Algebraic and Geometric Problem Solutions

Solutions to Linear and Radical Equations

  • Problem 7 Solutions and Algebraic Steps:

    • The initial equation setup evaluates to 11=12(5x−8)11 = \frac{1}{2}(5x - 8).
    • Multiplying both sides by 22 yields: 22=5x−822 = 5x - 8.
    • Adding 88 to both sides isolates the linear term containing the variable xx: 30=5x30 = 5x.
    • Dividing both sides by 55 gives the final solution: x=6x = 6.
  • Problem 8 Solutions and Radical Steps:

    • The initial algebraic radical statement is 8=9x+108 = \sqrt{9x + 10}.
    • The intermediate simplified relation provides: 16=9x+1016 = 9x + 10.
    • Subtracting 1010 from both sides isolates the variable term: 6=9x6 = 9x.
    • Reducing the fraction gives: 23\frac{2}{3}.
    • The evaluated variable solution is x=23x = \frac{2}{3}.

Geometric Properties of Vertical and Supplementary Angles

  • Problem 9 Angle Determination:

    • Angle bb is vertical to an angle measuring 66∘66^\circ, which establishes that b=66∘b = 66^\circ because vertical angles are equal.
    • Angle cc forms a straight line with 66∘66^\circ, indicating that they are supplementary angles that add up to 180∘180^\circ
    • Solving for cc: c=180∘−66∘=114∘c = 180^\circ - 66^\circ = 114^\circ
    • Final angle results: b=66∘b = 66^\circ and c=114∘c = 114^\circ
  • Problem 10 Angle Determination:

    • Angle cc is vertical to 100∘100^\circ, which establishes that c=100∘c = 100^\circ
    • Angle bb is supplementary to 100∘100^\circ, which means b=180∘−100∘=80∘b = 180^\circ - 100^\circ = 80^\circ
    • Final angle results: b=80∘b = 80^\circ and c=100∘c = 100^\circ

Complementary Angles and Right Angle Calculation

  • Problem 11 Angle Calculation:
    • The whole corner forms a right angle measuring 90∘90^\circ
    • The equation relating variable aa and the given angle is a+31∘=90∘a + 31^\circ = 90^\circ
    • Solving for aa gives a=59∘a = 59^\circ
    • Associated numerical value: 77