Thermodynamics: Enthalpy, Entropy, Free Energy, and Spontaneity

  • Thermodynamic Constructs Introduced: The lecture revisits entropy (<br>ho<br>ho) and enthalpy (extHext{H}), initially discussed on Wednesday.

  • Entropy and Spontaneity: Change in entropy of a system (<br>hoextsystem<br>ho_{ ext{system}}) alone does not necessarily indicate spontaneity, though it can influence it.

  • Enthalpy ($ ext{H}$) - Exothermic vs. Endothermic Processes:

    • Exothermic Process: Defined by a negative change in enthalpy (extH<0ext{H} < 0).

      • Heat is a product of the process.

      • If a reaction in a test tube is exothermic, holding the test tube will feel hot because heat is released into the surroundings (your hand).

    • Endothermic Process: Defined by a positive change in enthalpy (extH>0ext{H} > 0).

      • Heat appears as a reactant; it is absorbed by the process.

      • If a reaction in a test tube is endothermic, holding the test tube will feel cold.

      • This cold sensation is because heat is absorbed from the surroundings (your hand) by the reaction. Heat flows from warmer (your hand) to colder (the reacting system).

  • Gibbs Free Energy ($ ext{G}$) - The Indicator of Spontaneity:

    • The relationship between enthalpy, entropy, and free energy is given by the equation: ΔG=ΔH−TΔS\Delta G = \Delta H - T\Delta S where TT is the absolute temperature in Kelvin.

    • Both entropy and enthalpy directly influence the free energy change (ΔG\Delta G).

    • Spontaneity Criteria:

      • If ΔG<0\Delta G < 0: The process is spontaneous (also called exergonic) in the forward direction (reactants →\rightarrow products).

      • If ΔG>0\Delta G > 0: The process is non-spontaneous (also called endergonic) in the forward direction. The reverse process would be spontaneous.

      • If ΔG=0\Delta G = 0: The system is at equilibrium.

    • Conditions for Spontaneity based on ΔH\Delta H and ΔS\Delta S:

      • If ΔH<0\Delta H < 0 (exothermic) and ΔS>0\Delta S > 0 (increasing entropy), then ΔG\Delta G will always be negative, making the process spontaneous at all temperatures.

      • If ΔH>0\Delta H > 0 (endothermic) and ΔS<0\Delta S < 0 (decreasing entropy), then ΔG\Delta G will always be positive, making the process non-spontaneous at all temperatures.

      • If ΔH<0\Delta H < 0 and ΔS<0\Delta S < 0: Spontaneous at low temperatures (when ∣ΔH∣>∣TΔS∣|\Delta H| > |T\Delta S|).

      • If ΔH>0\Delta H > 0 and ΔS>0\Delta S > 0: Spontaneous at high temperatures (when ∣TΔS∣>∣ΔH∣|T\Delta S| > |\Delta H|).

  • Units and Calculations:

    • Temperature (TT) must always be in Kelvin. To convert Celsius to Kelvin, add 273.15273.15 (or approximately 273273).

    • Units of ΔH\Delta H are typically in kilojoules (extkJext{kJ}) or kilojoules per mole (extkJ/molext{kJ/mol}).

    • Units of ΔS\Delta S are typically in joules per Kelvin (extJ/Kext{J/K}) or joules per Kelvin per mole (extJ/K⋅molext{J/K \cdot mol}).

    • Crucial Unit Conversion: Before adding/subtracting ΔH\Delta H and TΔST\Delta S, their units must be consistent. If ΔH\Delta H is in kilojoules, ΔS\Delta S (and thus TΔST\Delta S) must also be converted to kilojoules. For example, convert joules per Kelvin to kilojoules per Kelvin (1 kJ=1000 J1 \text{ kJ} = 1000 \text{ J}).

  • Reaction Progress Diagrams:

    • Illustrate the change in free energy (or enthalpy) as a reaction proceeds.

    • Reactants: Initial free energy level.

    • Products: Final free energy level.

    • Transition State: The highest energy point on the path, where bonds are partially broken and formed. This state is related to activation energy.

    • Activation Energy (E<em>aE<em>a): The energy difference between the reactants and the transition state. It is related to the rate of the reaction (lower E</em>aE</em>a = faster rate).

