Quadratic Functions Review

Horizontal Transformations of Quadratic Functions

  • Replacing a parent function f(x)f(x) with f(x+k)f(x + k) results in a horizontal shift (translation) of the graph by kk units.

  • Effect of the Constant kk on the Graph:

    • If k>0k > 0 (positive constant inside the function argument), the graph of f(x)f(x) shifts horizontally to the left by kk units.

    • If k<0k < 0 (negative constant inside the function argument), the graph of f(x)f(x) shifts horizontally to the right by ∣k∣|k| units.

  • Coordinate Point Mapping:

    • Under the transformation f(x)→f(x+k)f(x) \rightarrow f(x + k), every point (x,y)(x, y) on the original graph maps to (x−k,y)(x - k, y).

    • The y-coordinates of all points remain completely unchanged, while the x-coordinates decrease by kk units.

  • Impact on Key Features:

    • Axis of Symmetry: Shifts horizontally from x=0x = 0 (for standard parent function f(x)=x2f(x) = x^2) to x=−kx = -k.

    • Vertex: Shifts from (0,0)(0, 0) to (−k,0)(-k, 0).

    • Range: Remains unchanged, as vertical position is unaffected.

    • Domain: Continuous across all real numbers, (-\text{∑}, \text{∑}).

Vertical Transformations of Quadratic Functions

  • Replacing a function f(x)f(x) with f(x)+kf(x) + k results in a vertical shift (translation) of the graph by kk units.

  • Effect of the Constant kk on the Graph:

    • If k>0k > 0 (positive constant added outside the function), the graph shifts vertically upwards by kk units.

    • If k<0k < 0 (negative constant subtracted outside the function), the graph shifts vertically downwards by ∣k∣|k| units.

  • Coordinate Point Mapping:

    • Under the transformation f(x)→f(x)+kf(x) \rightarrow f(x) + k, every point (x,y)(x, y) on the original graph maps to (x,y+k)(x, y + k).

    • The x-coordinates of all points remain completely unchanged, while the y-coordinates increase by kk units.

  • Impact on Key Features:

    • Axis of Symmetry: Remains unaffected at x=0x = 0 (unless horizontal shifts are also present).

    • Vertex: Shifts from (0,0)(0, 0) to (0,k)(0, k).

    • Extreme Values: The minimum or maximum value of the function changes directly by adding kk (new extreme value is kk).

    • Range: Changes from [0, \text{∑}) to [k, \text{∑}) for upward-opening parabolas, or from (-\text{∑}, 0] to (-\text{∑}, k] for downward-opening parabolas.

Vertical Dilations and Reflections

  • Replacing a function f(x)f(x) with kf(x)k f(x) scales or reflects the graph vertically by a multiplicative factor kk

  • Effect of the Multiplier kk on the Shape of the Graph:

    • Vertical Stretch: If ∣k∣>1|k| > 1, the graph is stretched vertically by a factor of ∣k∣|k|, making the parabola appear narrower.

    • Vertical Compression: If 0<∣k∣<10 < |k| < 1, the graph is compressed vertically by a factor of ∣k∣|k|, making the parabola appear wider.

    • Axis Reflection: If k<0k < 0, the graph is reflected across the x-axis, changing its opening direction.

  • Coordinate Point Mapping:

    • Under the transformation f(x)→kf(x)f(x) \rightarrow k f(x), every point (x,y)(x, y) on the original graph maps to (x,ky)(x, k y).

    • The x-coordinates remain identical while all y-coordinates are multiplied by kk

  • Combination of Stretch and Reflection:

    • If k=−2k = -2, the graph reflects across the x-axis and undergoes a vertical stretch by a factor of 22

    • If k=−12k = -\frac{1}{2}, the graph reflects across the x-axis and undergoes a vertical compression by a factor of 12\frac{1}{2}

Equivalent Forms of Quadratic Functions

  • Quadratic functions can be represented in three primary algebraic forms, each revealing distinct geometric properties of the parabola.

  • Standard Form:

    • Expression: f(x)=ax2+bx+cf(x) = a x^2 + b x + c, where a≠0a \neq 0

    • Revealed Properties: Directly shows the y-intercept at (0,c)(0, c) and whether the parabola opens upward (a>0a > 0) or downward (a<0a < 0).

