NMR Spectroscopy Notes

NMR Spectrometer

  • The NMR spectrometer uses several components:
    • Radio frequency transmitter
    • Magnet with poles
    • Sweep coils
    • Sweep generator
    • Spinning sample tube
    • Radio frequency receiver and amplifier
    • Shimming components
    • Control console and recorder

Sensitivity of NMR Experiments

  • Sensitivity in NMR is quantified by the signal-to-noise ratio (S/N).
  • Several factors influence S/N:
    • N: Number of spins (concentration)
    • γ\gamma: Gyromagnetic ratio of detected nuclei
    • n: Number of scans
    • B: External magnetic field
  • Formula: S/NNγ3B3nS/N \propto N \gamma^3 B^3 \sqrt{n}
  • An example comparing a 750 MHz spectrometer with a 300 MHz spectrometer, illustrating the improvement in sensitivity with a higher magnetic field:
    • (750300)32=cN<em>1N</em>2(\frac{750}{300})^\frac{3}{2} = c \frac{N<em>1}{N</em>2}

NMR Sensitivity: Magnetic Field Strength

  • Increasing magnet strength (B0) is a major way to increase sensitivity.
  • Approximate costs:
    • ~$2,00,000
    • ~$4,500,000
  • Formula: S/NNγ3B3nS/N \propto N \gamma^3 B^3 \sqrt{n}

NMR Sensitivity: Concentration

  • Increasing the concentration of the sample is a common approach to increase sensitivity.
  • Example comparing two different concentrations on signal to noise ratio.
  • Formula: S/NNγ3B3nS/N \propto N \gamma^3 B^3 \sqrt{n}

NMR Sensitivity: Gyromagnetic Ratio and Natural Abundance

  • The gyromagnetic ratio (γ\gamma) and the natural abundance of the isotope significantly affect NMR sensitivity.
  • (γH/γC)3 for 13C is 64x
  • (γH/γN)3 for 15N is 1000x
  • 1H is approximately 64 times as sensitive as 13C and 1000 times as sensitive as 15N.
  • Considering the natural abundance:
    • 13C has a natural abundance of 1.1%.
    • 15N has a natural abundance of 0.37%.
    • Relative sensitivity increases to ~6,400x and ~2.7x105x, respectively.
  • 1H NMR spectra of caffeine (8 scans ~12 secs)
  • 13C NMR spectra of caffeine (8 scans ~12 secs)
  • 13C NMR spectra of caffeine (10,000 scans ~4.2 hours)
  • Formula: S/NNγ3B3nS/N \propto N \gamma^3 B^3 \sqrt{n}

NMR Sensitivity: Number of Scans

  • Increasing the number of scans (NS) or signal averaging is a common approach to increase sensitivity and signal-to-noise ratio (S/N).
  • S/NnS/N \approx \sqrt{n}
  • S/NNγ3B3nS/N \propto N \gamma^3 B^3 \sqrt{n}
  • The S/N increases with the square root of the number of scans.
  • Comparison of number of Scans and S/N:
    • n = 1, S/N = 1
    • n = 8, S/N = 2.83
    • n = 16, S/N = 4
    • n = 80, S/N = 8.94
    • n = 800, S/N = 28.3
  • Experimental Time = Number of Scans x Acquisition Time, so it takes significantly longer to acquire the spectrum as the number of scans increase.

Solvent Selection in NMR

  • The ideal solvent should:
    • Contain no protons
    • Be inert
    • Have a low boiling point
    • Be inexpensive
  • Deuterated solvents are necessary for modern NMR instruments:
    • Deuterium signal is used to lock or stabilize the B0 field of the magnet.
    • Instruments with a deuterium channel constantly monitor and adjust (locks) the B0 field to the frequency of the deuterated solvent.
    • The deuterium signal is also used to shim the B0 field, ensuring the homogeneity of the field is precise at the center of the sample.
  • Commonly used deuterated solvents: CDCl3, C6D6.

NMR Sample Preparation

  • Shows a picture of NMR Sample Preparation and a 500MHZ/52 MM setup.

