3.2 Coordinate System and Vector Components — Key Points

Coordinate systems

  • A coordinate system is an artificial grid imposed on a problem to make quantitative measurements easier. We usually use Cartesian coordinates: two perpendicular axes with an origin where they cross.
  • Label axes clearly (e.g., +x to the right, +y up).

Component vectors and vector resolution

  • Any vector a can be decomposed into two perpendicular components parallel to the axes: a = ax + ay.
  • The x component vector ax lies along the x-axis; the y component vector ay lies along the y-axis.
  • Components are scalars with sign: ax and ay carry magnitude and direction information.
  • The parallelogram (or head-to-tail) rule shows that a is the sum of its components.

How to determine components from magnitude and angle

  • If the vector a has magnitude |a| and is at angle θ from the +x axis (above the horizontal):
    a<em>x=acosθ,a</em>y=asinθ.a<em>x = |a| \cos \theta, \quad a</em>y = |a| \sin \theta.
  • Signs reflect direction: positive components point toward the positive axis direction.
  • If the angle is measured from the vertical (the y-axis), the roles of sine and cosine swap (examples below):
    a<em>x=asinθ,a</em>y=acosθ.a<em>x = |a| \sin \theta, \quad a</em>y = -|a| \cos \theta.
  • The magnitude and angle from components:
    a=a<em>x2+a</em>y2,θ=tan1(a<em>ya</em>x).|a| = \sqrt{a<em>x^2 + a</em>y^2}, \quad \theta = \tan^{-1}\left(\frac{a<em>y}{a</em>x}\right).
  • Important: always define the angle from a diagram; the above formulas depend on that definition and may change if the angle origin changes.

Determine components from a given vector direction (examples)

  • Example: magnitude 6.0 m/s^2 at 30° below the negative x-axis (i.e., in the third quadrant direction along −x and −y with 30° down from −x):
    a<em>x=6.0cos305.2,a<em>x = -6.0 \cos 30^{\circ} \approx -5.2,a</em>y=6.0sin30=3.0.a</em>y = -6.0 \sin 30^{\circ} = -3.0.
  • Example: vector with components ax = +3 m, ay = +2 m corresponds to a vector in the first quadrant; signs indicate direction.

Inverse problem: from components to magnitude and direction

  • Magnitude from components:
    a=a<em>x2+a</em>y2.|a| = \sqrt{a<em>x^2 + a</em>y^2}.
  • Direction from components:
    θ=tan1(a<em>ya</em>x)\theta = \tan^{-1}\left(\frac{a<em>y}{a</em>x}\right)
  • If signs differ (different quadrant), adjust θ accordingly based on the signs of ax and ay.
  • If angle is defined relative to vertical, use the appropriate form (see above).

Special cases: vectors with negative components and quadrant awareness

  • If a vector points down or left, the corresponding components are negative (e.g., ay < 0 for downward, ax < 0 for left).
  • The magnitude is unaffected by signs, but direction is.
  • When the vector lies in unusual quadrants, always refer to a diagram to identify the correct signs and angle.

Vector addition and subtraction using components (algebraic addition)

  • If c = a + b, then
    c<em>x=a</em>x+b<em>x,c</em>y=a<em>y+b</em>y.c<em>x = a</em>x + b<em>x, \quad c</em>y = a<em>y + b</em>y.
  • Subtraction: if d = pq, then
    d<em>x=p</em>xq<em>x,d</em>y=p<em>yq</em>y.d<em>x = p</em>x - q<em>x, \quad d</em>y = p<em>y - q</em>y.
  • Scalar multiplication: for scalar t,
    (ta)<em>x=ta</em>x,(ta)<em>y=ta</em>y.(t\mathbf{a})<em>x = t a</em>x, \quad (t\mathbf{a})<em>y = t a</em>y.
  • Vector equations encode two scalar equations (one for each axis).

Example: displacement by algebraic (component) addition

  • Bird displacement: 100 m east, then 200 m NW (45° north of west).
    • Components: Ax = +100 m, Ay = 0; Bx = -200 cos 45° ≈ -141 m, By = +200 sin 45° ≈ +141 m.
    • Net: Cx = Ax + Bx ≈ -41 m; Cy = Ay + By ≈ +141 m.
    • Magnitude: |C| ≈ \sqrt{(-41)^2 + 141^2} ≈ 147\,\text{m}.
    • Direction: θ ≈ arctan(|141|/|41|) ≈ 74°, i.e., 74° north of west.

Tilted coordinate systems (tilted axes)

  • Sometimes x' axis is along a slope; decompose vectors into components along the tilted axes.
  • In a tilted frame, components are still projections:
    c<em>x=ccosθ,c</em>y=csinθc<em>{x'} = c \cos \theta', \quad c</em>{y'} = c \sin \theta'
    where θ' is the angle with respect to the tilted x' axis.
  • If the angle is measured from the vertical in a tilted frame, formulas adjust similarly (use the appropriate projections).

Quick reference tips

  • Components are the projections of a vector onto the axes; the numbers carry sign to indicate direction.
  • Always define the angle from a diagram before applying formulas.
  • Use algebraic addition for combining vectors via their components; this is often simpler than graphical addition.
  • Magnitude is found via the Pythagorean relation; direction via arctangent with quadrant awareness.