Module 1 Notes: History, Quantum Theory, Hydrogen Atom, Schrödinger Equation

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    • Prof. Knowles in Hutchison 457: Thursday 3-4 pm, Friday 11 am-12 pm
    • Prof. Matson in Hutchison B45: Thursday 2-3 pm, Friday, 12-1 pm

Module 1: Topic List

  • History of Atomic Theory and discovery of subatomic particles
  • Structure of nucleus
  • Why we need quantum theory to understand Chemistry
  • Key experiments that illustrate problems with classical physics
  • Rules of quantum mechanics: Schrödinger equation, Uncertainty Principle
  • Hydrogen atoms explained with quantum theory: wavefunctions, orbitals and energies
  • Spin and the Pauli Principle
  • Development of the Periodic Table
  • Periodic Trends in properties of the elements

Learning Objectives

  • Cite experimental evidence for the existence of atoms and nuclei
  • Identify an element based on its atomic number and mass
  • Determine when it is necessary to use quantum mechanics
  • Cite experimental evidence for quantum theory
  • Explain some of the mysteries of quantum mechanics to others
  • Calculate spectra and ionization energies of hydrogen
  • Recognize spatial patterns of orbitals
  • Rationalize the relative energies of orbitals in polyelectronic atoms
  • Determine electron configurations of atoms
  • Rationalize the structure of the Periodic Table
  • Understand periodic trends in ionization energy, electron affinity and electronegativity

Summary of Last Lecture: Quantum Implications

  • Observations that “broke” classical physics and their quantum implications:
    • Blackbody radiation
    • Photoelectric effect
    • Line Spectra
    • Energy is quantized; light behaves as particles; atomic energy levels are quantized
  • Key equations:
    • E=nhν,h=6.626×1034 Js,Ephoton=hν=hcλ,E = n h \nu, \quad h = 6.626 \times 10^{-34} \ \text{J} \cdot \text{s}, \quad E_{\text{photon}} = h \nu = \frac{h c}{\lambda},
    • En=2.18×1018 J Z2n2.E_n = -\frac{2.18 \times 10^{-18} \ \text{J} \ Z^{2}}{n^{2}}.
    • Note: The last expression is for hydrogen (Z = 1); for general Z: E<em>n=me4Z28ε</em>02h2n2=2.18×1018 J Z2n2.E<em>n = -\frac{m e^{4} Z^{2}}{8 \varepsilon</em>{0}^{2} h^{2} n^{2}} = -2.18 \times 10^{-18} \ \text{J} \ \frac{Z^{2}}{n^{2}}.

Origins of Bohr’s Model of the Atom

  • Bohr posited that electrons orbit the nucleus at discrete, well-defined distances.
  • Classical balance of forces:
    • mv2R=Ze24πε0R2\frac{m v^{2}}{R} = \frac{Z e^{2}}{4 \pi \varepsilon_{0} R^{2}}
  • Total Energy = kinetic energy + potential energy:
    • E=12mv2Ze24πε0RE = \frac{1}{2} m v^{2} - \frac{Z e^{2}}{4 \pi \varepsilon_{0} R}
  • Angular momentum quantization (Bohr’s postulate):
    • mvR=nh2π=nm v R = n \frac{h}{2 \pi} = n \hbar
  • For Hydrogen, Z = 1
  • Final expression for the quantized energy levels of a hydrogen-like atom:
    • E<em>n=me4Z28ε</em>02h21n2E<em>n = - \frac{m e^{4} Z^{2}}{8 \varepsilon</em>{0}^{2} h^{2}} \frac{1}{n^{2}}
    • =2.18×1018 J Z2n2= -2.18 \times 10^{-18} \ \text{J} \ \frac{Z^{2}}{n^{2}}
  • Orbit radius relation (Bohr radius concept):
    • R<em>n=4πε</em>02me2n2ZR<em>{n} = \frac{4 \pi \varepsilon</em>{0} \hbar^{2}}{m e^{2}} \frac{n^{2}}{Z}
  • Connection to de Broglie waves:
    • De Broglie wavelength: λ=hmv\lambda = \frac{h}{m v}
    • Standing-wave condition: 2πR=nλ,n=1,2,3,2 \pi R = n \lambda, \quad n = 1,2,3,\dots
    • Equivalent expression for angular momentum: mvR=nh2πm v R = n \frac{h}{2 \pi}

