(294) Graphs of Rational Functions | 5.1 - 5.2 Rational Functions and Graphs

Rational Function Analysis

Example 1: ( f(x) = (\frac{x + 1}{x^2 - 4}) )

Problem Type: Find vertical asymptotes, intercepts, and graph behavior.

Factoring:

  • Numerator: The numerator (x + 1) cannot be factored further; it remains as ((x + 1)).

  • Denominator: The denominator (x^2 - 4) can be factored using the difference of squares into ((x + 2)(x - 2)).

Conclusion: Since there are no common factors, there are no holes in the graph.

Vertical Asymptotes

Determine Vertical Asymptotes:

  • Set the denominator to zero:[(x + 2)(x - 2) = 0]

  • This gives roots of (x = -2) and (x = 2).

  • Therefore, vertical lines are drawn at (x = -2) and (x = 2).

  • The graph is split into three separate pieces due to the two vertical asymptotes.

End Behavior Asymptote

Degree Comparison:

  • The degree of the numerator is 1 and the degree of the denominator is 2.

  • Result: There is a horizontal asymptote at (y = 0) (the x-axis).

Finding Intercepts

X-Intercept:

  • Set the numerator to zero: (x + 1 = 0) results in (x = -1).

  • Therefore, the x-intercept is at the point ((-1, 0)).

Y-Intercept:

  • Plug in (x = 0):[f(0) = \frac{1}{-4} = -\frac{1}{4}]

  • The y-intercept is at the point ((0, -\frac{1}{4})).

Graphing Steps

Plot Asymptotes and Intercepts:

  • Vertical Asymptotes: Dashed lines are drawn at (x = -2) and (x = 2).

  • Horizontal Asymptote: A line is drawn at (y = 0).

  • Plot the x-intercept at ((-1, 0)) and the y-intercept at ((0, -\frac{1}{4})).

Analyzing Graph Behavior

Left of (-2):

  • Evaluate points less than (-2) (e.g., plug in (x = -3)): This yields a negative result, indicating the graph is below the x-axis.

Between (-2) and (-1):

  • Evaluate points between these x-values to check behavior.

  • Example: plug in (x = -1.5): results show the graph rises after crossing the x-axis.

Right of (2):

  • Perform a similar evaluation to determine if the graph is above or below the x-axis by substituting a point greater than 2.


Example 2: ( g(x) = (\frac{3x - 4}{2x + 1}) )

Problem Type: Analyze vertical asymptote, intercepts, and relation to horizontal asymptote.

Factoring:

  • These expressions cannot be factored further; both the numerator and denominator are prime.

Vertical Asymptote

Determine Vertical Asymptotes:

  • Set the denominator to zero: (2x + 1 = 0) yields (x = -\frac{1}{2}).

  • This creates two distinct pieces of the graph based on the asymptote.

End Behavior Asymptote

Degree Comparison:

  • The degrees of both the numerator and the denominator are equal (1). Therefore, there is a horizontal asymptote at (y = \frac{3}{2}).

Finding Intercepts

X-Intercept:

  • From the numerator, set (3x - 4 = 0) which yields (x = \frac{4}{3}).

Y-Intercept:

  • Plug (x = 0) into the function results in the point ((0, -4)).

Crossing Asymptote

  • To check for contradictions, set the function equal to the asymptote (y = \frac{3}{2}) and solve for any possible conflicts.


Example 3: ( h(x) = (\frac{x^2 - 1}{x - 3}) )

Problem Type: Identify vertical asymptotes and analyze the effect of degree differences on behavior.

Factoring:

  • The numerator can be factored as a difference of squares: (x^2 - 1 = (x - 1)(x + 1)).

Vertical Asymptote

Determine Vertical Asymptotes:

  • Solve (x - 3 = 0) giving (x = 3).

End Behavior

Degree Comparison:

  • Since the degree of the numerator is higher than that of the denominator, note that there is a slant asymptote rather than a horizontal one.

Finding Intercepts

X-Intercepts:

  • Find x-intercepts by solving both factors ((x - 1)(x + 1) = 0) giving (x = 1) and (x = -1).

Y-Intercept:

  • Evaluate the function at zero to find (h(0) = \frac{-1}{-3} = \frac{1}{3}) yielding the y-intercept at ((0, \frac{1}{3})).


Example 4: ( p(x) = (\frac{2}{x^2 + 3}) )

Problem Type: Establish absence of vertical asymptotes and analyze graph behavior.

Factoring:

  • No vertical asymptotes exist since the denominator produces complex solutions.

End Behavior

End Behavior Asymptote:

  • The horizontal asymptote is at (y = 0) as the degree of the denominator exceeds that of the numerator.

Finding Intercepts

X-Intercepts:

  • There are no x-intercepts as the function never crosses the x-axis.

Y-Intercept:

  • The y-intercept is determined at ((0, \frac{2}{3})).

Graph Behavior

Graph Behavior:

  • As the graph approaches the x-axis, it creates a 'hump' shape, reflecting the absence of any vertical asymptotes while moving towards the horizontal asymptote at (y = 0).

Steps in Rational Function Analysis

  1. Factoring: Factor the numerator and denominator if possible. Look for common factors to identify any holes in the graph.

  2. Determine Vertical Asymptotes: Set the denominator to zero and solve for x to find the vertical asymptotes.

  3. End Behavior Asymptote: Compare the degrees of the numerator and denominator to find any horizontal or slant asymptotes.

  4. Finding Intercepts:

    • X-Intercept: Set the numerator to zero and solve for x.

    • Y-Intercept: Plug in x = 0 into the function and calculate the output.

  5. Graphing Steps: Plot the asymptotes and intercepts on a graph.

  6. Analyzing Graph Behavior: Evaluate the function at points to determine behavior in the intervals created by vertical asymptotes and intercepts.

Finding Horizontal or Oblique Asymptotes

  1. Horizontal Asymptotes:

    • Compare the degrees of the numerator (N) and the denominator (D):

      • If N < D: The horizontal asymptote is at y = 0 (the x-axis).

      • If N = D: The horizontal asymptote is at y = a/b, where a is the leading coefficient of the numerator and b is the leading coefficient of the denominator.

      • If N > D: There is no horizontal asymptote, but there may be an oblique asymptote.

  2. Oblique Asymptotes (also known as slant asymptotes):

    • Occur when the degree of the numerator is exactly one greater than the degree of the denominator (N = D + 1).

    • To find the oblique asymptote, perform polynomial long division of the numerator by the denominator. The quotient (ignoring the remainder) gives the equation of the oblique asymptote.