Vectors and Scalars Vector vs. Scalar Quantities Definitions Vector : Numerical quantity possessing both magnitude and direction .Scalar : Numerical quantity possessing magnitude only (no direction).Common examples Vectors: displacement, velocity, acceleration, force. Scalars: distance, speed, energy, pressure, mass. Why the distinction matters On non-linear paths the two differ drastically. Example: Earth’s orbit Annual path length (distance): 9.4 × 10 8 km 9.4\times10^8\ \text{km} 9.4 × 1 0 8 km . Net displacement after one full orbit: 0 km 0\ \text{km} 0 km (returns to the starting point). Highlights that distance ≠ displacement when the path loops back. Representations & Notation Graphical : arrows drawn to scaleArrow direction → vector direction. Arrow length → proportional to magnitude. Symbolic conventions (Kaplan MCAT series) Boldface ((\mathbf{a})) → vector.Italic ((a)) → magnitude of a vector or a scalar.Alternative textbook conventionsArrow over letter ((\vec{a})). Direction referencesHorizontal axis → x x x component. Vertical axis → y y y component. Other axes chosen when more convenient (e.g., along an incline). Vector Addition (Resultant) Resultant : the single vector equivalent to adding (or subtracting) others.Tip-to-tail method Keep magnitude & direction constant. Place tail of (\mathbf{b}) at tip of (\mathbf{a}) . Draw vector from tail of (\mathbf{a}) to tip of (\mathbf{b}) → a + b \mathbf{a}+\mathbf{b} a + b . Component (analytical) method (often faster for >2 vectors)Break every vector into x x x and y y y pieces (or any orthogonal pair). Sum all x x x components → R x R_x R x . Sum all y y y components → R y R_y R y . Magnitude: R = R < e m > x 2 + R < / e m > y 2 R=\sqrt{R<em>x^2+R</em>y^2} R = R < e m > x 2 + R < / e m > y 2 . Direction: θ = tan − 1 ! ( R < e m > y / R < / e m > x ) \theta=\tan^{-1}!\bigl(R<em>y/R</em>x\bigr) θ = tan − 1 ! ( R < e m > y / R < / e m > x ) (inverse tangent; MCAT rarely requires computing it). Component Decomposition & Reconstruction For any vector v \mathbf{v} v at angle θ \theta θ from the x x x -axis:v < e m > x = v cos θ v<em>x = v\cos\theta v < e m > x = v cos θ v < / e m > y = v sin θ v</em>y = v\sin\theta v < / e m > y = v sin θ Conversely, if v < e m > x v<em>x v < e m > x and v < / e m > y v</em>y v < / e m > y are known:v = v < e m > x 2 + v < / e m > y 2 v = \sqrt{v<em>x^2 + v</em>y^2} v = v < e m > x 2 + v < / e m > y 2 θ = tan − 1 ! ( v < e m > y / v < / e m > x ) \theta = \tan^{-1}!\bigl(v<em>y/v</em>x\bigr) θ = tan − 1 ! ( v < e m > y / v < / e m > x ) Example (given) v = 10\,\text{m·s}^{-1},\;\theta = 30^{\circ} v_x = 10\cos30^{\circ}=10\cdot\frac{\sqrt3}{2}=5\sqrt3\,\text{m·s}^{-1} v_y = 10\sin30^{\circ}=10\cdot\frac12 = 5\,\text{m·s}^{-1} Example (find magnitude) Given vx = 3\,\text{m·s}^{-1},\;v y = 4\,\text{m·s}^{-1} v = \sqrt{3^2+4^2}=\sqrt{25}=5\,\text{m·s}^{-1} Vector Subtraction Concept : a − b = a + ( − b ) \mathbf{a}-\mathbf{b} = \mathbf{a}+(-\mathbf{b}) a − b = a + ( − b ) , where − b -\mathbf{b} − b has the same magnitude as b \mathbf{b} b but opposite direction.Tip-to-tail: flip (\mathbf{b}) , then add. Component method: subtract components directlyR < e m > x = a < / e m > x − b x R<em>x = a</em>x - b_x R < e m > x = a < / e m > x − b x R < e m > y = a < / e m > y − b y R<em>y = a</em>y - b_y R < e m > y = a < / e m > y − b y Multiplying Vectors by Scalars New vector b = n a \mathbf{b} = n\mathbf{a} b = n a Magnitude : ∣ b ∣ = ∣ n ∣ ∣ a ∣ |\mathbf{b}| = |n|\,|\mathbf{a}| ∣ b ∣ = ∣ n ∣ ∣ a ∣ .Direction :n>0 → same direction as a \mathbf{a} a . n<0 → opposite direction (antiparallel). Examples3 a 3\mathbf{a} 3 a : three times longer, same way.− 3 a -3\mathbf{a} − 3 a : three times longer, opposite way. Multiplying Vectors by Vectors Dot Product (Scalar Product) Generates scalar (e.g., work W W W ). Formula: a ⋅ b = a b cos θ \mathbf{a}\cdot\mathbf{b}=ab\cos\theta a ⋅ b = ab cos θ . Geometric meaning: projection of one vector onto another times the magnitude of the other. Significance: captures alignment (max when parallel, zero when perpendicular). Cross Product (Vector Product) Generates vector (e.g., torque τ \boldsymbol\tau τ ). Magnitude: ∣ a × b ∣ = a b sin θ |\mathbf{a}\times\mathbf{b}| = ab\sin\theta ∣ a × b ∣ = ab sin θ . Direction: perpendicular to the plane of a \mathbf{a} a & b \mathbf{b} b , determined by the Right-Hand Rule (RHR) . On the 2-D MCAT, this means “into the page” or “out of the page.” Right-Hand Rule (one common version) Point thumb in direction of a \mathbf{a} a . Extend fingers toward b \mathbf{b} b (rotate wrist if necessary). Direction your palm faces = direction of a × b \mathbf{a}\times\mathbf{b} a × b . Alternative mnemonic (index = a \mathbf{a} a , middle = b \mathbf{b} b , thumb = resultant) is equally valid. Worked Example – Cross Products Vectors:a = ⟨ − 3 N , 0 ⟩ \mathbf{a} = \langle -3\,\text{N},\ 0 \rangle a = ⟨ − 3 N , 0 ⟩ (points left along x x x ).b = ⟨ 0 , + 4 m ⟩ \mathbf{b} = \langle 0,\ +4\,\text{m} \rangle b = ⟨ 0 , + 4 m ⟩ (points up along y y y ). Angle between them: 90 ∘ 90^{\circ} 9 0 ∘ . Magnitude of a × b \mathbf{a}\times\mathbf{b} a × b and b × a \mathbf{b}\times\mathbf{a} b × a :
ab\sin90^{\circ} = (3)(4)(1) = 12\,\text{N·m}. Directions via RHRc = a × b \mathbf{c} = \mathbf{a}\times\mathbf{b} c = a × b → “into the page.”d = b × a \mathbf{d} = \mathbf{b}\times\mathbf{a} d = b × a → “out of the page.” Practical & Conceptual Connections Physics problem solving : Breaking vectors into components simplifies kinematics, dynamics, E-fields, etc.Engineering : Cross product governs rotational quantities (torque, angular momentum).Mathematics : Dot & cross products form the backbone of vector calculus and linear algebra; they extend naturally to higher dimensions (though MCAT focuses on 2-D).Philosophical/ethical note : Precise notation prevents miscommunication—critical in research, medicine, and engineering safety.Knowt Play Call Kai