Electrostatic Potential and Capacitance - Exhaustive Study Notes

Introduction to Electrostatic Potential and Conservative Forces

  • Concept of Potential Energy: In mechanics, when an external force does work against a conservative force (like a spring force or gravity), the work is stored as potential energy (UU). When the external force is removed, the body gains kinetic energy at the expense of potential energy, keeping the sum of the two constant.

  • Conservative Forces: The Coulomb force between stationary charges is a conservative force, similar to gravitational force, as both follow an inverse-square dependence on distance. The primary difference lies in the proportionality constants (masses vs. charges).

  • Work and Electrostatic Field: If a test charge qq is moved from point RR to point PP in an electrostatic field E\mathbf{E} produced by a charge configuration (e.g., a charge QQ at the origin):

    • The external force (Fext\mathbf{F}_{ext}) applied must be just enough to counter the electric force (FE\mathbf{F}_E), meaning Fext=FE\mathbf{F}_{ext} = -\mathbf{F}_E.

    • To avoid acceleration, the charge is moved at an infinitesimally slow constant speed.

    • The work done by the external force is: WRP=RPFextdr=RPFEdrW_{RP} = \int_R^P \mathbf{F}_{ext} \cdot d\mathbf{r} = -\int_R^P \mathbf{F}_E \cdot d\mathbf{r}.

    • This work is stored as the potential energy difference between the two points: ΔU=UPUR=WRP\Delta U = U_P - U_R = W_{RP}.

  • Path Independence: The work done by an electrostatic field depends only on the initial and final positions, not on the path taken. This path-independence is the fundamental characteristic of conservative forces.

  • Reference Point for Potential Energy: The actual value of potential energy is not physically significant; only the difference is. It is conventional to choose the potential energy to be zero at infinity. Therefore, the potential energy of a charge qq at a point PP is the work done by an external force to bring it from infinity to that point.

Electrostatic Potential (V)

  • Definition: Electrostatic potential is the work done per unit test charge in bringing a unit positive charge from infinity to a point without acceleration.

  • Mathematical Relation: VPVR=UPURq=WRPqV_P - V_R = \frac{U_P - U_R}{q} = \frac{W_{RP}}{q}.

  • Significance: Potential is a characteristic of the electric field specifically, independent of the test charge qq used to measure it.

  • Historical Note - Count Alessandro Volta (1745–1827): An Italian physicist who established that "animal electricity" (observed by Luigi Galvani) was actually generated by the contact of dissimilar metals with a moist body. He developed the first voltaic pile (battery) using moist cardboard disks (electrolyte) between metal electrodes.

Potential due to a Point Charge

  • Derivation: For a point charge QQ at the origin, the potential at a point PP at distance rr is calculated by integrating the work done on a unit positive charge from infinity to rr.

  • Force on unit charge at rr': E=Q4πϵ0(r)2r^\mathbf{E} = \frac{Q}{4\pi\epsilon_0 (r')^2} \hat{\mathbf{r}}'.

  • Work Done (Integration): W=rQ4πϵ0(r)2dr=Q4πϵ0rW = -\int_{\infty}^r \frac{Q}{4\pi\epsilon_0 (r')^2} dr' = \frac{Q}{4\pi\epsilon_0 r}.

  • Potential Formula: V(r)=Q4πϵ0rV(r) = \frac{Q}{4\pi\epsilon_0 r}.

  • Observations:

    • If Q > 0, then V > 0 (work done against repulsion is positive).

    • If Q < 0, then V < 0 (work done by external force is negative as the field attracts the charge).

    • V1/rV \propto 1/r, whereas the electric field E1/r2E \propto 1/r^2.

Potential due to an Electric Dipole

  • Dipole Configuration: Two charges qq and q-q separated by a distance 2a2a, with dipole moment p=q×2a\mathbf{p} = q \times 2\mathbf{a}.

  • Superposition Principle: The potential at a point PP is the algebraic sum of the potentials due to individual charges:

    • V=14πϵ0(qr1qr2)V = \frac{1}{4\pi\epsilon_0} \left( \frac{q}{r_1} - \frac{q}{r_2} \right), where r1r_1 and r2r_2 are distances from qq and q-q.

  • General Formula (r >> a): At large distances, the potential is given by V(r)=14πϵ0pr^r2=pcos(θ)4πϵ0r2V(r) = \frac{1}{4\pi\epsilon_0} \frac{\mathbf{p} \cdot \hat{\mathbf{r}}}{r^2} = \frac{p \cos(\theta)}{4\pi\epsilon_0 r^2}.

  • Special Cases:

    • On the dipole axis (θ=0\theta = 0 or θ=π\theta = \pi): V=±p4πϵ0r2V = \pm \frac{p}{4\pi\epsilon_0 r^2}.

    • On the equatorial plane (θ=π/2\theta = \pi/2): V=0V = 0.

  • Comparison with Point Charge: Dipole potential falls off as 1/r21/r^2, compared to 1/r1/r for a point charge. It also depends on the angle θ\theta but is axially symmetric about p\mathbf{p}.

