ATI TEAS Mathematics Practice Guide Version 7

Basic Addition and Subtraction

  • Standard Arithmetic Operations: The fundamental process for subtraction involves subtracting digits column-by-column from the rightmost digit. When the top digit is smaller than the bottom digit, the "borrowing" method is applied (e.g., in 1,234−5781,234 - 578, borrow from the tens place to make the ones place 14−8=614 - 8 = 6).
  • Addition with Carrying: Summing numbers like 493+208493 + 208 requires adding columns from right to left; if a sum exceeds 9, the tens digit is carried over to the next column (e.g., 3+8=113 + 8 = 11, carry the 1).
  • Negative Number Rules:     * Subtracting a Negative: Subtracting a negative number is equivalent to adding its positive counterpart (x−(−y)=x+yx - (-y) = x + y). For example, 243−(−157)=243+157=400243 - (-157) = 243 + 157 = 400.     * Adding a Negative: Adding a negative number is equivalent to subtracting that value (x+(−y)=x−yx + (-y) = x - y). For instance, 625+(−489)=625−489=136625 + (-489) = 625 - 489 = 136.     * Negative Result Logic: Subtracting a larger number from a smaller one results in a negative value (3−7=−43 - 7 = -4).
  • Time and Distance Calculations:     * Marathon Times: When adding times (e.g., 2 hours 27.5 minutes+3 hours 35.2 minutes2 \text{ hours } 27.5 \text{ minutes} + 3 \text{ hours } 35.2 \text{ minutes}), add minutes first (62.762.7). Since 60 minutes=1 hour60 \text{ minutes} = 1 \text{ hour}, the total is 6 hours and 2.7 minutes6 \text{ hours and } 2.7 \text{ minutes}.     * Total Journey Distance: Distance problems often involve summing legs of a trip (1,200× City A to B+800× City B to C=2,000 km1,200 \times \text{ City A to B} + 800 \times \text{ City B to C} = 2,000 \text{ km}). Stops do not affect total travel distance.     * Direct Return Distance: Calculated by subtracting completed legs from the total trip distance (e.g., 500 total−(145+230)=125 km500 \text{ total} - (145 + 230) = 125 \text{ km}).

Basic Multiplication and Division

  • Order of Operations (PEMDAS):     * Parentheses: Operations inside parentheses must be solved first.     * Exponents: Apply power rules before further operations.     * Multiplication and Division: Perform these from left to right as they appear in the expression.     * Addition and Subtraction: Perform these last from left to right.     * Example: 50 \text{ % } 5 \times 3 + 10 \rightarrow 10 \times 3 + 10 \rightarrow 30 + 10 = 40.
  • Rules for Signed Numbers:     * Negative multiplied/divided by Negative = Positive.     * Positive multiplied/divided by Negative = Negative.     * Example: -36 \text{ % } 4 \times 3 + 15 \rightarrow -9 \times 3 + 15 \rightarrow -27 + 15 = -12.
  • Calculations with Scenarios:     * Production Increase: To find total yearly production after an efficiency increase, multiply the monthly rate by the increase factor, then by 12 months (e.g., 250×4×12=12,000250 \times 4 \times 12 = 12,000).     * Team Scoring: Final score = (Wins× Points/Win)−(Losses× Points/Loss)(Wins \times \text{ Points/Win}) - (Losses \times \text{ Points/Loss}).     * Rate and Time: Net distance is the difference between opposite directions (e.g., 50 km/h×10 hours north−50 km/h×3.4 hours south=330 km north from start50 \text{ km/h} \times 10 \text{ hours north} - 50 \text{ km/h} \times 3.4 \text{ hours south} = 330 \text{ km north from start}).