NMR Spectra Analysis

  • This section details the analysis of an NMR spectrum.
  • Spectrum for ethylacetate.
  • Key parameters:
    • Experiment = zg.ppg
    • Pulse length = 22.00 usec
    • Recycle delay = 3.00 sec
    • Number of acquisitions (NA) = 8
    • Points (PTS1d) = 8192
    • F1 = 90.019463 MHZ
    • SW1 = 1470.60 Hz
    • AT1 = 5.57 sec
  1. Hz per Pt 1stD = 0.18 Hz
  2. 01 = 495.40
  3. LB1 = 0.00 Hz
  4. TP A = -75.50
  5. B
  6. -76.30
  • Peaks at:
    • 4.159 ppm
    • 4.079 ppm
    • 2.032 ppm
  • Spectrum includes signals for H3C and CH3 groups.

NMR: Spectrum Concepts

  • Key concepts in NMR spectrum analysis:
    • Shielding and deshielding
    • Chemical Shift (ppm)
    • Number of Signals
    • Integral of Signals
    • Coupling Constant (Hz)
    • Understanding Magnetic Anisotropy

Chemical Shift

  • Explains why hydrogen atoms have different frequencies.
  • ν=γ2πB0\nu = \frac{\gamma}{2 \pi} B_0
    • B0B_0 is 300, 400, or 600 MHz.

Chemical Shift: Shielding

  • Nuclei are surrounded by electrons, which generate a magnetic field that alters the B0 field in the microenvironment around the nucleus; this is called SHIELDING of the nucleus.
  • Shielding (σ) varies with chemical environments.
  • Electrons move to create an opposing field.
  • 1 T = 10 kG
  • For Naked Nuclei: ν=γ2πB0\nu = \frac{\gamma}{2 \pi} B_0
  • Effective magnetic field: B<em>eff=B</em>0σB<em>{eff} = B</em>0 - \sigma

Chemical Shift: Shielding (Continued)

  • At a constant applied magnetic field (B0), different protons experience different effective magnetic fields (Beff).
  • Electronic shielding σ is normally positive.
  • The shielding constant (σ) is closely related to the degree of electron density surrounding the nucleus.
  • Nuclei in regions of high electron density are shielded.
  • Conversely, nuclei in low electron density are deshielded.
  • Variation of the resonance frequency with shielding has been termed the Chemical Shift.
  • Example calculation:
    • νeff=299.999994 MHz\nu_{eff} = 299.999994 \ MHz
    • ν=γ2πBeff=300 MHz\nu = \frac{\gamma}{2 \pi} B_{eff} = 300 \ MHz
    • Δν=6.0 Hz\Delta \nu = 6.0 \ Hz
    • Δν=γ2πσB0\Delta \nu = \frac{\gamma}{2 \pi} \sigma B_0

Chemical Shift: ppm (parts per million)

  • The basic frequency of the pulse (B1) is not the same as the sample resonance.
  • The observed FID (Free Induction Decay) is the difference of two frequencies: the B1 (radiofrequency, known) and the frequency emitted by excited nuclei.
  • These differences in resonance frequency are very small (Hz) compared with B1 (MHz).
  • The unit of chemical shift is ppm (parts per million).
  • No attempt is made to measure the exact resonance frequency of any proton.
  • Different machines have different real chemical shifts (ppm).
  • A standard reference is used: tetramethylsilane (TMS, Me4Si).
  • The chemical shift δ expresses the amount by which a proton resonance is shifted from TMS, in parts per million, of the spectrometer’s basic operating frequency.
  • It is a field-independent measure.
  • Variation of the resonance frequency with shielding has been termed the Chemical Shift.
  • Formulas:
    • FID:ν<em>real=ν</em>sampleνpulseFID: \nu<em>{real} = \nu</em>{sample} - \nu_{pulse}
    • Δδ=δ<em>sampleδ</em>TMS=ν<em>sampleν</em>TMSνpulse\Delta \delta = \delta<em>{sample} - \delta</em>{TMS} = \frac{\nu<em>{sample} - \nu</em>{TMS}}{\nu_{pulse}}
    • δ=Δννpulse=ppm\delta = \frac{\Delta \nu}{\nu_{pulse}} = ppm
    • δ=νrealxMHz=HzMHz\delta = \frac{\nu_{real}}{xMHz} = \frac{Hz}{MHz}
    • Example: δ=162Hz60MHz=2.70ppm\delta = \frac{162 Hz}{60 MHz} = 2.70 ppm

