Comprehensive Trigonometry Notes

Sec. 9.3: De Moivre’s Theorem; Complex Roots

  • De Moivre’s Theorem:

    • Formula for raising a complex number zz to the power of nn, where n1n ≥ 1 is a positive integer.
  • Examples:

    • Write 3cos40+isin403 \cos 40^\circ + i \sin 40^\circ in standard form a+bia + bi.
    • Write 13i1 - \sqrt{3}i in the standard form a+bia + bi.

Complex Roots

  • Examples:
    • Find the complex cube roots of 8-8.
    • Find the complex fourth roots of 3i3-i. Leave answers in polar form, with the argument in degrees.

Sec. 9.3: Product and Quotient of Complex Numbers

Multiplying Complex Numbers in Polar Form

  • Proof

  • Example 1:

    • Find the product (4cos200+isin200)(6cos185+isin185)\left(4 \cos 200^\circ + i \sin 200^\circ\right) \cdot \left(6 \cos 185^\circ + i \sin 185^\circ\right). Then express the product in rectangular form.
  • Example 2:

    • Find the product (72cosπ6+isinπ6)(23cosπ3+isinπ3)\left(7 \sqrt{2} \cos \frac{\pi}{6} + i \sin \frac{\pi}{6} \right) \cdot \left(2 \sqrt{3} \cos \frac{\pi}{3} + i \sin \frac{\pi}{3} \right). Then express the product in rectangular form.

Dividing Complex Numbers in Polar Form

  • Proof

  • Example 3:

    • Find the quotient 4(cos60+isin60)10(cos90+isin90)\frac{4 \left(\cos 60^\circ + i \sin 60^\circ\right)}{10 \left(\cos 90^\circ + i \sin 90^\circ\right)}. Then express the quotient in rectangular form.
  • Example 4:

    • Find the quotient 12(cosπ4+isinπ4)4(cosπ2+isinπ2)\frac{12 \left(\cos \frac{\pi}{4} + i \sin \frac{\pi}{4}\right)}{4 \left(\cos \frac{\pi}{2} + i \sin \frac{\pi}{2}\right)}. Then express the quotient in rectangular form.

Sec. 9.3: The Complex Plane and Polar Form

  • A complex number z=x+yiz = x + yi can be interpreted geometrically as the point (x,y)(x, y) in the xy-plane.

  • Each point in the plane corresponds to a complex number, and conversely, each complex number corresponds to a point in the plane.

  • The collection of such points is referred to as the complex plane.

  • The x-axis is referred to as the real axis, because any point that lies on the real axis is of the form z=x+0i=xz = x + 0i = x, a real number.

  • The y-axis is referred to as the imaginary axis, because any point that lies on it is of the form z=0+yi=yiz = 0 + yi = yi, a pure imaginary number.

  • Example 2:

    • Graph each number in the complex plane and find its modulus.
      • a. z=43iz = 4 - 3i
      • b. z=3+4iz = -3 + 4i
  • Example 3:

    • Express each complex number in polar form using exact values when necessary.
      • a. 1+i1 + i
      • b. 3+i\sqrt{3} + i
  • Example 4:

    • Plot the point corresponding to z=11(cosπ6+isinπ6)z = 11 \left(\cos \frac{\pi}{6} + i \sin \frac{\pi}{6}\right) in the complex plane, then express it in rectangular form using exact values.
  • Example 5:

    • Graph z=3cos60+isin60z = 3 \cos 60^\circ + i \sin 60^\circ in the complex plane and write an expression for zz in rectangular form.

Sec. 9.2: Polar Systems

  • Solving a system of equations with 2 unknowns involves finding the pair(s) of numbers that satisfy both equations.

  • Use the graphing calculator to look for potential solutions.

  • Use algebra and trig to find the exact solutions.

  • Solve equations for solutions between 0° and 360°.

  • Example 1:

    • Solve
      • r=sinθr = \sin \theta
      • r=1r = 1
  • Example 2:

    • Solve
      • r=8cosθr = 8\cos \theta
      • r=5r = 5
  • Example 3:

    • Solve
      • r=6+4cosθr = 6 + 4 \cos \theta
      • r=5+8cosθr = 5 + 8 \cos \theta
  • Example 4:

    • Solve
      • r=5sinθr = 5\sin \theta
      • r=2cosθr = 2\cos \theta

Sec. 9.2: Graphs of Polar Equations

  • In Lesson 9.1, graphing polar equations that were simple in form like r=kr = k and θ=k\theta = k

  • In this lesson, you will learn how to graph more complicated types of polar equations.

  • The best way to graph a “new” type of equation is to use a table of values.