De Broglie Wavelength and Bohr’s Model

  • De Broglie relation:
    • λ=hmv\lambda = \frac{h}{m v}
  • Circular standing-wave condition:
    • 2πR=nλ,n=1,2,3,2 \pi R = n \lambda, \quad n = 1,2,3,\dots
  • Equivalence to angular-momentum quantization:
    • mvR=nh2πm v R = n \frac{h}{2 \pi}
  • The de Broglie picture provides a wave explanation for Bohr’s energy quantization

Practice: de Broglie wavelength problem

  • Question: What is the de Broglie wavelength of an electron moving at velocity v=0.01cv = 0.01 c?
  • How does this compare to the distance between the electron and nucleus in the ground-state of the hydrogen atom?
  • Note: Ground-state radius given: Rn=1=5.3×1011 mR_{n=1} = 5.3 \times 10^{-11} \ \, \text{m}

Summary of Last Lecture (continued): Wave-Particle Duality

  • Consequence: Electron Diffraction
  • Davisson and Germer at Bell Labs observed an interference pattern consistent with Bragg’s formula
  • Bragg formula:
    • n=order of diffraction,d=spacing of atoms,θ=scattering anglen = \text{order of diffraction}, \quad d = \text{spacing of atoms}, \quad \theta = \text{scattering angle}
    • nλ=2dsinθn \lambda = 2 d \sin \theta
  • Classical expectations for double-slit: particles vs waves (Feynman reference)

Double-Slit in Electron Microscopy and Matter-Wave Wavelengths

  • Electron microscope setup (one electron at a time)
  • Question: What determines the wavelength of a particle?
  • De Broglie wavelength connection to Bohr’s angular momentum quantization (see above)

De Broglie Wavelength of Matter and Bohr (Detailed)

  • Reiteration of: λ=hmv\lambda = \frac{h}{m v} and 2πR=nλ,mvR=nh2π2 \pi R = n \lambda, \quad m v R = n \frac{h}{2 \pi}
  • The wave nature of matter underpins atomic structure and bonding

Practice: de Broglie wavelength and hydrogen comparison (summary)

  • Provided in the previous practice problem; links to how mass, velocity, and confinement determine wavelength and allowed orbits

Summary Observations: Wave-Particle Duality

  • Four key observations:
    1) Blackbody radiation
    2) Photoelectric effect
    3) Line spectra
    4) Electron diffraction
  • Core ideas:
    • Energy is quantized; light behaves as particles (photons)
    • Atomic energy levels are quantized
    • Matter behaves as waves
  • Key relations (repeated):
    • E=nhν,h=6.626×1034 JsE = n h \nu, \quad h = 6.626 \times 10^{-34} \ \text{J} \cdot \text{s}
    • Ephoton=hν=hcλE_{\text{photon}} = h \nu = \frac{h c}{\lambda}
    • En=2.18×1018 JZ2n2E_n = -2.18 \times 10^{-18} \ \text{J} \frac{Z^{2}}{n^{2}}

Electron Diffraction (Davisson–Germer) and Bragg’s Formula

  • Davisson and Germer demonstrated electron diffraction consistent with wave-like behavior of electrons
  • Bragg’s formula: nλ=2dsinθn \lambda = 2 d \sin \theta
  • The observation that particles can display interference patterns supports wave-particle duality

Schrödinger Equation

  • Schrödinger proposed an equation to describe electron waves (and generalized to other systems):
    • H^ψ=Eψ\hat{H} \psi = E \psi
  • Hamiltonian operator is a set of mathematical operations defining total energy
    • H^=“Kinetic energy operator”+“Potential energy operator”\hat{H} = \text{“Kinetic energy operator”} + \text{“Potential energy operator”}
  • Wavefunction is the object whose squared magnitude gives probabilities
  • In this course, focus on the position of the electron: where are we most likely to find it within an atom?
  • Key definitions:
    • H^ψ=Eψ,H^=22m2+V(r),ψ=wavefunction\hat{H} \psi = E \psi, \quad \hat{H} = -\frac{\hbar^{2}}{2 m} \nabla^{2} + V(\mathbf{r}), \quad \psi = \text{wavefunction}

What does the wavefunction mean?