Hz vs ppm

  • The chemical shift in ppm is independent of the strength of the applied magnetic field.
  • Formula: ν=δx Hz\nu = \delta * x \ Hz
  • Example: for a 400 MHz machine with δ = 2.0 ppm, ν=2.0400 Hz=800 Hz\nu = 2.0 * 400 \ Hz = 800 \ Hz
  • Formulas:
    • δ=ν<em>Hzx</em>MHz\delta = \frac{\nu<em>{Hz}}{x</em>{MHz}}
    • ν=δ<em>ppmx</em>MHz=δ106x106Hz=δx Hz\nu = \delta<em>{ppm} * x</em>{MHz} = \delta * 10^{-6} * x * 10^6 Hz = \delta * x \ Hz
    • δ=ν<em>sampleν</em>TMSxMHz\delta = \frac{\nu<em>{sample} - \nu</em>{TMS}}{xMHz}

Chemical Shift unit: ppm vs Hz

  • ν=δx Hz\nu = \delta * x \ Hz
  • The same chemical shift (e.g., 2.032 ppm) in ppm will have a different frequency under different magnetic fields.
  • Stronger magnetic field, higher chemical shift in Hertz.
  • Examples:
    • B0 = 90 MHz: ν=2.03290 Hz=182.88 Hz\nu = 2.032 * 90 \ Hz = 182.88 \ Hz
    • B0 = 400 MHz: ν=2.032400 Hz=812.8 Hz\nu = 2.032 * 400 \ Hz = 812.8 \ Hz

Effect of Changing Field Strength

  • The strongest Magnetic field available should be used to spread out the chemical shifts.
  • ν=δx Hz\nu = \delta * x \ Hz

Range of Chemical Shifts (δ)

  • Different nuclei have different shift ranges, depending on γ.
  • Nucleus Shift Range (ppm) Reference
    • 1H -30 to 20 (commonly 0-12) (CH3)4Si
    • 13C -100 to 200 (commonly 0-220) (CH3)4Si
    • 19F -200 to 200 CFCl3
    • 31P -100 to 250 H3PO4
  • Δν=γ2πσB0\Delta \nu = \frac{\gamma}{2 \pi} \sigma B_0

Downfield and Upfield

  • Downfield: Deshielded nuclei. Higher frequency. Larger effective magnetic field.
  • Upfield: Shielded nuclei. Lower frequency. Smaller effective magnetic field.

Protons in a molecule

  • More shielded protons absorb at a higher field (upfield).
  • Less shielded protons absorb at a lower field (downfield).
  • Examples include H-C-O and H-O-C-H.

Proton NMR Chemical Shifts of Common Functional Groups & Factors

  • Electronegativity
  • Anisotropy (Ring Currents)
  • Electron Delocalization
  • H‐Bonding

Proton NMR Chemical Shifts of Common Functional Groups

  • Ranges of chemical shifts for different types of protons:
    • OH : 12 - 1
    • Y-C-H: F, etc 4 - 2
    • C=O -C-H: 10 - 9
    • C-H: 5 - 0
  • Regions:
    • Deshielded, High Frequency, High Chemical Shift, Downfield
    • Shielded, low Frequency, Low Chemical Shift, Upfield
    • H-Bonding
    • anisotropy
    • Electronegativity

Factors on Chemical Shift: Electron density

  • Electronegativity
  • Anisotropy (π-bond)
  • Electron Delocalization
  • H-Bonding

Deshielding by Electronegative Element

  • Chlorine “deshields” the proton by taking valence electron density away from carbon, which in turn takes more density from hydrogen.
  • “highly shielded” protons appear at upfield (lower δ).
  • “deshielded“ protons appear at downfield (higher δ).
  • deshielding moves proton resonance to lower field and higher δ.
  • Cδ+HδClδC^{\delta+} - H^{\delta-} Cl^{\delta-}

Deshielding by Electronegative Element examples

  • The effect increases with greater numbers of electronegative atoms:
    • CHCl3: 7.27 ppm
    • CH2Cl2: 5.30 ppm
    • CH3Cl: 3.05 ppm
  • The effect decreases with increasing distance from the electronegative atom:
    • −CH2−Br: 3.30 ppm
    • −CH2−CH2−Br: 1.69 ppm
    • − CH2−CH2−CH2−Br: 1.25 ppm
  • The effect completely vanishes at the fourth bond from the electronegative atom.

