Polarity of Molecules – Comprehensive Study Notes

Required Documents

  • Posted on the module’s Learning Activities page:

    • Periodic Table (reference for atomic symbols & electronegativity values).

    • Electronegativity Values chart (needed for ΔEN|\Delta EN| calculations).

    • “Summary: Geometry and Polarity for Molecules and Polyatomic Ions”

    • Condenses information from this and the previous presentation.

    • “Geometry and Polarity – Practice Worksheet”

    • Step-by-step framework for all polarity-determination steps.

    • Mirrors the worksheet used in the Molecular Geometry experiment; useful for extra practice.

Context & Scope

  • Unit 5 – Part 5 of CHE 111 (Atoms First) textbook, Section 4.6.

  • Created by Dr. Lynn Tracey, last updated 15 Aug 2023.

  • Goal of this lecture: learn to classify molecules (NOT polyatomic ions) as polar or nonpolar.

    • Polyatomic ions possess an overall formal charge that dominates their behaviour, so polarity analysis is unnecessary for them.

  • Importance: Molecular polarity governs many physical/chemical properties (e.g., solubility, boiling point, intermolecular forces). Details explored in later units.

Fundamental Definitions

  • Polar molecule

    • Possesses an overall dipole moment: one end is partially positive (δ+) and the other partially negative (δ-).

  • Nonpolar molecule

    • Exhibits no overall dipole moment; charge distribution is symmetric.

  • Electronegativity (EN)

    • A calculated, dimensionless value indicating how strongly an atom attracts shared electrons in a covalent bond.

    • Difference in EN between two atoms is expressed as ΔEN|\Delta EN| (absolute value).

    • Larger ΔEN|\Delta EN| → more polar bond (greater electron-pulling disparity).

    • Course convention:

      • Polar covalent bond if ΔEN0.5|\Delta EN| \ge 0.5.

      • Nonpolar covalent bond if |\Delta EN| < 0.5.

Bond Dipoles

  • Every polar bond behaves as a tiny dipole:

    • Negative end: atom with higher EN (electron density ↑).

    • Positive end: atom with lower EN (electron density ↓).

  • Two notation styles:

    • Partial-charge symbols: δ+X—Yδ\delta^+\text{X}—\text{Y}\delta^-.

    • Arrow/plus sign: X+Y\underset{+}{\text{X}}\longrightarrow \text{Y} (arrow points toward δ- end; plus sign marks δ+).

Criteria for Molecular Polarity

  • Nonpolar molecule if EITHER condition is met:

    1. No bond dipoles exist (all bonds nonpolar).

    2. Bond dipoles are arranged so they completely cancel.

  • Polar molecule if BOTH conditions are met:

    1. At least one polar bond exists (≥ 1 bond dipole).

    2. Bond dipoles do NOT cancel.

Two-Step Decision Process

  1. Bond Polarity Check

    • Identify each unique bond type.

    • Compute ΔEN|\Delta EN| using EN chart.

    • Classify each bond as polar or nonpolar.

  2. Dipole-Cancellation Check

    • Examine 3-D molecular geometry (cannot rely on flat Lewis structure).

    • Determine whether the vector sum of all bond dipoles is zero.

    • For simple molecules this is qualitative; rigorous vector math is unnecessary in CHE 111.

Special Rules for Molecules with ONE Central Atom

  • Dipoles cancel ONLY IF both of the following are true:

    1. Every electron domain around the central atom is a bonding domain (no lone pairs).

    2. All atoms directly bonded to the central atom are identical (i.e., equal EN values).

  • Visual key (used in slides):

    • Black circle = central atom.

    • Blue circles = one set of identical surrounding atoms.

    • Green circles = another set of identical surrounding atoms (if present) with a different EN from the blue set.

    • Small red lobe = non-bonding (lone) pair.

Only Three “Perfect-Cancellation” Geometries (in this course)
  • Linear (AX₂)

    • 180180^\circ bond angle.

    • Two equal-magnitude dipoles in opposite directions → perfect cancellation.

  • Trigonal Planar (AX₃)

    • 120120^\circ bond angles in one plane.

    • Three identical dipoles symmetrically oriented outward/inward → three-way cancellation.

  • Tetrahedral (AX₄)

    • 109.5109.5^\circ bond angles in 3-D.

    • Four identical dipoles symmetrically oriented → four-way cancellation.

  • All other combinations (lone pairs present, different surrounding atoms, or different geometries) result in polar molecules because the dipoles do not fully cancel.

Molecules with MULTIPLE Central Atoms

  • Can be nonpolar only if every individual bond dipole in the entire molecule cancels collectively.

  • No simple “shortcut rule”; entire 3-D frame must be analysed.

