Forces and Equilibrium Notes
Normal Force
- Definition: Electrostatic force exerted by a surface on an object, balancing the force exerted by the object on the surface.
- Direction: Always acts perpendicular and upwards from the surface on which the object is situated.
- Balance: Balances the component of weight directed along the same axis but in the opposite direction.
- Horizontal Ground, Object at Rest: FN=mg.
- Stationary Object with Other Vertical Forces: Find FN by equating all forces acting perpendicular to the ground.
- Object on Incline, Stationary: FN balances the component of mg parallel to the normal force.
- Object on Incline, Stationary, with Other Perpendicular Forces: FN balances the component of mg parallel to the normal force plus/minus other forces acting perpendicular to the incline.
Force of Tension (FT)
- Definition: Force exerted by a rope on an object.
- Direction: Always in the direction in which the rope is pulled.
Force of Friction (F<em>fs and F</em>fk)
- Cause: Arises from the unevenness in the surfaces of objects, even highly-polished surfaces. Atoms stacked side by side create bumps, which lead to friction.
- Types:
- Static friction (Ffs): For a body not in motion.
- Kinetic friction (Ffk): For a body in motion.
- Static Friction in Response to Applied Force:
- Static friction acts in response to an applied force (FT).
- As F<em>T increases, F</em>fs also increases until it reaches its maximum possible value (Ffs,max).
- If F<em>T gets bigger than F</em>fs,max, the object starts to move.
- Computation of Static Friction: When asked to compute F<em>fs, compute F</em>fs,max.
Kinetic and Static Friction Equations
- Kinetic Friction: Always opposite to the direction of motion.
- F<em>fk=u</em>kFN
- Static Friction:
- F<em>fs,max=u</em>sFN
- <br/>u<em>s and u</em>k: Coefficients of static and kinetic frictions, respectively; depend on the two surfaces in contact.
Equilibrium System
- Definition: A system is in equilibrium when the sum of all forces on the system is zero (Fnet=0).
- Condition: No acceleration.
- State: Either not moving or moving with a constant velocity.
- Types:
- Static equilibrium: Object is at rest.
- Dynamic equilibrium: Object moving in a straight line at a constant speed (i.e., constant velocity).
Equilibrium Problem Solving Strategy
- PREPARE
- Make simplifying assumptions.
- Check that the object is either at rest or moving with constant velocity (a=0).
- Identify forces and show them on a free-body diagram.
- SOLVE
- Use Newton's Second Law in component form:
- ΣF<em>x=ma</em>x=0
- ΣF<em>y=ma</em>y=0
- Read the components from the free-body diagram.
- ASSESS
- Is the result reasonable?
Non-Equilibrium or Dynamic Systems
- Condition: Net force is not zero (Fnet=ma).
- State: Possesses a non-zero acceleration (speeding up or slowing down).
- Note: Dynamic equilibrium system is not the same as dynamic systems.
Dynamic Problem Solving Strategy
- PREPARE
- Make simplifying assumptions.
- Make a visual overview:
- Sketch a pictorial representation.
- Identify known quantities and what the problem is trying to find.
- Identify all forces and show them on a free-body diagram.
- SOLVE
- Use Newton's Second Law in component form:
- ΣF<em>x=ma</em>x
- ΣF<em>y=ma</em>y
- Read the components of the vectors from the free-body diagram.
- If needed, use kinematics to find positions and velocities.
- ASSESS
- Is the result reasonable?
QuickCheck Questions and Answers
- Question 3: Which of these objects is in equilibrium?
- A. A car driving down the road at a constant speed
- B. A block sitting at rest on a table
- C. A skydiver falling at a constant speed
- D. All of the above
- Question 4: Forces acting on a person hanging from a rope.
- Is this system in equilibrium?
- Represent the object of interest by a ’dot.’
- Identify all long-range forces.
- Identify all contact forces.
- Draw Force vectors showing the correct directions and relative magnitudes.
- If the weight of the person is 70 N, what is the tension on the rope? Object of interest: The person.
- Question 5 & 6: A steel beam hangs from a cable as a crane lifts the beam at a constant acceleration?
- What forces act on the beam if the beam is moving up with a constant acceleration?
- A. Gravity.
- B. Gravity and tension in the cable.
- C. Gravity and a force of motion.
- D. Gravity and tension and a force of motion.