Proton NMR Chemical Shifts of Common Functional Groups (slide 2)

  • Common Functional Groups Examples

Unexpected Shielding

  • H-C-OR
  • | C=C
    H 5.5 ppm
  • H-C=CR.
  • 2.0 ppm

Diamagnetic Anisotropic effect DUE TO THE PRESENCE OF -BONDS

  • The presence of a nearby pi bond or pi system greatly affects the chemical shift.
  • Induced magnetic fields due to the  - electrons have greatest effect.

Diamagnetic Anisotropy

  • Shielding and deshielding depend on the orientation of the molecule with respect to the applied magnetic field.
  • Electron density of chemical bonds could be higher in one direction than another: anisotropic
  • Nuclei in close proximity of these bonds could be affected
  • Most pronounced in delocalised π‐ systems
  • For example H-C≡C-H Shielding of alkyne protons Shielded δ = 2.5 ppm shielded

Diamagnetic Anisotropy: Aldehyde δ = 9-10 ppm

  • Shielding and deshielding depend on the orientation of the molecule with respect to the applied magnetic field.
  • Deshielding of aldehyde protons
  • The effect of B0 is greatest along the transverse axis of the C=O.

Diamagnetic Anisotropy: Aldehyde spectrum

  • Displays a spectrum of benzaldehyde, showing a peak at 9.984 ppm for the aldehyde proton.

Diamagnetic Anisotropy: Alkene δ = 5-6 ppm

  • The induced field reinforces the external field (deshielding).
  • Shows the anisotropic effect in alkenes.

Diamagnetic Anisotropy: Alkene examples

  • Examples:
    • H/δ = 5-6 ppm
    • 8 = 2.2 ppm
    • C
    • 8 = 2.2 ppm H

Diamagnetic Anisotropy: Alkene values

  • Shows chemical shift values of miscellaneous Alkenes

Diamagnetic Anisotropy: Ketone δ = 2-2.5 ppm

  • Examples for methyl, methylene groups.

Diamagnetic Anisotropy: Ketone explanation

  • The magnetic anisotropy of C=O has a strongly deshielding (+δ) region in the plane of the carbonyl group.

Diamagnetic Anisotropy: π-bond shielding

  • Chemical shifts values and deshielding.

Proton NMR Chemical Shifts of Common Functional Groups (slide 3)

  • Chemical shifts values and deshielding.

Diamagnetic Anisotropy: Aromatic

  • Protons on the benzene ring are deshielded.
  • Benzene ring contains delocalized -electrons
  • Deshielded δ = 7-8 ppm.

Diamagnetic Anisotropy: Aromatic example

  • Displays a spectrum of styrene, showing signals in the aromatic region (7-8 ppm) and alkene region (5-6 ppm).

Examples of Ring-Current Effect

  • Shows multiple examples of ring-current effects on chemical shifts in various aromatic compounds, with specific chemical shift values listed for different protons.

Reinforced double Diamagnetic Anisotropy

  • All the ring protons of acetophenone are deshielded because of the ring current effect.
  • The ortho protons are further deshielded.

Reinforced double Diamagnetic Anisotropy - Spectra

  • Spectra of 4'-Methylacetophenone
  • Spectra of 4-Methoxybenzaldehyde illustrating reinforced double diamagnetic anisotropy.

Reinforced double Diamagnetic Anisotropy- Spectra values

  • Spectra values of 4'-Methylacetophenone

How Do Ring Currents Affect 1H NMR Chemical Shifts?

  • Abstract explaining the downfield ¹H of benzene is not due to deshielding ring current effects.

How Do Ring Currents Affect 1H NMR Chemical Shifts? continued

  • Conventional explanations of proton NMR chemical shifts need fundamental revisions: arene hydrogens are NOT deshielded by ring current effects.

Proton NMR Chemical Shifts of Common Functional Groups (slide 4)

  • Review of chemical shifts values.

