Domain and Range

  • domain of f(x) - set of allowable inputs (usually x)

  • range of f(x) - set of possible outputs (usually y)

    • f(x) = √x+1

      • domain is what x can be, from a starting number to an end number

      • range is what f(x) can be, from a starting number to an end number

        • x+1 ≠ -y, so x has to be greater than or equal to -1 (bcs -1 + 1 = 0)

        • this means the domain is [-1, ∞)

        • the √x of 0 = 0, so f(x) must be greater than or equal to 0

        • this means the range is [0, ∞)

  • x/0 = undefined

  • √-x = undefined

  • () = endpoint is not included in set

    • (0,5) = all numbers from 0-5, but not including 0 or 5

    • infinity signs (-∞,∞) always use parentheses

    • on a graph, () is represented with an OPEN dot

  • [] = endpoint is included in set

    • (0,5) = all numbers from 0-5, including 0 and 5

    • on a graph, [] is represented with a CLOSED dot

  • (x, ∞) = all numbers greater than x;

  • (-∞, x) = all numbers less than x

  • (-∞,∞) - all real numbers

domain limitations

(0,∞) - starts and includes 0, goes on for infinity

(-∞, 0) - starts and includes negative infinity numbers, ends at 0

  • f(x) = x²; domain (-∞,∞) , range (0,∞)

  • f(x) = √x; domain (0,∞), range (0,∞)

  • f(x) = log(x); domain (0,∞), (-∞,∞)

  • f(x) = ax; domain (-∞,∞), range (0,∞)

  • f(x) = 1/x; domain and range (-∞, 0) ∪ (0,∞)

  • polynomials = domain (-∞,∞) all real numbers

  • absolute value = domain (-∞,∞) all real numbers

  • integers - whole numbers (positive, negative, zero)

  • real numbers - all numbers (integers, fractions, decimals etc)

denominator can’t be 0 bcs it’s undefined

0² / (0² - 1) (0-3)

0 / (-1)(-3)

0/3; 0 is included in domain

3² / (3² - 1) (3-3)

9 / (8)(0)

9/0 = undefined; 3 is not included in domain

answer is x ≠ -1, 1, 3

can’t be log 0 bcs its undefined

log2( |3-3| )

log2( |0| )

log20 = undefined; 3 is not included in domain

answer is x = 3

the range (y) can’t have a repeating output

f(x) = x4 + 1

f(-2) = 17

f(-1) = 2

f(0) = 1

f(1) = 2

f(-2) = 17

the range has multiple repeating outputs, so it doesn’t have a well defined inverse

answer is f(x) = x4 + 1