A study examines the probability of 15 drivers having a blood alcohol content (BAC) exceeding the legal limit.
20% of all drivers are reported to have BAC levels above the limit, which translates to a probability (p) of 0.2.
Goal: Calculate the probability that all 15 drivers have a BAC level exceeding the legal limit.
Probability of success (p) = 0.2
Probability of failure (q) = 1 - p = 0.8
The formula for the binomial probability is:
P(X = k) = (n choose k) * p^k * q^(n-k)
For 15 drivers (k = 15):
P(X = 15) = (15 choose 15) * (0.2)^15 * (0.8)^0 = 1 * (0.2)^15
This evaluates as
(0.2)^15 is a very small number, thus approximately equal to 0.
Conclusion: The probability of all 15 drivers having BAC above the limit is essentially zero.
Goal: Calculate the probability of exactly 6 drivers having BAC above the limit.
Using the binomial probability formula for k = 6:
P(X = 6) = (15 choose 6) * (0.2)^6 * (0.8)^9
Calculation results in:
Approximately 0.043 (or 4.3%).
Conclusion: There is a 4.3% probability of exactly 6 drivers exceeding the BAC limit.
Goal: Find P(X ≥ 6).
This requires calculating the probabilities of X = 6, 7, ..., up to 15.
Advice: Use statistical software or online binomial distribution calculators.
Result obtained: Approximately 0.06.
Conclusion: The probability of 6 or more drivers exceeding the legal BAC limit is about 6%.
Goal: Determine the probability that all drivers are within the legal limit.
This is equivalent to finding P(Y = 0), where Y is the number of drivers above the limit (success).
Since p = 0.2 (probability of being over the limit), the probability of being within the legal limit is:
q = 0.8.
Therefore, for Y = 15, we calculate:
P(X = 0) = (15 choose 0) * (0.2)^0 * (0.8)^15
Conclusion: The probability of all 15 drivers being within the legal limit is calculated using the binomial formula and results in a significant value, indicating that it’s plausible for all drivers to be below the limit.
Mean Calculation: Mean (μ) = n * p = 15 * 0.2 = 3.
Standard Deviation Calculation: Standard deviation (σ) is found using:
σ = sqrt(n * p * (1-p)) = sqrt(15 * 0.2 * 0.8) ≈ 1.55.
Interpretation: On average, 3 out of 15 drivers are expected to exceed the legal BAC limit, with a standard deviation of approximately 1.55, indicating variability in the number of drivers exceeding the limit.
Continuous random variables deal with measurements that can take on any value within a certain range, unlike discrete variables that count occurrences.
Examples: Height, weight, GPA, distance.
Denoted as f(y).
The area under the curve of f(y) equals 1.
The PDF helps to determine probabilities over intervals rather than specific values.
Characteristics: Bell-shaped and defined by mean (μ) and standard deviation (σ).
Can be expressed as: Y ~ N(μ, σ) where N represents normal distribution.
Standard normal distribution is centered at 0 with a standard deviation of 1.
Approximately 68% of values lie within one standard deviation of the mean.
About 95% lie within two standard deviations.
Approximately 99.7% lie within three standard deviations.
Z-Score is calculated as: Z = (Y - μ) / σ.
Z-scores help compare different datasets that may vary in scale but share normal distribution patterns.
Provides insight into how far a specific value is from the mean in terms of standard deviations.