  • Wavepacket: a cross between a wave and a particle; wavefunction for a free electron (V(x) = 0)
  • For a 1D coordinate x:
    • Δx  ψ2(x)Δx\Delta x \; \psi^{2}(x) \Delta x is the probability of finding the particle in [x, x+Δx]
  • If a position measurement is made, the particle will “choose” a specific location
  • Repeated measurements yield a histogram that maps out ψ2(x)\psi^{2}(x) over x
  • In atoms or molecules, ψ2\psi^{2} is proportional to the electron density; in 3D this corresponds to the electron density per unit volume

The Schrödinger Equation as a Wave Equation (1D Box Analogy)

  • To understand standing waves, consider a particle in a box with walls separated by distance a
  • For a standing wave to exist, the wave must have zero amplitude at the walls (boundary conditions)
  • Nodes occur where the wave crosses zero between walls
  • The allowed wavelengths satisfy
    • λ=2an,n=1,2,3,\lambda = \frac{2 a}{n}, \quad n = 1,2,3,\dots

Hydrogen Atom: Schrödinger Equation in 3D

  • The hydrogen problem leads to standing waves on a sphere (spherical waves)
  • These standing waves are characterized by multiple quantum numbers
  • Note: The slide images are schematic cartoons; they illustrate the concept of standing waves on a circle or a sphere, not literal wavefunctions for hydrogen

Schrödinger Equation: 3D Formalism

  • General form in 3D coordinates:
    • H^ψ=Eψ,H^=22m2+V(x,y,z)\hat{H} \psi = E \psi, \quad \hat{H} = -\frac{\hbar^{2}}{2 m} \nabla^{2} + V(x,y,z)
  • In Cartesian coordinates, the kinetic energy operator expands as:
    • 22m(2x2+2y2+2z2)-\frac{\hbar^{2}}{2 m} \left( \frac{\partial^{2}}{\partial x^{2}} + \frac{\partial^{2}}{\partial y^{2}} + \frac{\partial^{2}}{\partial z^{2}} \right)
  • Potential energy operator simply multiplies by V(x,y,z): V^ψ=V(x,y,z)ψ\hat{V} \psi = V(x,y,z) \psi

Hydrogen Atom Schrödinger Equation: Key Concepts

  • Chemistry is largely governed by the Coulomb potential between nuclei and electrons
  • For hydrogen (one electron, one proton):
    • Coulomb potential is spherically symmetric:
    • V<em>r=e24πε</em>0rV<em>r = -\frac{e^{2}}{4 \pi \varepsilon</em>{0} r}
  • The goal is to obtain wavefunctions (orbitals) and energies that satisfy the equation
  • These orbitals provide the basis for all chemical bonds

Quantum Numbers and Orbitals

  • Each orbital is defined by a set of integers known as quantum numbers (Table 6.1 in the textbook)
  • Generally, there is one quantum number per spatial dimension (in the full treatment there are multiple quantum numbers for the hydrogen problem: n, l, ml, ms in the full solution)
  • The hydrogen orbitals are the eigenfunctions of the Schrödinger equation with the Coulomb potential; in many chemistries courses these orbitals form the basis for bonding and electron configurations

Important Notes and Connections

  • Experimental foundations link classical physics failures to quantum concepts: blackbody radiation, photoelectric effect, line spectra, electron diffraction; these motivate quantization and wave-particle duality
  • De Broglie hypothesis connects particle and wave pictures: matter waves have wavelength λ=hmv\lambda = \frac{h}{m v} which explains the Bohr quantization and leads to standing-wave interpretations of atomic orbitals
  • The Schrödinger equation provides a quantitative framework to calculate allowed energies and spatial distributions of electrons in atoms, beyond Bohr’s simple model
  • The Coulomb potential is central to most chemistry because it captures how charged particles (nuclei and electrons) influence each other’s energy; the spherical symmetry greatly simplifies the hydrogen problem and provides intuition for multi-electron atoms

