Two-Dimensional Figures, Transformations, and Three-Dimensional Solids

1-6: Two-Dimensional Figures and 10-2: Areas of Trapezoids

  • Application: Ella's Designer Handbags

    • Ella has turned her hobby of making designer handbags and totes into a small business.
    • Among her designs is a trapezoid-shaped handbag.
    • To estimate the amount of material needed to produce each handbag, she must calculate the area of a trapezoid.
  • Polygons and Classification

    • Classification Criteria: Polygons are classified by their number of sides, whether they are convex or concave, and whether they are regular or irregular.
    • Convex vs. Concave:
      • Convex: A polygon where no line segment between two points on the boundary ever goes outside the polygon.
      • Concave: A polygon that has at least one interior angle greater than 180180^{\circ}, effectively looking like a portion of the figure is "caved in."
    • Regular vs. Irregular:
      • Regular: A convex polygon that is both equilateral (all sides equal) and equiangular (all angles equal).
      • Irregular: A polygon that does not have all sides and all angles equal.
  • Key Geometric Formulas (Perimeter, Circumference, and Area)

    • Triangle:
      • Perimeter: P=a+b+c+dP = a + b + c + d (Note: usually a+b+ca+b+c for triangles, transcript uses four variables for general polygon perimeter).
      • Area: A=12bhA = \frac{1}{2}bh
      • Variables: bb is base, hh is height.
    • Square:
      • Perimeter: P=s+s+s+s=4sP = s + s + s + s = 4s
      • Area: A=s×s=s2A = s \times s = s^{2}
      • Variables: ss is side length.
    • Rectangle:
      • Perimeter: P=l+w+l+w=2l+2wP = l + w + l + w = 2l + 2w
      • Area: A=l×wA = l \times w
      • Variables: ll is length, ww is width.
    • Circle:
      • Circumference: C=2πrC = 2\pi r or C=πdC = \pi d
      • Area: A=πr2A = \pi r^{2}
      • Variables: rr is radius, dd is diameter.
    • Trapezoid:
      • Area: A=12h(b1+b2)A = \frac{1}{2}h(b_{1} + b_{2})
    • Calculation Note: The most accurate way to perform a calculation with pi is to use the π\pi symbol on a calculator. Use 3.143.14 as an estimate ONLY if a calculator is unavailable.
  • Practice Examples: Perimeter and Area

    • Mrs. Moore's Classroom Tape:
      • Goal: Use most or all of 19ft19\,ft of tape to mark an area.
      • Option A: Square with side length 5ft5\,ft. P=4(5)=20ftP = 4(5) = 20\,ft (Too much tape).
      • Option B: Circle with radius 3ft3\,ft. C=2π(3)18.85ftC = 2\pi(3) \approx 18.85\,ft (Best fit).
      • Option C: Right triangle with legs of 6ft6\,ft. P=6+6+62+62=12+8.48=20.48ftP = 6 + 6 + \sqrt{6^{2} + 6^{2}} = 12 + 8.48 = 20.48\,ft (Too much tape).
      • Option D: Rectangle with length 8ft8\,ft and width 3ft3\,ft. P=2(8)+2(3)=22ftP = 2(8) + 2(3) = 22\,ft (Too much tape).
    • Trapezoid Base Calculation:
      • Given: Area A=549cm2A = 549\,cm^{2}, height h=18cmh = 18\,cm, and base b2=35cmb_{2} = 35\,cm.
      • Formula: 549=12(18)(b1+35)549 = \frac{1}{2}(18)(b_{1} + 35).
      • Simplify: 549=9(b1+35)549 = 9(b_{1} + 35).
      • Divide by 99: 61=b1+3561 = b_{1} + 35.
      • Solve for b1b_{1}: b1=26cmb_{1} = 26\,cm.
    • Perimeter of Quadrilateral on Coordinate Plane:
      • Vertices: R(1,3)R(-1, 3), S(3,3)S(3, 3), T(5,1)T(5, -1), and U(2,1)U(-2, -1).
      • Length RS=3(1)=4RS = |3 - (-1)| = 4.
      • Length ST=(53)2+(13)2=22+(4)2=4+16=20ST = \sqrt{(5-3)^{2} + (-1-3)^{2}} = \sqrt{2^{2} + (-4)^{2}} = \sqrt{4 + 16} = \sqrt{20}.
      • Length UT=5(2)=7UT = |5 - (-2)| = 7.
      • Length RU=(2(1))2+(13)2=(1)2+(4)2=1+16=17RU = \sqrt{(-2 - (-1))^{2} + (-1 - 3)^{2}} = \sqrt{(-1)^{2} + (-4)^{2}} = \sqrt{1 + 16} = \sqrt{17}.
      • Perimeter: 4+7+20+1719.6units4 + 7 + \sqrt{20} + \sqrt{17} \approx 19.6\,units.

