AP Calc Ab Integration Notes
Fundamental Theorem of Calculus (FTC)
Part 1: Establishes the connection between differentiation and integration.
If f is continuous on [a, b] and F is an antiderivative of f on [a, b], then:[ \int_a^b f(x) \ dx = F(b) - F(a) ]
Part 2: Describes how differentiation works with integrals.
If F(x) = [ \int_a^x f(t) \ dt ], then:[ F'(x) = f(x) ]
Interpretation: This shows that differentiation "undoes" integration, allowing evaluation of integrals using antiderivatives.
U-Substitution (U-Sub)
Choose u: Select u = g(x) where g(x) is a suitable function to simplify the integral.
Compute du: Compute the differential: [ du = g'(x) \ dx ].
Rewrite Integral: Substitute u into the integral:[ \int f(g(x)) g'(x) \ dx = \int f(u) \ du ]
Integrate: Solve the integral in terms of u.
Substitute Back: Replace u back in terms of x after integrating to get the final result.
Complex Integrals
Identify the Function: Determine the function of complex numbers to integrate.
Identifying Contour: Choose a closed contour C in the complex plane for integration.
Residue Theorem: Use the theorem when evaluating around poles. If z has a pole, the integral around the contour can be expressed as:[ \int_C f(z) \ dz = 2 \pi i \times \text{(Sum of residues inside C)} ]
Interpretation: This simplifies evaluation of integrals of complex functions.
Inverse Trigonometric Functions
Identify the Integral: Recognize forms for integrals involving inverse trigonometric functions:
For example:[ \int \frac{1}{\sqrt{1-x^2}} \ dx = \sin^{-1}(x) + C ]
Evaluate Other Forms: Learn and evaluate other forms:
[ \int \frac{1}{1+x^2} \ dx = \tan^{-1}(x) + C ]
[ \int \frac{1}{|x| \sqrt{x^2-1}} \ dx = \sec^{-1}(|x|) + C ]
Definite Integration
Set Up the Integral: Write the definite integral over [a, b]:[ A = \int_a^b f(x) \ dx ]
Find Antiderivative: Calculate the antiderivative F(x) of f(x).
Apply Limits: Compute the definite integral using limits:[ A = F(b) - F(a) ]
Interpretation: The result A represents total accumulated value under the curve from x = a to b.
FTC Derivatives
Choose Function: Let F(x) = [ \int_a^x f(t) \ dt ].
Apply FTC: By the theorem:[ F'(x) = f(x) ]
Interpretation: This shows that differentiating the definite integral of f(t) from a to x yields f(x).
Finding Area Under a Curve
Identify the Function: Determine f(x) and the interval from a to b.
Set Up the Integral: Write the integral for area under the curve:[ A = \int_a^b f(x) \ dx ]
Find Antiderivative: Calculate F(x), the antiderivative of f(x).
Apply Limits: Compute the integral using limits:[ A = F(b) - F(a) ]
Interpretation: Result A represents area under the curve from x = a to x = b.
Finding Area Between a Curve and the X-Axis
Identify Function: Determine f(x) and the interval from a to b.
Set Up the Integral: Write integral for area:[ A = \int_a^b |f(x)| \ dx ]
Determine Crossings: Check for crossings of the x-axis.
Separate Segments: If crossings occur, divide integral into segments where f(x) > 0 and f(x) < 0.
Compute Each Integral: Evaluate integrals separately and sum absolute areas to obtain total area.
Finding Area Between Two Curves
Identify Both Functions: Determine upper curve f(x) and lower curve g(x) over interval [a, b].
Set Up the Integral: Write area formula:[ A = \int_a^b (f(x) - g(x)) \ dx ]
Find Points of Intersection: Identify intersection points to determine limits if needed.
Evaluate Integral: Compute the integral to find area between the curves.
Interpretation: Result A represents the area between two curves from x = a to x = b.