Study Notes for Writing and Balancing Chemical Equations
7.1 Writing and Balancing Chemical Equations
LEARNING OBJECTIVES
By the end of this section, you will be able to:
Derive chemical equations from narrative descriptions of chemical reactions.
Write and balance chemical equations in molecular, total ionic, and net ionic formats.
Introduction to Chemical Equations
Chemical equations use element symbols to represent individual atoms.
When atoms gain or lose electrons to form ions, or when they combine to create molecules, their symbols are modified or combined to yield chemical formulas.
To represent the identities and relative quantities of substances involved in a chemical (or physical) change, one must write and balance a chemical equation.
Example Reaction
Consider the reaction of methane (CH4) with oxygen (O2):
Reactants: 1 Methane (CH4) and 2 Diatomic Oxygen (O2)
Products: 1 Carbon Dioxide (CO2) and 2 Water (H2O)
The chemical equation for this process is represented as:
CH4 + 2O2 \rightarrow CO2 + 2H2O
Fundamental Aspects of Chemical Equations
Reactants: The substances that underwent reaction, displayed on the left side of the equation.
Products: The substances generated from the reaction, displayed on the right side of the equation.
Plus Signs (+): Separate individual reactant and product formulas.
Arrow ($\rightarrow$): Separates the reactant side from the product side of the equation.
Coefficients: Numbers placed immediately to the left of each formula to indicate the relative amounts, often expressed in the smallest whole-number terms.
Example Ratio Interpretation:
Methane to oxygen to carbon dioxide to water ratio is 1:2:1:2.
Valid interpretations include:
One methane molecule reacts with two oxygen molecules yielding one carbon dioxide molecule and two water molecules.
One mole of methane reacts with two moles of oxygen yielding one mole of carbon dioxide and two moles of water.
Balancing Equations
A balanced chemical equation ensures equal numbers of each type of atom on both sides, adhering to the law of conservation of matter. This means:
The number of atoms for each element must be equal in both reactants and products.
Example calculation for the methane-oxygen reaction:
Count atoms:
C: 1 (reactant) = 1 (product)
H: 4 (reactant) = 4 (product)
O: 4 (reactant) = 4 (product)
Confirmed balanced since each element maintains equality.
Method: Balancing by Inspection
Balancing equations can be achieved through a straightforward method called balancing by inspection.
Example for the decomposition of water (H_2O):
Unbalanced equation shows H: 2 \neq O: 1.
After adjusting coefficients, the balanced equation is:
2H2O \rightarrow 2H2 + O_2Note: Subscripts in formulas cannot be changed since they define the substance's identity.
Example of Balancing Chemical Equation
For the reaction of molecular nitrogen (N2) and oxygen (O2) to form dinitrogen pentoxide (N2O5), begin with:
Unbalanced Equation:
N2 + O2 \rightarrow N2O5Count atoms:
N: 2 (reactants) vs. 2 (products), balanced.
O: 2 (reactants) vs. 5 (products), not balanced.
Changing coefficients brings balance:
2N2 + 5O2 \rightarrow 2N2O5
Advanced Balancing Techniques
Fractional Coefficients: In some cases, employing fractions can simplify the balancing process temporarily.
Example: Balancing of ethane (C2H6) with oxygen before converting fractional coefficients to integers by multiplying through:
C2H6 + \frac{7}{2}O2 \rightarrow 2CO2 + 3H2O Multiplying by 2 yields: 2C2H6 + 7O2 \rightarrow 4CO2 + 6H2O
Information Included in Chemical Equations
Physical States: Indicated with abbreviations following formulas:
(s): solid
(l): liquid
(g): gas
(aq): aqueous, for substances dissolved in water.
Example: The reaction of sodium (Na) in water (H2O) producing hydrogen gas (H2) and sodium hydroxide (NaOH):
2Na(s) + 2H2O(l) \rightarrow H2(g) + 2NaOH(aq)
Conditions for Reactions
Special conditions may be noted above or below the arrow:
Heating is indicated by the Greek letter delta (\Delta).
Ionic Reactions
Reactions in aqueous solutions often involve ions, which can be represented in varying detail.
Example reaction between calcium chloride (CaCl2) and silver nitrate (AgNO3):
Molecular Equation:
CaCl2(aq) + 2AgNO3(aq) \rightarrow Ca(NO3)2(aq) + 2AgCl(s)Complete Ionic Equation: Dissociates all aqueous ionic compounds:
Ca^{2+}(aq) + 2Cl^{-}(aq) + 2Ag^{+}(aq) + 2NO3^{-}(aq) \rightarrow Ca^{2+}(aq) + 2NO3^{-}(aq) + 2AgCl(s)
Net Ionic Equation
Remove spectator ions to yield:
Ag^{+}(aq) + Cl^{-}(aq) \rightarrow AgCl(s)This represents the actual chemical change taking place.
Additional Example of Ionic Reactions
Dissolving Carbon Dioxide: In reaction with sodium hydroxide (NaOH):
Molecular equation, complete ionic equation, and net ionic equation can be derived using similar balancing methods as previously discussed.