- Is this system in equilibrium?
- Question 7: Can you draw the free body diagram if the beam is moving up with a constant acceleration?
- Question 8: An object on a rope is lowered at constant speed. Which of the following is true?
- A. The rope tension is greater than the object’s weight.
- B. The rope tension equals the object’s weight.
- C. The rope tension is less than the object’s weight.
- D. The rope tension can’t be compared to the object’s weight.
- Hint: Draw a free body diagram first
- Question 9: An object on a rope is lowered at a steadily decreasing speed. Which is true?
- A. The rope tension is greater than the object’s weight.
- B. The rope tension equals the object’s weight.
- C. The rope tension is less than the object’s weight.
- D. The rope tension can’t be compared to the object’s weight.
- Hint: Draw a free body diagram first
- Question 10: A ball has been tossed straight up. Which is the correct free-body diagram just after the ball has left the hand? Ignore air resistance.
- Question 11: A car is towed to the right at constant speed. Which is the correct free-body diagram?
- Question 12, 13 & 14: A box is resting on a smooth frictionless horizontal surface of a table.
- Is this system in equilibrium?
- Net force =?
- Question 15: A box is sitting on the floor of an elevator. The elevator is accelerating upward. The magnitude of the normal force on the box is
- A. FN>mg.
- B. FN=mg.
- C. F_N < mg.
- D. FN=0.
- E. Not enough information to tell.
- Question 16: The top block is accelerated across a frictionless table by the falling mass m. The string is massless, and the pulley is both massless and frictionless. The tension in the string is
- A. FT<mg
- B. FT=mg
- C. F_T > mg
- Question 17: How are acceleration of Block A and Block B related?
- A. a<em>Ay=a</em>By
- B. −a<em>Ay=−a</em>By
- C. a<em>Ay=−a</em>By
- D. a<em>By=−a</em>Ay
- E. Either C or D.
- Question 18: A box is being pulled to the right over a rough surface. F<em>T>F</em>fs, so the box is speeding up. Suddenly the rope breaks. What happens? The box ___
- A. Stops immediately.
- B. Continues with the speed it had when the rope broke.
- C. Continues speeding up for a short while, then slows and stops.
- D. Keeps its speed for a short while, then slows and stops.
- E. Slows steadily until it stops.
- Question 19: A box on a rough surface is pulled by a horizontal rope with tension FT. The box is not moving. In this situation,
- A. F<em>fs=F</em>T
- B. F<em>fs<F</em>T
- C. F<em>fs>F</em>T
- D. Ffs=0
- Question 20: A box is being pulled to the right at steady speed on a rough surface by a rope that angles upward. In this situation:
- A. F_N > mg
- B. FN=mg
- C. FN<mg
- D. FN=0
- E. Not enough information to judge the size of the normal force.
- Question 21: A box with a weight of 100 N is at rest. It is then pulled by a 30 N horizontal force. Does the box move?
Alternative Notations
- Normal force:
- FN=N=normal force
- Gravitational force on an object:
- FG=weight(W)=mg
- Force of static friction:
- F<em>fs=f</em>s=ν<em>sF</em>N
- Force of kinetic friction:
- F<em>fk=f</em>k=ν<em>kF</em>N
Object on an Incline with Friction
- Is this system in equilibrium?
- Drawing the free bdy diagram:
- Define your coordinate system
- Represent the object of interest by a ’dot.’
- Identify all long-range forces.
- Identify all contact forces.
- Draw Force vectors showing the correct directions. Note: For each force vector start drawing the vector from the dot.
- Write down an expression for the net force on this person along the x-direction.
- Write down an expression for the net force on this person along the y-direction.
- Write down an expression for the acceleration of this person.
- Question: A 100 kg block is sitting on an incline plane whose angle of inclination is 10 degrees. Find:
- a) the parallel and perpendicular components of the force due to gravity.
- b) the normal force.
- c) the force of friction that keeps the block from sliding.
- Note: if the box is at rest or moving at constant velocity along a particular axis, net force is zero along that axis. If it is speeding up or slowing down, then net force is ma.
Summary
- All forces arise from interaction between objects.
- The type of force (gravity, friction, normal force, magnetic force etc) depend on the nature of the interaction and sometimes on the nature of the objects themselves.
- We learnt how to draw free body diagrams (diagram showing forces acting on a body) and how to denote different kinds of forces.