displacement, Time, and Average Velocity

Problem Statement
  • A car travels in the +x-direction on a straight and level road.
  • The average velocity (D9U_{av}) of the car for the first 4.00 seconds of its motion is given as 6.25 m/s.
Question
  • How far does the car travel in 4.00 s?
Formula for Average Velocity

  • The formula for average velocity is:

    Uav=ΔxΔtU_{av} = \frac{\Delta x}{\Delta t}

  • Where:

    • D9U_{av} = average velocity
    • \Delta x = displacement (distance traveled)
    • \Delta t = time interval
Given Values
  • Average Velocity (D9U_{av}) = 6.25 m/s
  • Time Interval (D9\Delta t) = 4.00 s
Calculation

  • To find the distance traveled by the car, rearrange the formula for average velocity to solve for displacement:

    Δx=Uav⋅Δt\Delta x = U_{av} \cdot \Delta t

  • Substituting the known values into the equation:

    Δx=6.25 m/s⋅4.00 s\Delta x = 6.25 \, \text{m/s} \cdot 4.00 \, \text{s}

  • Performing the multiplication:

    Δx=25.00 m\Delta x = 25.00 \, \text{m}

Conclusion
  • Therefore, the car travels a distance of 25.00 meters in 4.00 seconds.