Simplification of Algebraic Expressions

Algebraic Expression and Polynomial Simplification

The provided expression is an algebraic problem from Page 1, labeled as item (b), which requires the simplification of a polynomial expression: 3x(2x+3)x(3x+5)3x(2x+3)-x(3x+5). This mathematical statement consists of two distinct products of monomials and binomials, separated by a subtraction operator. To simplify this expression, one must apply the distributive property to eliminate the parentheses and then combine like terms to achieve the most concise form of the polynomial.

Expansion via the Distributive Property

The first step in resolving the expression 3x(2x+3)x(3x+5)3x(2x+3)-x(3x+5) is to apply the distributive property, which is a fundamental algebraic principle defined by the formula a(b+c)=ab+aca(b + c) = ab + ac. This requires multiplying the term outside the parentheses to every term located within the parentheses.

For the first part of the expression, 3x(2x+3)3x(2x+3), the monomial 3x3x is distributed. First, we calculate the product of 3x3x and 2x2x. Multiplying the coefficients 33 and 22 results in 66, while multiplying the variables xx and xx (by adding their exponents according to the product rule xa×xb=xa+bx^a \times x^b = x^{a+b}) results in x2x^{2}. Thus, the first product is 6x26x^{2}. Next, we multiply 3x3x by the constant 33. Multiplying the coefficient 33 by the constant 33 gives 99, and the variable xx is retained, resulting in 9x9x. The fully expanded form of the first section is 6x2+9x6x^{2} + 9x.

Managing Negatives in Algebraic Distribution

The second part of the expression is x(3x+5)-x(3x+5). It is crucial in algebra to treat the subtraction sign preceding the variable as a negative sign attached to that variable (essentially 1x-1x). This negative monomial must be distributed across the binomial (3x+5)(3x+5).

When distributing x-x to the term 3x3x, we multiply 1-1 by 33 to get 3-3, and xx by xx to get x2x^{2}, resulting in the term 3x2-3x^{2}. Following this, we distribute x-x to the constant +5+5. Multiplying a negative by a positive yields a negative value: 1×5=5-1 \times 5 = -5, and the variable xx is appended, resulting in 5x-5x. Combining these results, the expansion of the second part of the original expression is 3x25x-3x^{2} - 5x.

Final Simplification through Combining Like Terms

After completing the distribution for both parts of the expression, we are left with the expanded polynomial string: 6x2+9x3x25x6x^{2} + 9x - 3x^{2} - 5x. To simplify this further, we must identify and combine "like terms," which are terms that share identical variable bases raised to the same powers.

The quadratic terms in this expression are those containing x2x^{2}. We group 6x26x^{2} and 3x2-3x^{2}. By performing the subtraction of the coefficients, we get (63)x2(6-3)x^{2}, which simplifies to 3x23x^{2}.

The linear terms in this expression are those containing the variable xx to the power of 1. We group +9x+9x and 5x-5x. By subtracting the coefficients, we get (95)x(9-5)x, which simplifies to 4x4x.

Concatenating these Two simplified parts yields the final, irreducible form of the expression: 3x2+4x3x^{2} + 4x.