Angular Acceleration

  • Angular Acceleration Definition

    • Angular acceleration corresponds with linear acceleration.

    • Variable notation: Greek letter alpha (α).

    • Appearance: resembles a fish.

  • Calculation of Angular Acceleration

    • Formula:
      α=ΔωΔt\alpha = \frac{\Delta \omega}{\Delta t} where:

    • Δω\Delta \omega = change in angular velocity

    • Δt\Delta t = change in time

    • Units:

    • Radians per second squared (rad/s2\text{rad/s}^2)

    • Degrees per second squared (°/s2\text{°/s}^2)

    • Angular acceleration is a vector; direction is significant.

    • Preferred units: radians per second squared.

  • Example Problem 1: Ice Skater

    • Scenario: Ice skater increases angular velocity from 450 degrees/s to 610 degrees/s over 2.3 seconds.

    • Known values:

    • Initial angular velocity (ωi\omega_i) = 450 degrees/s

    • Final angular velocity (ωf\omega_f) = 610 degrees/s

    • Time (Δt\Delta t) = 2.3 seconds

    • Conversion of units:

    • Convert degrees to radians:

      • ωi=450×π180=7.85 rad/s\omega_i = \frac{450 \times \pi}{180} = 7.85 \text{ rad/s}

      • ωf=610×π180=10.65 rad/s\omega_f = \frac{610 \times \pi}{180} = 10.65 \text{ rad/s}

    • Change in angular velocity:

    • Δω=ωfωi=10.657.85=2.8 rad/s\Delta \omega = \omega_f - \omega_i = 10.65 - 7.85 = 2.8 \text{ rad/s}

    • Angular acceleration calculation:

    • α=ΔωΔt=2.82.3=1.22 rad/s2\alpha = \frac{\Delta \omega}{\Delta t} = \frac{2.8}{2.3} = 1.22 \text{ rad/s}^2

Tangential Acceleration

  • Tangential Acceleration Definition

    • Denoted as ata_t, where aa is regular linear acceleration.

    • Tangential acceleration relates directly to angular acceleration and radius.

  • Formula for Tangential Acceleration

    • at=α×ra_t = \alpha \times r where:

    • α\alpha = angular acceleration (in rad/s2\text{rad/s}^2)

    • rr = radius (in meters)

    • Units: m/s2\text{m/s}^2

  • Example Problem 2: Olympic Softball Pitcher

    • Scenario: Pitcher changes angular velocity from 1000 degrees/s to 2190 degrees/s over 0.1 seconds, with a radius of 0.7 meters.

    • Known values:

    • Initial angular velocity = 1000 degrees/s (convert to radians: ωi=1000×π180=17.45 rad/s\omega_i = \frac{1000 \times \pi}{180} = 17.45 \text{ rad/s})

    • Final angular velocity = 2190 degrees/s (convert to radians: ωf=2190×π180=38.25 rad/s\omega_f = \frac{2190 \times \pi}{180} = 38.25 \text{ rad/s})

    • Time = 0.1 seconds

    • Radius = 0.7 m

    • Angular acceleration:

    • Δω=ωfωi=38.2517.45=20.8 rad/s\Delta \omega = \omega_f - \omega_i = 38.25 - 17.45 = 20.8 \text{ rad/s}

    • α=ΔωΔt=20.80.1=208 rad/s2\alpha = \frac{\Delta \omega}{\Delta t} = \frac{20.8}{0.1} = 208 \text{ rad/s}^2

    • Calculation of Tangential Acceleration:

    • at=α×r=208×0.7=145.6 m/s2a_t = \alpha \times r = 208 \times 0.7 = 145.6 \text{ m/s}^2

Radial or Centripetal Acceleration

  • Radial Acceleration Definition

    • Also known as centripetal acceleration; implies 'center-seeking'.

    • Occurs when an object moves in a circular path, requiring a radial force.

  • Conceptual Understanding of Radial Acceleration

    • Relationship with Newton's Second Law: F=maF = ma leads to:

    • Fr=mimesarF_r = m imes a_r

    • Illustrative Example: Turntable experiment with jars and cork.

    • Round motion example involving resistance of inertia.

  • Radial Acceleration Calculation

    • Formula options:

    • ar=vt2ra_r = \frac{v_t^2}{r} (using linear velocity)

    • ar=ω2×ra_r = \omega^2 \times r (using angular velocity)

    • Units: m/s2\text{m/s}^2

  • Example Problem 3: Hammer Throw

    • Radial acceleration when the tangential velocity of the hammer is 28 m/s and radius is 2 m:

    • ar=2822=392 m/s2a_r = \frac{28^2}{2} = 392 \text{ m/s}^2

Practical Applications and Implications

  • Centripetal Acceleration in Sports.

    • Example of Sean White in snowboarding:

    • Acceleration relating to speed and forces on the body.

    • Discuss the engineering behind half pipe design affecting athlete performance.

  • Observations on Safety in Sports Engineering

    • Height and radius of half pipe influence centripetal forces and athlete safety.

    • Higher walls, larger radius reduce centripetal force but also increase air time with associated risk.