Decimals and Fractions

  • Conversions:     * Decimal to Fraction: Terminate decimals are written over a power of 10 and simplified (e.g., 0.75=75100=340.75 = \frac{75}{100} = \frac{3}{4}; 0.125=1251000=180.125 = \frac{125}{1000} = \frac{1}{8}).     * Fraction to Decimal: Divide the numerator by the denominator (\frac{7}{8} = 7 \text{ % } 8 = 0.875).     * Percentage to Decimal: Divide the percentage by 100 (75\text{%} = 0.75).     * Decimal to Percentage: Multiply the decimal by 100 (0.125 \times 100 = 12.5\text{%}).
  • Comparison and Ordering: When comparing mixed formats, convert all numbers to decimals (e.g., to compare 0.250.25, 25\text{%}, and 14\frac{1}{4}, recognize all are 0.250.25).
  • Proportion Logic:     * Complimentary Sets: In a class of 30 where 18 are girls, the fraction of girls is 1830=35\frac{18}{30} = \frac{3}{5}. The remaining students are 1230=25\frac{12}{30} = \frac{2}{5}.     * Fiction Ratios: If 1,500 of 10,000 books are fiction, the ratio of non-fiction is \frac{8,500}{10,000} = 85\text{%}.

Operations with Fractions and Mixed Numbers

  • Addition and Subtraction:     * Common Denominator: To add or subtract (e.g., 34+16\frac{3}{4} + \frac{1}{6}), find the least common multiple of the denominators (1212). Result: 912+212=1112\frac{9}{12} + \frac{2}{12} = \frac{11}{12}.     * Mixed Number Conversion: Convert mixed numbers to improper fractions before calculating (214=(2×4)+14=942 \frac{1}{4} = \frac{(2 \times 4) + 1}{4} = \frac{9}{4}).
  • Multiplication and Division:     * Multiplication: Multiply numerators and denominators independently (34×56=1524\frac{3}{4} \times \frac{5}{6} = \frac{15}{24}, simplified to 58\frac{5}{8}).     * Division: Multiply by the reciprocal of the divisor (\frac{7}{8} \text{ % } \frac{2}{3} = \frac{7}{8} \times \frac{3}{2} = \frac{21}{16} = 1 \frac{5}{16}).
  • Relative Quantity Problems:     * Ratio Factors: If a recipe needs 3133 \frac{1}{3} times as much sugar as salt and you have 212 cups2 \frac{1}{2} \text{ cups} of salt, multiply: 52×103=506=813 cups sugar\frac{5}{2} \times \frac{10}{3} = \frac{50}{6} = 8 \frac{1}{3} \text{ cups sugar}.     * Unit Breakdown: A container with 312 liters3 \frac{1}{2} \text{ liters} can fill glasses holding 14 liter\frac{1}{4} \text{ liter} by dividing: \frac{7}{2} \text{ % } \frac{1}{4} = \frac{7}{2} \times \frac{4}{1} = 14 \text{ glasses}.

Ratios, Proportions, and Percentages

  • Equivalent Ratios: Ratios like 3:43:4, 0.750.75, and 75\text{%} are identical proportions. Ratios like 6:96:9 simplify to 2:32:3.
  • Percentage of a Value: Calculate as (Percent×Value)(\text{Percent} \times \text{Value}) (e.g., 40\text{% of } 250 = 0.40 \times 250 = 100).
  • Finding the Whole: If a portion is known (e.g., 120 \text{ is } 25\text{% of } x), solve using x = 120 \text{ % } 0.25 = 480.
  • Solving Proportions: Use cross-multiplication for a:b::c:xa:b :: c:x (e.g., 9:16 :: x:144 \rightarrow (9 \times 144) \text{ % } 16 = 81).
  • Financial Applications:     * Compound Change: Successive increases/decreases are multiplicative. A 20\text{%} price increase followed by a 20\text{%} decrease results in 1.20 \times 0.80 = 0.96 \text{ (96% of original cost)}.     * Tips and Gratuities: Calculated on the pre-tax amount. Total = Bill+(Bill×Tax Rate)+(Bill×Tip Rate)\text{Bill} + (\text{Bill} \times \text{Tax Rate}) + (\text{Bill} \times \text{Tip Rate}).     * Markups: Retail Price = Cost1−Markup percentage as decimal\frac{\text{Cost}}{1 - \text{Markup percentage as decimal}} or \text{Cost} \times (1 + \text{Markup %}) (e.g., 120 \text{ sale price with } 20\text{% markup } \rightarrow 120 \text{ % } 1.2 = 100 \text{ cost price}).
  • Concentration Problems: A solution involving 60% Solvent A in 500 mL means 300 mL is Solvent A. To reach 50% concentration without changing Solvent A, total volume must become 600 mL, requiring 100 mL additional Solvent B.

