Kirchhoff’s Law
Kirchhoff's Laws
Ohm’s Law and Resistor Values
R1 = 47.00 Ω
R2 = 0.27 kΩ (or 270 Ω)
R3 = 0.12 kΩ (or 120 Ω)
R4 = 47.00 Ω
R5 = 1.00 kΩ (or 1000 Ω)
Basic Circuit Components
Total Voltage (V_total) = 6 V
Total Current (Itotal) = 8 A
Conventional Current vs. Electron Flow
Conventional Current: Direction of current flow from positive to negative terminal (positive charge flow).
Electron Flow: Actual flow of electrons, which is from negative to positive terminal.
Recommendation: Use conventional current for calculations as it simplifies analysis and understanding.
Kirchhoff’s Laws
Gustav Kirchhoff (1845)
Fundamental laws in electrical engineering for circuit analysis.
Kirchhoff's Current Law (KCL)
Definition: The total current entering a junction must equal the total current leaving the junction.
Kirchhoff's Voltage Law (KVL)
Definition: The sum of the potential differences (voltage) across all elements in a closed circuit loop must equal zero.
Problem Solving Steps with Kirchhoff's Laws
Assign Direction to Currents: Choose direction for currents in each wire; if uncertain, can be adjusted later if the sign of the current is negative.
Apply KCL (Kirchhoff's Current Law): Set up equations based on the junctions.
Draw a Loop for KVL (Kirchhoff's Voltage Law): Analyze closed loops in the circuit and establish equations.
Determine Voltage Drops: If the assumed loop direction aligns with current, resistor voltage drop is considered negative.
Determine Voltage Gains: If the loop goes against current direction, voltage is considered positive.
Capacitor/Battery Behavior:
Leaving positive terminal = positive contribution to the loop equation.
Leaving negative terminal = negative contribution to the loop equation.
Example Problems (Practice Problems)
Example 1
Task: Find the current through each resistor
Solution: I = -0.33 A
Interpretation: Negative current indicates wrong initial assumed direction; adjust as necessary.
Example 2
Task: Find potential difference between points a and b (moving clockwise).
Given:
R1 = 5 Ω
R2 = 10 Ω
ε1 = 12 V
ε2 = 8 V
Capacitance = 4 𝜇F, Stores = 12 𝜇C
Current (I) = 2 A
Solution: Vb - Va = 13 V
Example 3
Task: Calculate current through each resistor in the circuit:
Given: I1 = 2 A, I2 = 3 A, I3 = 1 A.
Detailed verification through Kirchhoff’s Laws and expected constraints on the circuit yields these values.