  • Example 1:

    • Graph r=sinθr = \sin \theta. Hint: Let the polar axis scale be 0.25
    • Just like the graph of r=sinθr = \sin \theta above, it illustrates a circle with a diameter of 1 that passes through the origin.
    • Just like with any graph, you can alter its shape and position by multiplying the function by a number and/or adding to it.
    • You can also alter the graph by multiplying or adding numbers to θ\theta.
    • However, you may be very surprised to find that the results are vastly different from the graphing transformations you have learned previously.
  • Example 2:

    • Graph r=35cosθr = -3 - 5\cos \theta Hint: Let the polar axis scale be 2

Use Graphing Calc to Sketch Classical Curves

  • Ex. Sketch r=2+2cosθr = 2 + 2 \cos \theta
  • Ex. Sketch r=4θr = 4 \theta
  • Ex. Sketch r=5sin2θr = 5\sin 2\theta
  • Ex. Sketch r2=4cos2θr^2 = 4\cos 2\theta

Sec. 9.1: Converting from Polar to Rectangular and back…

  • Suppose a rectangular coordinate system is superimposed on a polar coordinate system so that the origins coincide and the x-axis aligns with the polar axis.

  • Let P be any point in the plane.

  • Polar coordinates: (r,θ)(r, \theta)

  • Rectangular coordinates: (x,y)(x, y)

  • Trigonometric functions can be used to convert from polar coordinates to rectangular coordinates.

  • Example 1:

    • Find the rectangular coordinates of each point. Express as exact values when possible, otherwise round coordinate values to the nearest hundredth.
      • a. (5,π3)\left(5, \frac{\pi}{3}\right)
      • b. Q(13,70)Q(-13, 70^\circ)
  • If a point is named by the rectangular coordinates (x,y)(x, y), you can find the corresponding polar coordinates by using the Pythagorean Theorem and the Arctangent function.

  • Since the Arctangent function only determines angles in the first and fourth quadrants, you must add π\pi radians to the value of θ\theta for points with coordinates (x,y)(x, y) that lie in the second or third quadrants.

  • Example 2:

    • Find the polar coordinates of R(8,12)R(-8, -12) rounded to the nearest hundredth.
  • Example 3:

    • The conversion equations can also be used to convert equations from one coordinate system to the other.
  • Example 4:

    • Write the polar equation r=6cosθr = 6\cos \theta in rectangular form.
  • Example 5:

    • Write the rectangular equation x2+(y+3)2=9x^2 + (y + 3)^2 = 9 in polar form.
  • Example 6:

    • Transform the equation y=x4y = \frac{x}{4} from rectangular coordinates to polar coordinates.

Sec. 9.1/9.2: Polar Coordinates

  • Recording the position of an object using the distance from a fixed point and an angle made with a fixed ray from that point uses a polar coordinate system.

  • When surveyors record the locations of objects using distances and angles, they are using polar coordinates.

  • The Polar Coordinate Plane

    • In a polar coordinate system, a fixed point O is called the pole or origin.
    • The polar axis is usually a horizontal ray directed toward the right from the pole.
    • The location of a point P in the polar coordinate system can be identified by polar coordinates in the form (r,θ)(r, \theta).
    • If a ray is drawn from the pole through P, the distance from the pole to point P is rr.
    • The measure of the angle formed by OPOP and the polar axis is θ\theta.
    • The angle can be measured in degrees or radians.
    • It is important to consider both positive and negative values of r.
    • Suppose r > 0. Then θ\theta is the measure of any angle in standard position that has OPOP as its terminal side.
    • Suppose r < 0. Then θ\theta is the measure of any angle that has the ray opposite OPOP as its terminal side.
  • Example 1:

    • Graph each point.
      • a. P(3,60)P(3, 60^\circ)
      • b. Q(1.5,7π6)Q\left(-1.5, \frac{7\pi}{6}\right)
  • You may have noticed that the r-coordinate can be any real value.

  • The angle θ\theta can also be negative.

  • If \theta > 0, then θ\theta is measured counterclockwise from the polar axis.

  • If \theta < 0, then θ\theta is measured clockwise from the polar axis.

  • Example 2:

    • Graph R(2,135)R(-2, -135^\circ)
  • Example 3:

    • Name four different ordered pairs of polar coordinates that represent point S on the graph with the restriction that 360θ360-360^\circ \le \theta \le 360^\circ.
  • An equation expressed in terms of polar coordinates is called a polar equation. For example, r=2sinθr = 2\sin \theta is a polar equation.

  • A polar graph is the set of all points whose coordinates (r,θ)(r, \theta) satisfy a given polar equation.

  • Example 4:

    • Graph each polar equation.
      • a. r=3r = 3
      • b. θ=4π3\theta = \frac{4\pi}{3}
  • Note: In Example 2, the location of point R suggests that it could be called R(2,45)R(2, 45^\circ). Polar points are not unique. They can be represented by infinitely many different ordered pairs.