Quick Reference: Key Equations

  • Quantization of energy for photons and atoms:
    • E=nhν,h=6.626×1034 JsE = n h \nu, \quad h = 6.626 \times 10^{-34} \ \text{J} \cdot \text{s}
    • Ephoton=hν=hcλE_{\text{photon}} = h \nu = \frac{h c}{\lambda}
    • Hydrogen-like energy levels: E<em>n=me4Z28ε</em>02h21n2=2.18×1018 JZ2n2E<em>n = - \frac{m e^{4} Z^{2}}{8 \varepsilon</em>{0}^{2} h^{2}} \frac{1}{n^{2}} = -2.18 \times 10^{-18} \ \text{J} \frac{Z^{2}}{n^{2}}
  • Bohr model relationships:
    • Centripetal-Coulomb balance: mv2R=Ze24πε0R2\frac{m v^{2}}{R} = \frac{Z e^{2}}{4 \pi \varepsilon_{0} R^{2}}
    • Kinetic + Potential energy: E=12mv2Ze24πε0RE = \frac{1}{2} m v^{2} - \frac{Z e^{2}}{4 \pi \varepsilon_{0} R}
    • Angular momentum quantization: mvR=nh2π=nm v R = n \frac{h}{2 \pi} = n \hbar
    • Energy levels (explicit): E<em>n=me4Z28ε</em>02h21n2E<em>n = - \frac{m e^{4} Z^{2}}{8 \varepsilon</em>{0}^{2} h^{2}} \frac{1}{n^{2}}
  • Bohr radius and radii:
    • R<em>n=4πε</em>02me2n2ZR<em>n = \frac{4 \pi \varepsilon</em>{0} \hbar^{2}}{m e^{2}} \frac{n^{2}}{Z}
  • De Broglie wavelength and standing waves:
    • λ=hmv\lambda = \frac{h}{m v}
    • 2πR=nλ,n=1,2,3,2 \pi R = n \lambda, \quad n = 1,2,3,\dots
  • Bohr–de Broglie connection:
    • mvR=nh2πm v R = n \frac{h}{2 \pi}
  • Standing-wave in a 1D box:
    • λn=2an,n=1,2,3,\lambda_n = \frac{2 a}{n}, \quad n = 1,2,3,\dots
  • Schrödinger equation in 1D/3D:
    • H^ψ=Eψ,H^=22m2+V(r)\hat{H} \psi = E \psi, \quad \hat{H} = -\frac{\hbar^{2}}{2 m} \nabla^{2} + V(\mathbf{r})
  • Probability interpretation of the wavefunction:
    • Δx ψ2(x)ΔxProbability of finding particle in [x,x+Δx]\Delta x \ \psi^{2}(x) \Delta x \approx \text{Probability of finding particle in } [x, x+\Delta x]
  • Hydrogenic Coulomb potential:
    • V<em>r=e24πε</em>0rV<em>r = -\frac{e^{2}}{4 \pi \varepsilon</em>{0} r}

Practice and Review Prompts

  • Describe an experiment where we need to think of electrons as waves and how that helps to rationalize the results.
  • Describe an experiment where we need to think of light as particles and how that helps to rationalize the results.
  • Define the de Broglie wavelength in both English and quantitatively. What is its significance? How does it make clear that we need quantum theory to understand chemistry?
  • What was Bohr’s basic idea to explain the energies the electron is allowed to have? How does his theory explain why hydrogen atoms can only emit a few colors of light? How do we determine which colors?
  • State the Uncertainty Principle. What are the practical implications?

Office Hours and Course Logistics (Bonus Reference)

  • Prof. Knowles: Hutchison 457 — Thu 3–4 pm, Fri 11 am–12 pm
  • Prof. Matson: Hutchison B45 — Thu 2–3 pm, Fri 12–1 pm
  • WSL Office hour schedule and UCS tutoring hours (as posted in Blackboard)
  • Quiz and practice problem reminders (e.g., Ionization Energy of hydrogen; links to notes and problem sets)