  • Reminder: If the molecule contains zero polar bonds, it is automatically nonpolar regardless of size or shape.

Worked Examples (from slides)

Example 1: AsCl3\text{AsCl}_3
  • Geometry: Trigonal pyramidal (1 lone pair on As, 3 bonding pairs).

  • Bonds present: As–Cl.

    • ΔEN=3.02.0=1.0|\Delta EN| = 3.0 - 2.0 = 1.0 \Rightarrow polar bonds.

  • Dipole cancellation?

    • One central atom, 3 atoms + 1 lone pair → cancellation fails.

  • Conclusion: POLAR molecule.

  • Explanation: Dipoles from the three identical polar bonds are tilted by the lone pair; net vector ≠ 0 → overall dipole present.

Example 2: CO2\text{CO}_2
  • Geometry: Linear O=C=O.

  • Bonds present: C–O.

    • ΔEN=3.52.5=1.0|\Delta EN| = 3.5 - 2.5 = 1.0 \Rightarrow polar bonds.

  • Dipole cancellation?

    • Central atom with 2 identical surrounding atoms, 0 lone pairs → criteria for linear cancellation satisfied.

  • Conclusion: NONPOLAR molecule.

  • Explanation: Two equal polar bonds oriented 180180^\circ apart cancel exactly → net dipole = 0.

Example 3: COH2\text{COH}_2 (Formaldehyde, CH₂O)
  • Geometry: Trigonal planar around C (no lone pairs).

  • Bonds present & polarity:

    • C–O: ΔEN=1.0|\Delta EN| = 1.0 → polar.

    • C–H: ΔEN=0.4|\Delta EN| = 0.4 → nonpolar.

  • Net dipoles:

    • Only one bond dipole exists (C–O).

    • A single vector cannot cancel itself.

  • Conclusion: POLAR molecule.

  • Explanation: Unequal EN of attached atoms means symmetry is broken; lone dipole remains unopposed → overall dipole.

Example 4: SO2\text{SO}_2
  • Geometry: Bent (1 lone pair on S, 2 bonding pairs).

  • Bonds present: S–O.

    • ΔEN=1.0|\Delta EN| = 1.0 → polar bonds.

  • Dipole cancellation?

    • Two polar bonds + lone pair create an angular geometry; vectors not directly opposed.

  • Conclusion: POLAR molecule.

  • Explanation: Lone pair forces bent shape, preventing linear arrangement; dipoles add to give net moment.

General Summary / Decision Algorithm

  1. Identify all bond types.

    • Compute ΔEN|\Delta EN| for each.

    • Label each bond as polar or nonpolar.

  2. If no polar bonds → molecule is nonpolar (done).

  3. If ≥ 1 polar bond → inspect molecular geometry.

    • For single-central-atom species, use the three “perfect-cancellation” geometries as a quick test.

    • For others (lone pairs, mixed atoms, multi-central-atom frameworks), draw/visualise the 3-D structure and qualitatively sum the dipole vectors.

  4. Conclusions:

    • Polar molecule → at least one polar bond AND incomplete dipole cancellation.

    • Nonpolar molecule → either no polar bonds OR complete cancellation of all dipoles.

Ethical, Philosophical & Practical Implications (highlighted implicitly)

  • Understanding polarity underpins responsible handling of chemicals (predicting solubility, toxicity, environmental persistence).

  • Encourages molecular-level thinking: appreciating that invisible vector sums dictate macroscopic behaviour.

Numerical / Statistical References & Formula Recap

  • Electronegativity cut-offs:

    • ΔEN0.5|\Delta EN| \ge 0.5 → polar covalent.

    • |\Delta EN| < 0.5 → nonpolar covalent.

  • Perfect-cancellation bond angles (ideal VSEPR values):

    • Linear: 180180^\circ.

    • Trigonal planar: 120120^\circ.

    • Tetrahedral: 109.5109.5^\circ.

  • Dipole vector representation: arrow points toward δ-, plus sign marks δ+.

Connection to Previous & Upcoming Content

  • Builds directly on VSEPR & Molecular Geometry (Unit 5 – Part 4) where shapes/lone pairs were determined.

  • Sets the stage for Unit 5 – Part 6 (Sigma & Pi Bonds; Hybrid Orbitals) by emphasising spatial orientation of bonds and electron density.

Practice & Next Steps

  • Use the “Geometry and Polarity – Practice Worksheet” to reinforce the two-step method.

  • Additional molecules (beyond examples) should be tested to master quick identification.

  • Upcoming lecture will explore orbital overlap (σ and π bonds) and hybridisation, further explaining why certain geometries arise and how they affect polarity.


Last slide reminder: “THE END” – proceed to Unit 5 Part 6.