1-7: Transformations in the Plane

  • Application: Fashion Design Prints

    • Patterns are created by sliding (translation), flipping (reflection), or turning (rotation) figures.
  • Types of Rigid Transformations

    • Rigid Transformation: A transformation that preserves the size and shape of a figure, resulting in a congruent image.
    • Translation: Sliding a figure to a different location. It maintains the orientation of the figure.
    • Reflection: Flipping a figure over a line to create a mirror image.
    • Rotation: Turning a figure around a fixed point.
  • Coordinate Rules for Transformations

    • Reflection across x-axis: (a,b)(a,b)(a, b) \rightarrow (a, -b).
    • Reflection across y-axis: (a,b)(a,b)(a, b) \rightarrow (-a, b).
    • Translation: If translated along vector x,y\langle x, y \rangle, then (a,b)(a+x,b+y)(a, b) \rightarrow (a + x, b + y).
    • Rotations about the Origin:
      • 9090^{\circ} Rotation: (x,y)(y,x)(x, y) \rightarrow (-y, x).
      • 180180^{\circ} Rotation: (x,y)(x,y)(x, y) \rightarrow (-x, -y).
      • 270270^{\circ} Rotation: (x,y)(y,x)(x, y) \rightarrow (y, -x).
  • Practice Examples: Transformations

    • Reflection in x-axis: ΔPSR\Delta PSR with P(3,4),S(3,1),R(6,2)P(-3, 4), S(-3, -1), R(-6, 2) becomes P(3,4),S(3,1),R(6,2)P'(-3, -4), S'(-3, 1), R'(-6, -2).
    • Translation along Vector 1,2\langle -1, 2 \rangle: Parallelogram ABCDABCD with A(2,1),B(1,4),C(3,1),D(4,4)A(-2, 1), B(-1, 4), C(3, 1), D(4, 4) becomes A(3,3),B(2,6),C(2,3),D(3,6)A'(-3, 3), B'(-2, 6), C'(2, 3), D'(3, 6).
    • 180180^{\circ} Rotation: Quadrilateral ABCDABCD with A(4,2),B(3,3),C(2,1),D(1,0)A(-4, -2), B(-3, -3), C(-2, -1), D(-1, 0) becomes A(4,2),B(3,3),C(2,1),D(1,0)A'(4, 2), B'(3, 3), C'(2, 1), D'(1, 0).

1-8: Surface Area and Volume of Three-Dimensional Figures

  • Polyhedrons

    • Definition: A solid figure made up of flat surfaces (polygons) that enclose a region of space.
    • Examples: Prisms and Pyramids.
    • Non-Polyhedrons: Cylinders, Cones, and Spheres (contain curved surfaces).
    • Parts of a Polyhedron:
      • Face: A flat surface.
      • Edge: The line segment where two faces meet.
      • Vertex: The point where three or more edges intersect.
      • Base: The faces used to name the solid.
  • Surface Area (S or SA) Formulas

    • Prism: S=Ph+2BS = Ph + 2B
    • Pyramid: S=12Pl+BS = \frac{1}{2}Pl + B
    • Cylinder: S=Ch+2B=2πrh+2πr2S = Ch + 2B = 2\pi rh + 2\pi r^{2}
    • Cone: S=πrl+B=πrl+πr2S = \pi rl + B = \pi rl + \pi r^{2}
    • Sphere: S=4πr2S = 4\pi r^{2}
    • Hemisphere: S=12(4πr2)+πr2=3πr2S = \frac{1}{2}(4\pi r^{2}) + \pi r^{2} = 3\pi r^{2}
    • Variables:
      • BB: Area of the base.
      • PP: Perimeter of the base.
      • CC: Circumference of the base.
      • hh: Height of the solid.
      • ll: Slant height (distance from the vertex to the edge of the base along the surface curved/slanted side).
      • Watch Out: Height (hh) is the vertical distance to the base; slant height (ll) is different.
  • Volume (V) Formulas

