CH 5: Principle of Chemcial Reactivity

Chemistry and Chemical Reactivity: Principles of Chemical Reactivity: Energy and Chemical Reactions

Overview

  • Focus on energy changes associated with physical changes and chemical reactions.
  • Key questions raised include:
    • How to measure and calculate energy changes?
    • Relationship between energy changes, heat, and work.
    • Determining product-favored vs reactant-favored chemical reactions at equilibrium (Chapter 18).
    • Identifying spontaneous chemical reactions or physical changes.

Types of Energy

  • Energy: Capacity to do work.
    • Kinetic Energy (KE): Associated with motion.
    • Formula: KE = rac{1}{2}mv^2
    • Types: Thermal (motion of particles), mechanical (moving objects), electrical (electron movement).
    • Potential Energy: Associated with position.
    • Types: Gravitational, electrostatic, chemical energy associated with chemical bonds.

Law of Conservation of Energy

  • Energy cannot be created or destroyed.
  • Total energy of an isolated system remains constant. Mathematically presented as: ΔU=q+w\Delta U = q + w
    • Where:
    • ΔU\Delta U: Change in internal energy.
    • qq: Heat exchanged.
    • ww: Work done.
Molecular Level
  • Thermal Energy: Kinetic energy of molecules; related to heat transfer between objects at different temperatures.
  • Chemical Energy: Potential energy linked to the arrangement and bonds of atoms and molecules.

Heat

  • Heat: Transfer of thermal energy from a hotter object to a colder one.
    • Heat flows from objects with higher average kinetic energy to those with lower.
    • Symbol for heat: qq.

Systems and Surroundings

  • System: Part of the universe under study (e.g., contents of a beaker).
    • Types:
    • Open System: Exchanges matter and energy with surroundings.
    • Closed System: Exchanges energy, but not matter.
    • Isolated System: Exchanges neither matter nor energy.
  • Surroundings: Everything outside the system.

Energy Transfer

Energy Changes
  • ΔU=q+w\Delta U = q + w
  • Endothermic Process: System absorbs heat; q > 0.
  • Exothermic Process: System releases heat; q < 0.
Energy Units
  • Joules (J): Official SI unit for energy.
  • Calories:
    • 1 Cal = 1000 cal (1 kcal).
    • 1 cal = 4.184 J (exact).
Concept Check
  • Convert 3.75×1033.75 \times 10^3 calories into Joules:
    • 3.75×103 cal×4.184 J/cal=15665 J3.75 \times 10^3 \text{ cal} \times 4.184 \text{ J/cal} = 15665 \text{ J}.

Heat Capacity

  • Heat Capacity: Amount of heat required to raise the temperature of an object by 1 K (1 °C).
    • Formula: q=Cobject×ΔTq = C_{object} \times \Delta T
  • Where:
    • qq: Energy gained or lost as heat.
    • CobjectC_{object}: Heat capacity of an object (J/K).
    • ΔT\Delta T: Change in temperature.
  • Extensive Properties: Depend on material quantity (e.g., mass, volume).
  • Intensive Properties: Independent of amount (e.g., density, specific heat capacity).

Specific Heat Capacity

  • Quantity of heat required to raise 1 gram of substance by 1 K (or °C).
  • Formula: q=C×m×ΔTq = C \times m \times \Delta T
    • Where:
    • CC: Specific heat capacity (J/K/g).
    • mm: Mass.
Example Calculation of Specific Heat Capacity
  • For water: Cwater=4.184J/g/KC_{water} = 4.184 \, \text{J/g/K}.
  • Example: Heating 50 g of water from 25.3 °C to 33.7 °C.
    • ΔT=33.725.3=8.4K\Delta T = 33.7 - 25.3 = 8.4 \, K
    • Calculate heat transfer: q=4.184J/g/K×50g×8.4K=1757.3Jq = 4.184 \, \text{J/g/K} \times 50 \, \text{g} \times 8.4 \, K = 1757.3 \, J
Quantitative Aspects of Heat Transfer
  • Energy transfers spontaneously from hotter to colder objects until thermal equilibrium is reached.
  • Thermal Equilibrium: No net transfer of heat between objects.
Law of Conservation of Energy in Systems
  • In an isolated system, the sum of energy changes is zero.

Calorimetry and Energy Transfer

Example Problem in Calorimetry
  • A 145 g sample of copper at 100.0 °C placed in 250.0 g of water at 25.0 °C, reaching thermal equilibrium at 28.8 °C.
  • Calculate the specific heat capacity of copper:
    • q<em>Cu+q</em>H2O=0q<em>{Cu} + q</em>{H2O} = 0
    • Use:
      m<em>Cu×C</em>Cu×(T<em>fT</em>i)+m<em>H2O×C</em>H2O×(T<em>fT</em>i)=0m<em>{Cu} \times C</em>{Cu} \times (T<em>f - T</em>i) + m<em>{H2O} \times C</em>{H2O} \times (T<em>f - T</em>i) = 0.

First Law of Thermodynamics

  • Based on conservation of energy:
    • Internal energy change: ΔU=q+w\Delta U = q + w
  • Implications for endothermic and exothermic processes:
    • Positive Heat Transfer: Energy absorbed; increases internal energy.
    • Negative Heat Transfer: Energy released; decreases internal energy.
Enthalpy
  • Enthalpy (H): Defined as H=U+PVH = U + PV
  • Change in enthalpy (ΔH): ΔH=H<em>finalH</em>initial\Delta H = H<em>{final} - H</em>{initial}
  • At constant pressure, ΔH=qp\Delta H = q_p.
Thermochemical Equations
  • Example reactions with enthalpy changes:
    • C(s)+O<em>2(g)CO</em>2(g)(ΔH=393.5kJ/mol)C(s) + O<em>2(g) → CO</em>2(g) \, (\Delta H = -393.5 \, kJ/mol).
Example Problem for Hess’s Law
  • Determine energy changes for reactions using known enthalpy values by manipulation of stoichiometric equations.
    • Energy change for combustion of glucose:
      C<em>6H</em>12O<em>6(s)+6O</em>2(g)6CO<em>2(g)+6H</em>2O(l)(answer=2801kJ)C<em>6H</em>{12}O<em>6(s) + 6 O</em>2(g) → 6 CO<em>2(g) + 6 H</em>2O(l) \, (answer = -2801 \, kJ).
  • Standard enthalpy of formation (ΔfH°) defined at standard conditions,
    • Values indicate the stability of compounds under formation from elements.
Product vs Reactant Favored Reactions
  • Product-favored reactions generally have negative ΔH°rxn.
  • Reactant-favored reactions generally possess positive ΔH°rxn.

Note: This document is a fully detailed study guide based on the principles of chemical reactivity regarding energy changes, heat transfer, heat capacity, calorimetry, and thermochemistry.