Displacement, Time, and Average Velocity Exercise

Exercises

Section 2.1: Displacement, Time, and Average Velocity

Problem Statement

• A car travels in the +x-direction on a straight and level road.
• The average velocity (D9U_{av}) of the car for the first 4.00 seconds of its motion is given as 6.25 m/s.

Question

• How far does the car travel in 4.00 s?

Formula for Average Velocity

• The formula for average velocity is:

  U_{av} = \frac{\Delta x}{\Delta t}

• Where:

  • D9U_{av} = average velocity
  • \Delta x = displacement (distance traveled)
  • \Delta t = time interval

Given Values

• Average Velocity (D9U_{av}) = 6.25 m/s
• Time Interval (D9\Delta t) = 4.00 s

Calculation

• To find the distance traveled by the car, rearrange the formula for average velocity to solve for displacement:

  \Delta x = U_{av} \cdot \Delta t

• Substituting the known values into the equation:

  \Delta x = 6.25 \, \text{m/s} \cdot 4.00 \, \text{s}

• Performing the multiplication:

  \Delta x = 25.00 \, \text{m}

Conclusion

• Therefore, the car travels a distance of 25.00 meters in 4.00 seconds.