Equations with One Variable

  • Algebraic Isolation: Solving 3x−7=2x+83x - 7 = 2x + 8 involves moving xx to one side (3x−2x=x3x - 2x = x) and constants to the other (8+7=158 + 7 = 15).
  • Inequality Rules:     * Directional Sign: When multiplying or dividing both sides by a negative number, the inequality sign must be reversed.     * Example: −5x>−4→x<45-5x > -4 \rightarrow x < \frac{4}{5}.     * Simplification: Distribute constants first (e.g., 2(x−3)→2x−62(x-3) \rightarrow 2x-6), combine like terms, then isolate the variable.
  • Fractional Equations: Eliminate denominators by multiplying all terms by the Least Common Multiple (LCM) of the denominators.

Solving Real-World Mathematical Problems

  • Cost Equations: Total Cost = (Daily Fee)+(Rate per mile×Miles)(\text{Daily Fee}) + (\text{Rate per mile} \times \text{Miles}). For a bill of 9595 with a 5050 daily fee drive 70 miles70 \text{ miles}, calculating (95-50) \text{ % } 70 = 0.64 \text{ per mile}.
  • Mixture Math: Use weighted averages for mixture costs (e.g., almond/cashew mix) and concentrations (e.g., alcohol solutions).
  • Work Rates: For two pipes with filling times of 2 and 3 hours2 \text{ and } 3 \text{ hours}, the combined rate is 12+13=56 tank/hour\frac{1}{2} + \frac{1}{3} = \frac{5}{6} \text{ tank/hour}. Time to fill is 1 \text{ % } \frac{5}{6} = 1.2 \text{ hours (1 hr 12 min)}.
  • Break-even Analysis: Break-even point occurs when Total Revenue=Fixed Costs+Variable Costs\text{Total Revenue} = \text{Fixed Costs} + \text{Variable Costs}. (e.g., Unit sale 250x=100x+5000250x = 100x + 5000).

Powers, Exponents, Roots, and Polynomials

  • Exponent Laws:     * Product Rule: am×an=am+na^m \times a^n = a^{m+n}.     * Power of a Power: (am)n=amn(a^m)^n = a^{mn}.     * Quotient Rule: aman=am−n\frac{a^m}{a^n} = a^{m-n}.     * Zero Exponent: a0=1a^0 = 1.     * Negative Exponents: a−n=1ana^{-n} = \frac{1}{a^n}.     * Fractional Exponents: a1n=The n-th root of aa^{\frac{1}{n}} = \text{The } n\text{-th root of } a.
  • Radical Simplification: Factor the number into prime components to remove perfect squares (e.g., Factor 1152→27×32→Pull out 23×3→Result 24√2\text{Factor } 1152 \rightarrow 2^7 \times 3^2 \rightarrow \text{Pull out } 2^3 \times 3 \rightarrow \text{Result } 24\text{√}2).
  • Polynomial Characteristics:     * Degree: The highest power of the variable present in the polynomial.     * Leading Coefficient: The coefficient of the term with the highest degree.
  • Polynomial Operations:     * Multiplication (FOIL): Multiply binomials term by term.     * Subtraction: Distribute the negative sign to all terms of the polynomial being subtracted before combining like terms.     * Factoring: Difference of squares (x2−9=(x−3)(x+3)x^2 - 9 = (x-3)(x+3)) and perfect squares (x2+4x+4=(x+2)2x^2 + 4x + 4 = (x+2)^2).     * Division: Synthetic or long division. The Remainder Theorem states the remainder of f(x) \text{ % } (x-c) is f(c)f(c).