  • Vertex Form:

    • Expression: f(x)=a(x−h)2+kf(x) = a(x - h)^2 + k, where a≠0a \neq 0

    • Revealed Properties: Directly identifies the vertex (h,k)(h, k), the axis of symmetry x=hx = h, and the vertical dilation/orientation factor aa

  • Factored Form (Intercept Form):

    • Expression: f(x)=a(x−r1)(x−r2)f(x) = a(x - r_1)(x - r_2), where a≠0a \neq 0

    • Revealed Properties: Directly identifies the zeros (x-intercepts) at (r1,0)(r_1, 0) and (r2,0)(r_2, 0).

  • Converting Between Equivalent Forms:

    • Standard to Vertex: Completed by completing the square or calculating h=−b2ah = \frac{-b}{2a} and k=f(h)k = f(h).

    • Vertex to Standard: Expanded algebraically via (x−h)2=x2−2hx+h2(x - h)^2 = x^2 - 2 h x + h^2 and simplified.

    • Factored to Standard: Expanded using polynomial distribution (FOIL) and multiplying by scalar aa

Factoring Quadratic Expressions with Leading Coefficient a = 1

  • Structure of Quadratic Expression:

    • Form: x2+bx+cx^2 + b x + c

    • Target Factored Form: (x+p)(x+q)(x + p)(x + q)

  • Step-by-Step Factoring Procedure:

    • Step 1: Identify coefficients bb (linear coefficient) and cc (constant term).

    • Step 2: Find two real numbers pp and qq that satisfy two simultaneous requirements:

    • Product Rule: p×q=cp \times q = c

    • Sum Rule: p+q=bp + q = b

    • Step 3: Rewrite the expression as the product of two binomials: (x+p)(x+q)(x + p)(x + q).

  • Sign Rules for Factoring:

    • If c>0c > 0 and b>0b > 0: Both pp and qq must be positive.

    • If c>0c > 0 and b<0b < 0: Both pp and qq must be negative.

    • If c<0c < 0: One factor is positive and one factor is negative; the sign of the larger absolute value matches the sign of bb

Identifying Zeros, Extreme Values, and Symmetry via Factoring

  • Determining Zeros (x-intercepts):

    • Set the factored function equal to zero: a(x−r1)(x−r2)=0a(x - r_1)(x - r_2) = 0

    • Apply the Zero Product Property: x−r1=0x - r_1 = 0 or x−r2=0x - r_2 = 0

    • Real Zeros: x=r1x = r_1 and x=r2x = r_2. Points on graph are (r1,0)(r_1, 0) and (r2,0)(r_2, 0).

  • Determining Axis of Symmetry:

    • Due to parabolic symmetry, the axis of symmetry is located precisely halfway between the two zeros.

    • Formula for Axis of Symmetry: x=r1+r22x = \frac{r_1 + r_2}{2}

  • Determining Extreme Values (Vertex):

    • The x-coordinate of the vertex hh is equal to the axis of symmetry value: h=r1+r22h = \frac{r_1 + r_2}{2}.

    • The y-coordinate of the vertex kk is obtained by substituting hh into the function: k = f\right(\frac{r_1 + r_2}{2}\right).

    • Type of Extremum:

    • If a>0a > 0, the parabola opens upward, providing a absolute minimum value of kk

    • If a<0a < 0, the parabola opens downward, providing an absolute maximum value of kk

Graphing Quadratic Functions from Vertex Form

  • Equation Structure: f(x)=a(x−h)2+kf(x) = a(x - h)^2 + k

  • Identification of Key Features:

    • Vertex: Read directly from equation parameters as (h,k)(h, k). Note that the sign inside the parenthesis is negated.

    • Axis of Symmetry: The vertical line defined by equation x=hx = h

    • Direction of Opening:

    • Opens upward if a>0a > 0

    • Opens downward if a<0a < 0

    • Y-Intercept: Found by substituting x=0x = 0 into the equation: f(0)=a(0−h)2+k=ah2+kf(0) = a(0 - h)^2 + k = a h^2 + k

  • Step-by-Step Procedure for Graphing:

    • Step 1: Plot the vertex (h,k)(h, k) on the coordinate plane.

    • Step 2: Draw the vertical axis of symmetry line x=hx = h as a dashed line.