Unexpected Deshielding

  • Cyclohexane
  • values of axial vs equatorial protons

σ-Bond Diamagnetic Anisotropy

  • In general, an axial protons are more shielded and resonate at lower frequency than equatorial protons, typically by about 0.5 ppm.
  • shielded =0.1-0.7 ppm

Electron delocalization

  • There are 'activating' and 'deactivating' groups that can redistribute electron densities through delocalized orbitals.

Hetero-aromatic compounds

  • Explain the difference in the chemical shift of a furan

Heteroaromatic compounds

  • Explain the difference in the chemical shift of a pyridine

Unexpected Activated Proton

  • Ethanol
  • CH3CH2OH Spectrum

Hydrogen Bonding

  • Hydrogen bonds deshield a proton signal
  • The position of OH and NH signals are unpredictable, as they are dependent on the amount of hydrogen bonding 10-12ppm (Why?)

Hydrogen Bonding Spectra Example

  • Hydrogen Bonding Spectra with specific chemical shift values labeled.

Hydrogen Bonding Example

  • Hydrogen Bonding Values

Proton NMR Chemical Shifts of Common Functional Groups(slide 5)

  • An overview of proton NMR chemical shifts and functional groups.

Chemical Shift of Common Functional Groups

  • Overview of Common Functional Groups

Estimation of Chemical Shift

  • Appreciation of the concepts of
    • Electronegativity (Inductive Effects)
    • Electron Delocalization (Resonance Effects)
    • Diamagnetic anisotropy
  • Permits both rationalization and prediction of Chemical Shift.
  • Software: Chemdraw i) Draw the structure, ii) select it, iii) click iv) Click

CHEMDRAW Estimation of Chemical Shift Protocol

  • Node Shift Base + Inc. Comment (ppm rel. to TMS)

Estimation of Chemical Shift—Shoolery’s Rule for CH2

  • δ = 0.23 + σY + σZ
  • For Example: PhCH2Br δ = 0.23 + 1.83 + 2.33 = 4.41 Found δ 4.43
  • For Example: HCH2Br δ = 0.23 + 0.34 + 2.33 = 2.90 Found δ 2.69

Estimation of Chemical Shift—Shoolery’s Rule for CH

  • δ = 2.5 + σX + σY + σZ
  • For Example: MeCH(OEt)2 δ = 2.5 + 0 + 1.14 + 1.14 = 4.78 Found δ 4.72
  • Two substituents are EWG, only one alkyl.

Estimation of Chemical Shift—Friedrich-Runkle Relationship

  • δ = δ(Me2CHZ) + xy
  • Substitution of methyl plus correction factors If two substituents are alkyl groups, then correction is needed!!

Estimation of Chemical Shift—Friedrich-Runkle Relationship example

  • δ = δ(Me2CHZ) + xy So, xy = 0.4 for vinyl δ = 2.89 + 0.4 = 3.29 Found: δ = 3.44 Table B.2b δ = 2.89

APPENDIX C CHEMICAL SHIFTS IN ALICYCLIC AND HETEROCYCLIC RINGS

  • Tables and values for chemical shifts in alicyclic and heterocyclic rings.

APPENDIX D AND Estimation of Chemical Shift— Tobey-Pascual-Meier-Simon

  • δ = 5.25 + Zgem + Zcis+ Ztrans

Estimation of Chemical Shift— Tobey-Pascual-Meier-Simon example

  • Trans: δ(HA) = 5.25 + 0.44 + 0.97 + 0 = 6.66 δ(HB) = 5.25 + 1.03 + (-0.26)+ 0 = 6.02
  • Cis: δ(HA) = 5.25 + 0.44 + 0 +1.21 = 6.90 δ(HB) = 5.25 + 1.03 + 0 + (-0.29) = 5.99
  • Observed: δ 6.87 & 6.03
  • Calculated:

Try to assign the signals

  • Example for assignments.

Try to assign the signals (slide 2)

  • Example for assignments for CH=CHCHO

Try to assign the signals (slide 3)

  • 10 9 8 7 6 5 4 3 210 6.00
  • Нь C=C C-OCH3
  • +ab 5 6.28 5.72