Standards of Measure

  • Imperial Units:     * 1 pound (lb)=16 ounces (oz)1 \text{ pound (lb)} = 16 \text{ ounces (oz)}.     * 1 foot (ft)=12 inches (in)1 \text{ foot (ft)} = 12 \text{ inches (in)}.     * 1 yard (yd)=36 inches=3 feet1 \text{ yard (yd)} = 36 \text{ inches} = 3 \text{ feet}.     * 1 mile (mi)=5,280 feet1 \text{ mile (mi)} = 5,280 \text{ feet}.     * 1 gallon (gal)=4 quarts (qt)=128 fluid ounces1 \text{ gallon (gal)} = 4 \text{ quarts (qt)} = 128 \text{ fluid ounces}.     * 1 quartile (qt)=2 pints (pt)1 \text{ quartile (qt)} = 2 \text{ pints (pt)}.     * 1 cup=16 tablespoons=236.6 mL1 \text{ cup} = 16 \text{ tablespoons} = 236.6 \text{ mL}.
  • Metric Units:     * 1 kilogram (kg)=1,000 grams (g)1 \text{ kilogram (kg)} = 1,000 \text{ grams (g)}.     * 1 kilometer (km)=1,000 meters (m)1 \text{ kilometer (km)} = 1,000 \text{ meters (m)}.     * 1 meter (m)=100 centimeters (cm)=1,000 millimeters (mm)1 \text{ meter (m)} = 100 \text{ centimeters (cm)} = 1,000 \text{ millimeters (mm)}.     * 1 liter (L)=1,000 milliliters (mL)1 \text{ liter (L)} = 1,000 \text{ milliliters (mL)}.     * 1 cubic meter (m3)=1,000,000 cm3=1,000 Liters1 \text{ cubic meter (m}^3\text{)} = 1,000,000 \text{ cm}^3 = 1,000 \text{ Liters}.
  • Conversions & Temperature:     * 1 inch=2.54 cm1 \text{ inch} = 2.54 \text{ cm}.     * 1 mile ≈ 1.609 km1 \text{ mile} \text{ ≈ } 1.609 \text{ km}.     * 1 kg ≈ 2.205 lb1 \text{ kg} \text{ ≈ } 2.205 \text{ lb}.     * Celsius to Fahrenheit: F=95C+32F = \frac{9}{5}C + 32.     * Fahrenheit to Celsius: C=59(F−32)C = \frac{5}{9}(F - 32).     * Celsius to Kelvin: K=C+273.15K = C + 273.15.     * Note: −40oF and −40oC-40^{\text{o}}F \text{ and } -40^{\text{o}}C represent the same temperature.

Mean, Median, Mode, Range, and Probability

  • Statistics Definitions:     * Mean: The sum of all values divided by the count (NN).     * Median: The middle value in an ordered set. If NN is even, average the two middle numbers.     * Mode: The number that appears most frequently. If no number repeats, there is no mode.     * Range: The difference between the highest and lowest values in the set.
  • Probability Theory:     * Calculation: Favorable OutcomesTotal Possible Outcomes\frac{\text{Favorable Outcomes}}{\text{Total Possible Outcomes}}.     * Independent Events: If A and BA \text{ and } B are independent, the probability of both occurring is P(A)×P(B)P(A) \times P(B).     * Non-replacement: When drawing multiple items without replacement, denominators must decrease for subsequent events (e.g., drawing two green balls from a bag of 15 starts with 615×514\frac{6}{15} \times \frac{5}{14}).     * Complementary Probability: The probability of an event not happening is 1−P(Event)1 - P(\text{Event}).

Geometric Quantities

  • Perimeter Formulas:     * Square: 4s4s.     * Rectangle: 2(L+W)2(L + W).     * Triangle: Sum of three sides.     * Parallelogram: 2(base+side)2(\text{base} + \text{side}).     * Trapezoid: Sum of all sides (bases + non-parallel sides).
  • Area Formulas:     * Rectangle: L×WL \times W.     * Square: s2s^2.     * Triangle: 12base×height\frac{1}{2} \text{base} \times \text{height}.     * Parallelogram: base×height\text{base} \times \text{height}.     * Trapezoid: 12(b1+b2)×h\frac{1}{2}(b_1 + b_2) \times h.     * Circle: ̀r^2.
  • Volume Formulas:     * Rectangular Prism: L×W×HL \times W \times H.     * Triangular Prism: Base Area×Prism Height\text{Base Area} \times \text{Prism Height}.     * Pyramid: 13Base Area×Height\frac{1}{3} \text{Base Area} \times \text{Height}.     * Cylinder: ̀r^2h.     * Cone: \frac{1}{3} ̀r^2h.     * Sphere: \frac{4}{3} ̀r^3.
  • Circles and Semicircles:     * Circumference: C = 2̀r = ̀d.     * Semicircle Perimeter: ̀r + 2r \text{ (Half-circumference + diameter)}.     * Semicircle Area: \frac{1}{2} ̀r^2.
  • Composite Figures: To calculate the perimeter of combined shapes, add the remaining outer sides and subtract the length of the shared interior side where the shapes connect.