    • Step 3: Determine the direction of opening and vertical stretch factor aa

    • Step 4: Calculate and plot additional reference points using step pattern relative to vertex (h±1,k+a)(h \text{±} 1, k + a), (h±2,k+4a)(h \text{±} 2, k + 4a), or by finding the y-intercept.

    • Step 5: Reflect points across the axis of symmetry x=hx = h to ensure symmetric accuracy.

    • Step 6: Connect points with a smooth, continuous U-shaped curve with arrows at both ends.

Writing Equations of Parabolas Given Specific Attributes

  • Attributes Provided:

    • Vertex (h,k)(h, k)

    • Axis of symmetry x=hx = h

    • Direction of opening (upward or downward)

    • Additional point on parabola (x1,y1)(x_1, y_1)

  • Procedure to Derive Equation in Vertex Form:

    • Step 1: Substitute the known vertex coordinates (h,k)(h, k) into vertex form equation: f(x)=a(x−h)2+kf(x) = a(x - h)^2 + k

    • Step 2: Substitute the coordinates of the given additional point (x1,y1)(x_1, y_1) into equation for xx and f(x)f(x): y1=a(x1−h)2+ky_1 = a(x_1 - h)^2 + k

    • Step 3: Solve algebraically for parameter aa:

    a=y1−k(x1−h)2a = \frac{y_1 - k}{(x_1 - h)^2}

  • Step 4: Verify that the sign of aa matches the specified direction of opening:

    • Upward opening requires a>0a > 0

    • Downward opening requires a<0a < 0

  • Step 5: Write final equation substituting numerical values for aa, hh, and kk

Questions and Discussion

  • Review Questions & Diagnostic Focus:

    • Identifying transformation types from equation modifications (f(x+k)f(x + k), f(x)+kf(x) + k, and kf(x)k f(x)).

    • Factoring quadratics with a=1a = 1 efficiently and determining x-intercepts.

    • Converting between quadratic forms to state features such as vertex, zeros, axis of symmetry, and minimum/maximum values.

Here are a few practice problems based on your notes to test your understanding:

  1. Horizontal and Vertical Transformations
    Describe the transformations required to convert the parent function f(x)=x2f(x) = x^2 into g(x)=(x+3)2−7g(x) = (x + 3)^2 - 7. State the vertex and axis of symmetry.

  2. Factoring Quadratic Expressions
    Factor the quadratic expression x2−8x+15x^2 - 8x + 15. Use your factored form to determine the zeros of the function f(x)=x2−8x+15f(x) = x^2 - 8x + 15.

  3. Converting to Vertex Form
    Rewrite f(x)=x2+6x+5f(x) = x^2 + 6x + 5 in vertex form f(x)=a(x−h)2+kf(x) = a(x - h)^2 + k by completing the square or finding the vertex. Identify the extreme value and state whether it is a minimum or maximum.

  4. Writing the Equation of a Parabola
    A parabola has a vertex at (3,−2)(3, -2) and passes through the point (5,6)(5, 6). Write its equation in vertex form.

Try solving these, and let me know if you would like to check your answers or see step-by-step solutions!

Here are 5 practice problems based on your notes: 1. Horizontal and Vertical Transformations: Describe the transformations required to convert the parent function f(x)=x2f(x) = x^2 into g(x)=−2(x−4)2+5g(x) = -2(x - 4)^2 + 5. State the vertex and axis of symmetry. 2. Factoring and Zeros: Factor the quadratic expression x2−7x+12x^2 - 7x + 12 and find the zeros of f(x)=x2−7x+12f(x) = x^2 - 7x + 12. Use the zeros to determine the axis of symmetry and the vertex. 3. Writing Equations in Vertex Form: A parabola has a vertex at (−2,3)(-2, 3) and passes through the point (1,−15)(1, -15). Write its equation in vertex form f(x)=a(x−h)2+kf(x) = a(x - h)^2 + k. 4. Converting Between Forms: Convert f(x)=(x−2)(x+6)f(x) = (x - 2)(x + 6) into standard form f(x)=ax2+bx+cf(x) = a x^2 + b x + c and identify its y-intercept. 5. Identifying Key Features: For the function f(x)=(x+1)2−9f(x) = (x + 1)^2 - 9, find the y-intercept, x-intercepts, vertex, minimum value, and range.