Potential due to a System of Charges

  • Calculation: For charges q1,q2,,qnq_1, q_2, \dots, q_n at distances r1P,r2P,,rnPr_{1P}, r_{2P}, \dots, r_{nP} from point PP, the total potential is: V=14πϵ0i=1nqiriPV = \frac{1}{4\pi\epsilon_0} \sum_{i=1}^n \frac{q_i}{r_{iP}}.

  • Continuous Charge Distribution: For a distribution with density ρ(r)\rho(\mathbf{r}), the potential is found by integrating over the volume: V=ρdv4πϵ0rV = \int \frac{\rho \, dv}{4\pi\epsilon_0 r}.

  • Uniformly Charged Spherical Shell:

    • Outside the shell (rRr \geq R): V=q4πϵ0rV = \frac{q}{4\pi\epsilon_0 r}.

    • Inside the shell (r < R): Potential is constant and equals the value at the surface, V=q4πϵ0RV = \frac{q}{4\pi\epsilon_0 R}, since E=0E = 0 inside.

Equipotential Surfaces

  • Definition: A surface where the potential has a constant value at every point.

  • Examples:

    • Single point charge: Concentric spherical surfaces.

    • Uniform electric field: Planes normal to the field lines.

  • Key Properties:

    • No work is required to move a charge between two points on an equipotential surface.

    • The electric field E\mathbf{E} is always normal to the equipotential surface at every point; otherwise, there would be a tangential component, requiring work to be done.

    • Relation between Field and Potential: E=δVδlE = -\frac{\delta V}{\delta l}.

    • Conclusion: The electric field points in the direction where the potential decreases most steeply, and its magnitude is the change in potential per unit displacement normal to the surface.

Potential Energy of a System of Charges

  • Two-Charge System: The work done to bring q1q_1 to r1\mathbf{r}_1 is zero. Then, the work done to bring q2q_2 to r2\mathbf{r}_2 in the field of q1q_1 is q2V1(r2)q_2 V_1(\mathbf{r}_2).

    • U=14πϵ0q1q2r12U = \frac{1}{4\pi\epsilon_0} \frac{q_1 q_2}{r_{12}}.

  • Three-Charge System: Sum of work for each pair added successively:

    • U=14πϵ0(q1q2r12+q1q3r13+q2q3r23)U = \frac{1}{4\pi\epsilon_0} \left( \frac{q_1 q_2}{r_{12}} + \frac{q_1 q_3}{r_{13}} + \frac{q_2 q_3}{r_{23}} \right).

Potential Energy in an External Field

  • Single Charge: If an external potential V(r)V(\mathbf{r}) is specified (from unknown sources), the potential energy of charge qq is U=qV(r)U = qV(\mathbf{r}).

    • Electron Volt (eV): The energy gained by an electron (q=1.6×1019Cq = 1.6 \times 10^{-19}\,C) when accelerated by a potential difference of 1V1\,V. 1eV=1.6×1019J1\,eV = 1.6 \times 10^{-19}\,J.

    • Units: 1keV=103eV1\,keV = 10^3\,eV, 1MeV=106eV1\,MeV = 10^6\,eV, 1GeV=109eV1\,GeV = 10^9\,eV, 1TeV=1012eV1\,TeV = 10^{12}\,eV.

  • Two-Charge System in External Field:

    • U=q1V(r1)+q2V(r2)+q1q24πϵ0r12U = q_1 V(\mathbf{r}_1) + q_2 V(\mathbf{r}_2) + \frac{q_1 q_2}{4\pi\epsilon_0 r_{12}}.

  • Dipole in Uniform External Field:

    • Torque: τ=p×E\mathbf{\tau} = \mathbf{p} \times \mathbf{E}.

    • Potential Energy: U(θ)=pE=pEcos(θ)U(\theta) = -\mathbf{p} \cdot \mathbf{E} = -pE \cos(\theta).

    • This is minimum (pE-pE) when p\mathbf{p} is parallel to E\mathbf{E} and maximum (+pE+pE) when anti-parallel.

Electrostatics of Conductors

  1. Field Inside: Electrostatic field is zero inside a conductor (E=0E = 0).

  2. Field at Surface: Electrostatic field must be normal to the surface at every point. Any tangential component would cause charges to move.

  3. Net Charge: There is no net charge in the interior; excess charge resides only on the outer surface.

  4. Constant Potential: The electrostatic potential is constant throughout the volume and surface of a conductor.

  5. Surface Field Magnitude: The electric field at the surface of a charged conductor is E=σϵ0n^\mathbf{E} = \frac{\sigma}{\epsilon_0} \hat{\mathbf{n}}.

  6. Electrostatic Shielding: The field inside a cavity within a conductor is zero, regardless of the size, shape, or external field. This is used to protect sensitive instruments (Faraday cage effect).

Dielectrics and Polarisation

  • Dielectrics: Non-conductors where an external field induces dipole moments rather than free charge movement.

    • Non-polar molecules: Centers of positive and negative charges coincide (e.g., O2,H2O_2, H_2). An external field induces a dipole moment by displacing the charges.