    • Volume is measured in cubic units (units3units^{3}).
    • Prism: V=BhV = Bh
    • Cylinder: V=Bh=πr2hV = Bh = \pi r^{2}h
    • Pyramid: V=13BhV = \frac{1}{3}Bh
    • Cone: V=13Bh=13πr2hV = \frac{1}{3}Bh = \frac{1}{3}\pi r^{2}h
    • Sphere: V=43πr3V = \frac{4}{3}\pi r^{3}
    • Hemisphere: V=23πr3V = \frac{2}{3}\pi r^{3}
  • Specific Examples: Surface Area and Volume

    • Rectangular Prism: Base sides 8in8\,in and 12in12\,in, height 6in6\,in.
      • S=(40)(6)+2(96)=240+192=432in2S = (40)(6) + 2(96) = 240 + 192 = 432\,in^{2}.
      • V=(96)(6)=576in3V = (96)(6) = 576\,in^{3}.
    • Cylinder: Radius 4cm4\,cm, height 9cm9\,cm.
      • S=2π(4)(9)+2π(42)=72π+32π=104π326.73cm2S = 2\pi(4)(9) + 2\pi(4^{2}) = 72\pi + 32\pi = 104\pi \approx 326.73\,cm^{2}.
      • V=π(42)(9)=144π452.39cm3V = \pi(4^{2})(9) = 144\pi \approx 452.39\,cm^{3}.
    • Sphere: Radius 5ft5\,ft.
      • V=43π(53)=5003π523.6ft3V = \frac{4}{3}\pi(5^{3}) = \frac{500}{3}\pi \approx 523.6\,ft^{3}.
    • Hemisphere: Radius 10ft10\,ft.
      • Volume: V=23π(103)2094.4ft3V = \frac{2}{3}\pi(10^{3}) \approx 2094.4\,ft^{3}.
    • Cone (Icing Bag):
      • Diameter 3.5in3.5\,in (r=1.75inr = 1.75\,in), height 5in5\,in, slant height 5.3in5.3\,in.
      • Volume: V=13π(1.752)(5)16.0in3V = \frac{1}{3}\pi(1.75^{2})(5) \approx 16.0\,in^{3}.
      • Surface Area (no top): S=π(1.75)(5.3)29.1in2S = \pi(1.75)(5.3) \approx 29.1\,in^{2}.

Questions & Discussion

  • Q: What geometric figure comprises the sides of a polygon?

    • A: Line segments.
  • Q: How do you name a polygon?

    • A: Based on the number of sides of the polygon.
  • Q: What is the name for a convex polygon that is equilateral and equiangular?

    • A: A regular polygon.
  • Q: How do you label units for perimeter or circumference? Area?

    • A: Perimeter and circumference use linear units (e.g., ft,cmft, cm). Area uses square units (e.g., ft2,cm2ft^{2}, cm^{2}).
  • Q: Which transformation maintains the orientation of a figure?

    • A: Translation.
  • Q: Why do rigid transformations create congruent figures?

    • A: Because they do not change the shape or size of the original figure.
  • Q: Which three-dimensional solids are polyhedrons? Which are not?

    • A: Pyramids and prisms are polyhedrons. Spheres, cylinders, and cones are not polyhedrons.
  • Q: How do you label units for volume?

    • A: Volume is labeled with cubic units (e.g., ft3,cm3ft^{3}, cm^{3}).
  • Quiz Correction Logic for Vanesa's Banner:

    • The problem asks which shape uses most of 20sqft20\,sq\,ft of fabric.
    • Option C (r=2.5ftr = 2.5\,ft circle) gives A=π(2.52)=19.63ft2A = \pi(2.5^{2}) = 19.63\,ft^{2}, which is the closest value under 2020 without exceeding it.