IGCSE Chemistry 0620/42 October/November 2023 Study Notes

Atomic Structure and Electronic Configurations

  • The following electronic configurations represent various atoms and ions:

    • A: 2,52,5
    • B: 2,82,8
    • C: 2,8,22,8,2
    • D: 2,8,42,8,4
    • E: 2,8,52,8,5
    • F: 2,8,62,8,6
    • G: 2,8,18,72,8,18,7
  • Identifications based on electronic configurations:

    • Noble gas atom: B (Neon, with a full outer shell of 88 electrons).
    • Atom of an element in Group VI: F (Sulfur, having 66 valence electrons).
    • Atom with an atomic number of 14: D (Silicon, where the total electrons 2+8+4=142 + 8 + 4 = 14).
    • Atoms from the same group: A and E (Both have 55 valence electrons, placing them in Group V).
    • Halogen atom: G (Chlorine/Bromine family, specifically having 77 valence electrons).
    • An atom of an element which is a good conductor of electricity: C (Magnesium, a metal with 22 valence electrons).
    • A stable ion of a Group V element: B (Group V atoms like A or E gain 33 electrons to achieve the stable 2,82,8 configuration).
    • An atom that forms an ion with a 22- charge: F (Needs to gain 22 electrons to complete its outer shell).

Transition Elements: Cobalt and Copper

  • Properties of Transition Elements:

    • They are significantly harder than Group I metals like Lithium.
    • They have much higher densities than Group I metals.
    • They possess significantly higher melting points and boiling points.
  • Isotopes and Subatomic Particles:

    • Copper (CuCu) has two naturally occurring isotopes: 63Cu{^{63}Cu} and 65Cu{^{65}Cu}.
    • Cobalt (CoCo) has one naturally occurring isotope: 59Co{^{59}Co}.
    • Table 2.1: Particle Counts:
    • 59Co{^{59}Co} atom: Protons = 2727, Neutrons = 3232 (592759 - 27), Electrons = 2727.
    • 65Cu2+{^{65}Cu^{2+}} ion: Protons = 2929, Neutrons = 3636 (652965 - 29), Electrons = 2727 (29229 - 2).
  • Relative Atomic Mass (RAM) Calculation:

    • Data: 63Cu{^{63}Cu} relative abundance = 70%70\%, 65Cu{^{65}Cu} relative abundance = 30%30\%.
    • Calculation: (63×70)+(65×30)100=4410+1950100=63.6\frac{(63 \times 70) + (65 \times 30)}{100} = \frac{4410 + 1950}{100} = 63.6.
    • Relative atomic mass of copper = 63.663.6.
  • Water of Crystallisation:

    • Definition: The water molecules that are chemically bonded into the crystalline structure of a salt.
    • Hydrated Cobalt(II) chloride crystals:
    • Colour: Pink.
    • Formula: CoCl26H2OCoCl_2 \cdot 6H_2O.
    • Anhydrous Copper(II) sulfate water test:
    • Adding water causes a color change from white to blue.
    • Reversibility: This change can be reversed by heating the hydrated salt to evaporate the water.

Extraction of Iron in the Blast Furnace

  • Starting Materials:

    • Coke (Carbon source).
    • Iron ore (Hematite).
    • Limestone (Calcium carbonate).
    • Hot Air (Oxygen source).
  • Chemical Processes:

    • Main Ore: Hematite (contains Fe2O3Fe_2O_3).
    • Reduction Equation: Fe2O3+3CO3CO2+2FeFe_2O_3 + 3CO \rightarrow 3CO_2 + 2Fe.
    • Oxidation Number Change: Iron changes from +3+3 in Fe2O3Fe_2O_3 to 00 in FeFe.
    • Reduction Explanation: The decrease in oxidation number (or the gain of electrons) confirms that the iron has been reduced.
  • Removal of Impurities (Silicon(IV) oxide):

    • Equation 1: CaCO3CaO+CO2CaCO_3 \rightarrow CaO + CO_2 (Type: Thermal Decomposition).
    • Equation 2: CaO+SiO2CaSiO3CaO + SiO_2 \rightarrow CaSiO_3 (Type: Neutralization / Acid-Base reaction).
  • Steel and Corrosion:

    • Alloy: A mixture of a metal with other elements (e.g., steel).
    • Stainless Steel: Made by mixing iron with Carbon and Chromium (or Nickel).
    • Rust: Chemically known as hydrated iron(III) oxide.
    • Protection Methods:
    • Galvanizing: The process of coating steel with Zinc.
    • Barrier Methods: Painting, greasing/oiling, or coating with plastic to prevent contact with water and oxygen.
    • Sacrificial Protection: Zinc is more reactive than iron. It loses electrons more readily and corrodes preferentially, protecting the underlying steel.

