Probability and Counting Techniques

How Many Ways (HMW)

  • HMW will be used to represent "How Many Ways" in problems.

Sample Space and Tree Diagrams

  • A sample space lists every possible outcome.
  • A tree diagram is a visual representation of a sample space, useful for illustrating initial concepts but can become bulky.
  • Example: Nick's Outfit Combinations (Doors, Top, Body)
    • Decisions to make: color of doors, color of top, color of body.
    • Possible door colors: red, white, blue (3 choices).
    • Top colors: must be different from the door color (2 choices).
    • Body colors: green, yellow (2 choices).
    • A complete tree diagram will show all possible combinations.
    • Total outcomes are found by counting the branches at the end of the tree. In this case, there are 12 total outcomes.

Fundamental Counting Principle (Slot Method)

  • Also known as the slot method.
  • If two events are done in succession: the first event can be done in xx ways, and the second event can be done in yy ways, then the total number of ways that can be done is equal to x×yx \times y.
  • This can be extended to multiple events.

Applying the Slot Method to Nick's Outfit

  • Three events: doors, top, body.
  • Slots representing each event.
    • Doors: 3 choices.
    • Top: 2 choices (different from door color).
    • Body: 2 choices.
  • Total number of ways: 3×2×2=123 \times 2 \times 2 = 12.
  • If between events, the word "and" makes sense, this means multiply.

License Plate Problem

  • License plates consist of three letters followed by four numbers.

No Restrictions

  • 26 letters in the alphabet.
  • 10 digits (0-9).
  • Number of ways: 26×26×26×10×10×10×10=263×104=175,760,00026 \times 26 \times 26 \times 10 \times 10 \times 10 \times 10 = 26^3 \times 10^4 = 175,760,000.
  • Multiply because it's a letter AND a letter AND a letter and a number AND a number AND a number.

No Repetition Allowed

  • Number of ways: 26×25×24×10×9×8×7=32,760,00026 \times 25 \times 24 \times 10 \times 9 \times 8 \times 7 = 32,760,000.
  • If letters can repeat, but numbers can't: 26×26×26×10×9×8×726 \times 26 \times 26 \times 10 \times 9 \times 8 \times 7.

Seating Arrangement Problem

  • Six people to be seated in a row of six seats.

No Restrictions

  • Choices for each seat: 6, 5, 4, 3, 2, 1.
  • Total number of ways: 6×5×4×3×2×1=7206 \times 5 \times 4 \times 3 \times 2 \times 1 = 720.
  • This is also 6 factorial (6!).
  • n!n! (n factorial) means multiply every number from n down to 1.
  • Calculators have a factorial function.

Couples Must Sit Together

  • Assume couples are boy/girl pairs.
  • Choices: 6, 1, 4, 1, 2, 1 (the "1" represents the date that has to sit with the person).
  • Total ways: 6×1×4×1×2×1=486 \times 1 \times 4 \times 1 \times 2 \times 1 = 48.

Couples Sit Together on the Left

  • Choices: 3, 1, 2, 1, 1, 1 (three options for the first couple -- first two seats).
  • Total ways: 3×1×2×1×1×1=63 \times 1 \times 2 \times 1 \times 1 \times 1 = 6.

Five-Digit Number Problems

  • A five-digit number cannot start with zero.

Digits Cannot Repeat

  • First digit: 9 choices (1-9).
  • Second digit: 9 choices (can include 0, but not the first digit).
  • Remaining digits: 8, 7, 6.
  • Total numbers: 9×9×8×7×6=27,2169 \times 9 \times 8 \times 7 \times 6 = 27,216.

Adjacent Digits Must Be Different

  • First digit: 9 choices (1-9).
  • Second digit: 9 choices (can be 0, but not the first digit).
  • Remaining digits: 9 choices (cannot be the same as the adjacent digit).
  • Total numbers: 9×9×9×9×9=95=59,0499 \times 9 \times 9 \times 9 \times 9 = 9^5 = 59,049.

No Repeats, Number is Odd

  • Last digit must be odd (1, 3, 5, 7, 9) - 5 choices.
  • First digit: 8 choices (cannot be 0 or the last digit).
  • Second digit: 8 choices (can be 0, but not the first or last digit).
  • Third digit: 7 choices.
  • Fourth digit: 6 choices.
  • Total numbers: 8×8×7×6×5=13,4408 \times 8 \times 7 \times 6 \times 5 = 13,440.

Sample Spaces for Kids or Coin Flips

  • Specifically designed for scenarios with two outcomes (e.g., boy/girl, heads/tails).

Three Kids, Exactly Two Girls

  • Three events (births), two outcomes for each.
  • Total possible outcomes: 2×2×2=82 \times 2 \times 2 = 8.
  • Sample Space:
    • Start with total number of outcomes and divide by 2. 8/2 = 4
    • List four boys, then four girls: BBBB GGGG
    • Halve it again: two boys, two girls: BB GG BB GG
    • Halve again: alternate boy and girl: BGBGBGBG
  • The sample space has all unique outcomes.
  • Ways to get two girls: BBG, BGB, GBB (3 ways).

Flip Four Coins, Get Three Tails

  • Four events two outcomes for each.
  • Total possible outcomes: 2×2×2×2=162 \times 2 \times 2 \times 2 = 16.
  • Sample Space:
    • Start with total number of outcomes and divide by 2. 16/2 = 8
    • List eight heads, then eight tails: HHHHHHHH TTTTTTTT
    • Halve it again: four heads, then four tails: HHHH TTTT HHHH TTTT
    • Halve again: two heads, then two tails: HHTT HHTT HHTT HHTT
    • Halve again: alternate head and tail: HTHTHTHTHTHTHTHT
  • Looking for three tails: HTTT, THTT, TTHT, TTTH (4 ways).

Sample Space for Rolling Two Dice

  • Outcomes range from 1-6 on each die.
  • Sample space is all the combinations of dice rolls.

Creating the Sample Space

  • (1,1), (1,2), (1,3), (1,4), (1,5), (1,6)
  • (2,1), (2,2), (2,3), (2,4), (2,5), (2,6)
  • (3,1), (3,2), (3,3), (3,4), (3,5), (3,6)
  • (4,1), (4,2), (4,3), (4,4), (4,5), (4,6)
  • (5,1), (5,2), (5,3), (5,4), (5,5), (5,6)
  • (6,1), (6,2), (6,3), (6,4), (6,5), (6,6)

Using the Sample Space

  • Ways to get a sum equal to 6: (1,5), (2,4), (3,3), (4,2), (5,1) (5 ways).
  • Diagonals from bottom left to top right have the same sum.
  • Ways to get a sum less than 7: count all combinations that sum to less than 7 (15 ways).
  • Ways to get a sum equal to 4 or 9: (1,3), (2,2), (3,1) and (3,6), (4,5), (5,4), (6,3) (7 ways).

Five on Either Die

  • Count combinations with a 5 on either die, but don't double-count (11 ways).
  • The word "or" means to include possibilities from either event.