    • Polar molecules: Have a permanent dipole moment due to charge separation (e.g., H2O,HClH_2O, HCl). An external field tends to align these random dipoles.

  • Polarisation (P\mathbf{P}): Defined as the dipole moment per unit volume. For linear isotropic dielectrics, P=χeE\mathbf{P} = \chi_e \mathbf{E}, where χe\chi_e is the electric susceptibility.

  • Reduction of Field: Induced surface charges (±σp\pm\sigma_p) create an opposing field that reduces the net electric field inside the dielectric.

  • Electric Displacement (D): Defined as D=ϵ0E+P\mathbf{D} = \epsilon_0 \mathbf{E} + \mathbf{P}. This vector is directly related to the free charge density σ\sigma.

Capacitors and Capacitance

  • Capacitor: A system of two conductors separated by an insulator. It stores charge and energy.

  • Capacitance (C): The ratio of charge QQ on one plate to the potential difference VV: C=Q/VC = Q/V.

    • Unit: Farad (FF). 1F=1C/V1\,F = 1\,C/V. Sub-multiples: 1μF=106F1\,\mu F = 10^{-6}\,F, 1nF=109F1\,nF = 10^{-9}\,F, 1pF=1012F1\,pF = 10^{-12}\,F.

  • Parallel Plate Capacitor (Vacuum): C0=ϵ0AdC_0 = \frac{\epsilon_0 A}{d} where AA is plate area and dd is separation.

  • Dielectric Strength: The maximum electric field a dielectric can withstand before breakdown (3×106Vm13 \times 10^6\,V m^{-1} for air).

Effect of Dielectrics and Combinations

  • Dielectric Constant (K): When a dielectric fills the space, capacitance increases by factor KK: C=KC0C = K C_0. Here, K=ϵϵ0K = \frac{\epsilon}{\epsilon_0}, where ϵ\epsilon is the permittivity of the medium.

  • Capacitors in Series:

    • Charges (QQ) are the same across all capacitors.

    • 1Ceq=1C1+1C2++1Cn\frac{1}{C_{eq}} = \frac{1}{C_1} + \frac{1}{C_2} + \dots + \frac{1}{C_n}.

  • Capacitors in Parallel:

    • Potential difference (VV) is the same across all capacitors.

    • Ceq=C1+C2++CnC_{eq} = C_1 + C_2 + \dots + C_n.

Energy Stored in a Capacitor

  • Work Done in Charging: The total work required to charge a capacitor to QQ is stored as electrostatic potential energy:

    • U=12Q2C=12CV2=12QVU = \frac{1}{2} \frac{Q^2}{C} = \frac{1}{2} CV^2 = \frac{1}{2} QV.

  • Energy Density (uu): Energy stored per unit volume in a parallel plate capacitor:

    • u=12ϵ0E2u = \frac{1}{2} \epsilon_0 E^2.

  • Energy Loss in Sharing: When a charged capacitor is connected to an uncharged one, some energy is lost as heat and electromagnetic radiation due to transient charging currents, even if no total charge is lost.

Example Summaries

  • Example 2.1: Calculating potential from a 4×107C4 \times 10^{-7}\,C charge at 9cm9\,cm distance gives 4×104V4 \times 10^4\,V. Moving a 2×109C2 \times 10^{-9}\,C charge to this point results in 8×105J8 \times 10^{-5}\,J of work, which is path-independent.

  • Example 2.2: For charges of 3×108C3 \times 10^{-8}\,C and 2×108C-2 \times 10^{-8}\,C located 15cm15\,cm apart, potential is zero at 9cm9\,cm and 45cm45\,cm from the positive charge along the line.

  • Example 2.4: Work needed to assemble four charges \pm q on corners of a square of side dd is U=q24πϵ0d(42)U = \frac{-q^2}{4\pi\epsilon_0 d} (4 - \sqrt{2}). Potential at the center is zero.

  • Example 2.5: Interaction energy of two charges 7μC7\,\mu C and 2μC-2\,\mu C at 18cm18\,cm separation is 0.7J-0.7\,J. In an external field E=A/r2E = A/r^2, the total energy must account for the separate interactions of each charge with the external potential.

  • Example 2.10: A 900pF900\,pF capacitor charged to 100V100\,V stores 4.5×106J4.5 \times 10^{-6}\,J. When connected to an identical uncharged capacitor, the shared potential becomes 50V50\,V, and the total system energy drops to 2.25×106J2.25 \times 10^{-6}\,J (50% loss).

Practical Conceptual Applications

  • Dry vs. Wet Hair: A comb run through dry hair attracts paper because of frictional charging. On rainy days or with wet hair, friction is reduced, and charge leaks away through moist air.

  • Aircraft Tyres: Made slightly conducting to dissipate static electricity accumulated during friction with the runway to prevent sparks and fire.

  • Fuel Trucks: Use metallic chains/ropes touching the ground to discharge accumulated static charge during motion.

  • Birds on High Power Lines: A bird sitting on one line is at the same potential as the wire. No potential difference means no current flows through the bird. A man on the ground completes a circuit between the high potential line and zero potential ground, causing a shock.