Lead(II) Chloride and Electrolysis

  • Preparation of Insoluble Salt (PbCl2):

    • Soluble Salts: Lead(II) nitrate (Pb(NO3)2Pb(NO_3)_2) and Sodium chloride (NaClNaCl) (or Potassium chloride).
    • Ionic Equation: Pb2+(aq)+2Cl(aq)PbCl2(s)Pb^{2+}(aq) + 2Cl^-(aq) \rightarrow PbCl_2(s).
    • Steps for Preparation:
    1. Mix the two aqueous solutions in a beaker.
    2. Filter the mixture to collect the precipitate.
    3. Wash the residue with distilled water to remove impurities.
    4. Dry the pure sample (e.g., in a warm oven or with filter paper).
  • Electrolysis of Molten Lead(II) Chloride:

    • Conductivity: Must be molten so that the ions are mobile and free to move to the electrodes.
    • Anode Reaction (Oxidation): 2Cl(l)Cl2(g)+2e2Cl^-(l) \rightarrow Cl_2(g) + 2e^-.
    • Chlorine Test: Damp blue litmus paper turns red and then bleaches white.
    • Cathode Observation: Formation of a silvery liquid bead of molten Lead metal.

Chemical Energetics and Rates

  • Enthalpy Change (ΔH\Delta H): The term used for the transfer of thermal energy during a reaction.

  • Reaction Equilibrium: CCl4(g)+2H2O(g)CO2(g)+4HCl(g)CCl_4(g) + 2H_2O(g) \rightleftharpoons CO_2(g) + 4HCl(g) (ΔH=130kJ/mol\Delta H = -130\,kJ/mol).

  • Collision Theory Application:

    • If concentration of CCl4CCl_4 increases, the rate of the forward reaction increases.
    • Explanation: There are more particles per unit volume, leading to a higher frequency of successful collisions.
  • Pressure and Equilibrium:

    • Increasing pressure shifts the equilibrium to the left (reactant side).
    • Reason: The left side has fewer moles of gas (33 moles) compared to the right side (55 moles). The system moves to oppose the change by favoring the side with lower pressure.
  • Activation Energy (EaE_a):

    • Definition: The minimum energy that colliding particles must possess for a reaction to occur.
    • Manipulation: The activation energy can be lowered by adding a catalyst.
  • Bond Energy Calculation:

    • Bond Energies: CCl=340kJ/molC-Cl = 340\,kJ/mol, HO=460kJ/molH-O = 460\,kJ/mol, C=O=805kJ/molC=O = 805\,kJ/mol.
    • Energy to break bonds: (4×340)+(4×460)=1360+1840=3200kJ(4 \times 340) + (4 \times 460) = 1360 + 1840 = 3200\,kJ.
    • Energy released from CO2CO_2 formation: 2×805=1610kJ2 \times 805 = 1610\,kJ.
    • Energy change formula: ΔH=Energy InEnergy Out\Delta H = \text{Energy In} - \text{Energy Out}.
    • 130=3200(1610+4(HCl))-130 = 3200 - (1610 + 4(H-Cl))
    • 1720=4(HCl)1720 = 4(H-Cl)
    • HClH-Cl bond energy = 430kJ/mol430\,kJ/mol.

Organic Chemistry: Homologous Series

  • Characteristics of a Homologous Series:

    1. Same general formula.
    2. Same functional group.
    3. Similar chemical properties.
    4. Subsequent members differ by a CH2-CH_2- unit.
  • Examples:

    • Compound A (C12H24C_{12}H_{24}): Belongs to the Alkenes.
    • Compound B (Tetradecane): Belongs to the Alkanes.
    • Compound C (C3H7COOHC_3H_7COOH): Belongs to the Carboxylic acids.
    • Name: Butanoic acid.
    • Structure: A chain of 4 carbons with the terminal carbon double-bonded to Oxygen and single-bonded to an OH-OH group.
  • Amino Acids and Polyamides:

    • Side Chain Calculation:
    • Base structure (H2NCHCOOHH_2N-CH-COOH) mass: N(14)+H(2)+C(12)+H(1)+C(12)+O(16)+O(16)+H(1)=74N(14) + H(2) + C(12) + H(1) + C(12) + O(16) + O(16) + H(1) = 74.
    • Total Mr=103M_r = 103.
    • RR group mass = 10374=29103 - 74 = 29.
    • Formula of RR: C2H5C_2H_5 ((2×12)+5=29(2 \times 12) + 5 = 29).
    • Proteins: The natural polyamides formed from amino acid monomers.