    • Calculating ΔG\Delta G from Diagram: ΔG=G<em>products−G</em>reactants\Delta G = G<em>{\text{products}} - G</em>{\text{reactants}} (final minus initial).

      • If G<em>products<G</em>reactantsG<em>{\text{products}} < G</em>{\text{reactants}}, then ΔG\Delta G is negative (spontaneous/exergonic).

      • If G<em>products>G</em>reactantsG<em>{\text{products}} > G</em>{\text{reactants}}, then ΔG\Delta G is positive (non-spontaneous/endergonic).

  • Catalysts:

    • A catalyst speeds up a reaction by lowering the activation energy (EaE_a) of both the forward and reverse reactions.

    • A catalyst does not affect the free energy change (ΔG\Delta G) of the reaction.

    • A catalyst does not affect the spontaneity of the reaction or the equilibrium position; it only helps the reaction reach equilibrium faster.

  • Chemical Equilibrium (A ⇌\rightleftharpoons B):

    • Definition: A state where the rate of the forward reaction equals the rate of the reverse reaction.

    • Misconception: Equilibrium does not mean that the concentrations of reactants and products are equal. It means their rates of interconversion are equal.

    • Equilibrium Constant (K<em>eqK<em>{eq}): At equilibrium, ΔG=0\Delta G = 0. Therefore, using the non-standard state equation, we can derive: ΔG0=−RTln⁡K</em>eq\Delta G^0 = -RT \ln K</em>{eq} This equation links the standard free energy change to the equilibrium constant.

  • Standard State vs. Non-Standard State Conditions:

    • Standard State Free Energy Change (ΔG0\Delta G^0):

      • Refers to specific standard conditions:

        • For solutes: 11 M concentration.

        • For gases: 11 atmosphere (1 atm1 \text{ atm}) partial pressure.

        • Temperature is usually specified (e.g., 298 K298 \text{ K} or 25∘C25^{\circ}\text{C}).

    • Non-Standard State Free Energy Change (ΔG\Delta G):

      • Describes processes under actual, non-standard conditions.

      • Calculated using the equation: ΔG=ΔG0+RTln⁡Q\Delta G = \Delta G^0 + RT \ln Q where QQ is the reaction quotient.

      • Reaction Quotient (QQ): An expression with the same form as the equilibrium constant but uses non-equilibrium (current) concentrations or partial pressures. For a reversible reaction aA+bB⇌cC+dDaA + bB \rightleftharpoons cC + dD, Q=[C]c[D]d[A]a[B]bQ = \frac{[C]^c [D]^d}{[A]^a [B]^b}.

      • If current concentrations are plugged into QQ and they are at equilibrium, then Q=KeqQ = K_{eq}.

    • Biological Standard State (ΔG0′\Delta G^{0'}):

      • A modification of the standard state to better reflect physiological conditions.

      • The key difference is that the hydrogen ion concentration ([H+][\text{H}^+]) is set to 10−7 M10^{-7} \text{ M} (which corresponds to pH=7pH = 7), rather than 1 M1 \text{ M} (pH=0pH = 0) in the chemical standard state.

      • Most biological processes occur around a physiological pHpH of 77 to 7.27.2.

      • Example of very low pHpH in the body: stomach, with hydrochloric acid concentration around 2 M2 \text{ M}.

  • State Functions:

    • A property whose value depends only on the current state of the system, not on the path taken to reach that state.

    • Examples: Altitude, free energy (ΔG\Delta G), enthalpy (ΔH\Delta H).

    • Not examples: Work, heat.

  • Coupling Reactions: Cells often couple an unfavorable (endergonic, ΔG>0\Delta G > 0) reaction with a highly favorable (exergonic, ΔG<0\Delta G < 0) reaction to drive overall processes.

    • Example: The phosphorylation of glucose to glucose-6-phosphate (an endergonic process, ΔG0=+18 kJ/mol\Delta G^0 = +18 \text{ kJ/mol}) is coupled with the hydrolysis of ATP to ADP and phosphate (an exergonic process, ΔG0=−30.5 kJ/mol\Delta G^0 = -30.5 \text{ kJ/mol}).

    • The overall reaction (Glucose + ATP →\rightarrow Glucose-6-Phosphate + ADP) has a net negative ΔG0\Delta G^0 (approx. −12.5 kJ/mol-12.5 \text{ kJ/mol}), making it spontaneous.