  • Given two points P<em>1(r</em>1,θ<em>1)P<em>1(r</em>1, \theta<em>1) and P</em>2(r<em>2,θ</em>2)P</em>2(r<em>2, \theta</em>2) in the polar plane, draw P<em>1OP</em>2P<em>1OP</em>2. P<em>1OP</em>2\angle P<em>1OP</em>2 has measure θ<em>1θ</em>2|\theta<em>1 - \theta</em>2|. Apply the Law of Cosines to P<em>1OP</em>2\triangle P<em>1OP</em>2.

P<em>1P</em>22=OP<em>12+OP</em>222(OP<em>1)(OP</em>2)cos(θ<em>2θ</em>1)P<em>1P</em>2^2 = OP<em>1^2 + OP</em>2^2 - 2(OP<em>1)(OP</em>2)\cos(\theta<em>2 - \theta</em>1)
P<em>1P</em>22=r<em>12+r</em>222r<em>1r</em>2cos(θ<em>2θ</em>1)P<em>1P</em>2^2 = r<em>1^2 + r</em>2^2 - 2r<em>1r</em>2 \cos(\theta<em>2 - \theta</em>1)

  • Example 5:
    • If two landmarks are 700 feet away and 40° to the left, and 350 feet away and 35° to the right, what is the distance between the landmarks?

Sec. 10.7: Parametric Equations and Projectile Motion

  • Objects that are launched are called projectiles. The path of a projectile is called its trajectory. The horizontal distance that a projectile travels is its range. Physicists describe the motion of a projectile in terms of its position, velocity, and acceleration. All these quantities can be expressed by vectors.

  • Parametric equations can represent the position of the ball relative to the starting point in terms of the parameter time.

  • In order to find parametric equations that represent the path of a projectile like a football, we must write the horizontal v<em>xv<em>x and vertical v</em>yv</em>y components of the initial vector.

  • Because the horizontal velocity is unaffected by gravity, it is the magnitude of the horizontal component of the initial velocity. Therefore, the horizontal position of a projectile, after tt seconds is given by the following equation.


x = v_x t

  • Since vertical velocity is affected by gravity, we must adjust the vertical component of the initial velocity. By subtracting the vertical displacement due to gravity from the vertical displacement caused by the initial velocity, we can determine the height of the projectile after t seconds. The height, in feet, or meters, of a free-falling object affected by gravity is given by the equation h=12gt2h = \frac{1}{2}gt^2, where g9.8m/s2g \approx 9.8 m/s^2 or 32ft/s232 ft/s^2 and tt is the time in seconds.

  • Example 1:

    • Jana hit a golf ball with an initial velocity of 102 ft/s at an angle of 67° to the ground.
      • a. Write the parametric equations.
      • b. After 2 seconds, how far has the ball traveled horizontally?
      • c. After 0.8 seconds, how high is the ball?
      • d. How long will the ball be in the air?
      • e. How far did the ball travel off the tee?
      • f. What was the maximum height of the ball?
  • Example 2:

    • A pitcher on a professional baseball team throws a ball at an angle of 5.1° with the horizontal at a speed of 85 mph. The distance of the pitcher’s mound to home plate is 60.5 feet. The pitcher releases the ball 2.9 feet above the ground.
      • a. How far from the ground is the ball when it crossed home plate?
      • b. If it is a passed ball, how long will the ball be in the air?

Vectors and Parametric Equations

  • If a line passes through the points P<em>1P<em>1 and P</em>2P</em>2 and is parallel to the vector a=a<em>1,a</em>2\textbf{a} = \langle a<em>1, a</em>2 \rangle, the vector P<em>1P</em>2\overrightarrow{P<em>1P</em>2} is also parallel to a\textbf{a}.

  • Thus P<em>1P\overrightarrow{P<em>1P} must be a scalar multiple of a\textbf{a}. Using the scalar tt, we can write the equation PP</em>1=ta\overrightarrow{PP</em>1} = t\textbf{a}. This is called the vector equation of the line.

  • Since a\textbf{a} is parallel to the line, it is called the direction vector. The scalar tt is called the parameter.

  • Example 1:

    • Write a vector equation describing a line passing through (1,4)(1, 4) and parallel to a=3,2\textbf{a} = \langle -3, 2 \rangle.
  • Example 2:

    • Find the parametric equations for a line parallel to q=6,3\textbf{q} = \langle -6, 3 \rangle and passing through the point (2,4)(-2, -4).
  • Example 3:

    • Write parametric equations of y=x+4y = -x + 4.
  • Example 4:

    • Write an equation in slope-intercept form of the line whose parametric equations are