Chapter 5 – Integral Calculus: Area, Definite Integrals, FTC & Substitution

5.1 Approximating and Computing Area

  • Core question: “How can we turn the geometric notion of area under a curve into an algebraic quantity we can calculate?”

  • Riemann rectangles

    • Partition the interval [a,b][a,b] into nn sub-intervals of equal (or variable) width Δxi\Delta x_i.

    • Choose a sample point xi∗x_i^* in each sub-interval.

    • Area of the ii-th rectangle: f(x<em>i∗) Δx</em>if(x<em>i^*)\,\Delta x</em>i.

    • Riemann sum: ∑i=1nf(xi∗) Δxi\sum{i=1}^{n}f(xi^{*})\,\Delta x_{i}

  • Left-endpoint, right-endpoint, and midpoint rules

    • Left-endpoint sampling tends to underestimate if ff is increasing, overestimate if ff is decreasing.

    • Right-endpoint sampling behaves oppositely.

    • Midpoint usually provides a better approximation (error proportional to 1/n21/n^2 vs 1/n1/n for the two endpoint rules).

  • Limit idea

    • As n→∞n\to\infty (i.e.

      max⁡Δxi→0\max\Delta xi\to0) the Riemann sums, if they converge, approach the definite integral:

    • lim⁡n→∞∑i=1nf(xi∗) Δxi=f(x) dx.{\displaystyle\lim{n\to\infty}\sum{i=1}^{n}f(xi^{*})\,\Delta xi=f(x)\,dx.}

  • Over/under estimates visualized

    • Example: f(x)=x2f(x)=x^2 on [0,1][0,1].

    • Left sum with n=4n=4 rectangles: width 0.250.25, heights 0,0.0625,0.25,0.5625⇒area=0.218750,0.0625,0.25,0.5625\Rightarrow\text{area}=0.21875 (underestimate; true area =1/3≈0.3333=1/3\approx0.3333).

    • Right sum: 0.0625+0.25+0.5625+1⇒area=0.468750.0625+0.25+0.5625+1\Rightarrow\text{area}=0.46875 (overestimate).

  • Philosophical note: Area (a geometric primitive) is reduced to limits of sums—one of the earliest demonstrations of “continuous quantity ⇒ limiting process.”

5.2 The Definite Integral

  • Definition

    • A bounded function ff on [a,b][a,b] is integrable (Riemann-integrable) if its Riemann sums converge to the same limit regardless of the choice of sample points.

  • Guarantee of integrability

    • Every continuous function on a closed interval is integrable.

    • Discontinuous functions can still be integrable if their discontinuities form a “small” set (e.g. a finite number of jump discontinuities or any set of measure 0, like the set of rationals).

    • Example of an integrable discontinuous function: f(x)={1,x≠0,x=0f(x)=\begin{cases}1, & x\ne0,\\ x=0 & \end{cases} The integral equals 2.2.

  • Definite vs. indefinite integrals

    • Definite integral ∫abf(x) dx\int_a^b f(x)\,dx ⇒ single number (net signed area).

    • Indefinite integral ∫f(x) dx\int f(x)\,dx ⇒ family of antiderivatives F(x)+C.F(x)+C.

  • Net area & orientation

    • Area above the xx-axis contributes positively; area below contributes negatively.

    • “Net area” ≠ “geometric area” unless f≥0f\ge0.

  • Properties (useful for proofs & computations)

    • Linearity: (Af(x)+Bg(x))dx=Af+B∫abg.\big(Af(x)+Bg(x)\big)dx=Af+B\int_{a}^{b}g.

    • Additivity on intervals: f=f+∫cbf=f+\int_{c}^{b}

    • Reversal: f=−f.f=-f.

5.3 Antiderivatives & Fundamental Theorem of Calculus (FTC) Part I

  • Antiderivative

    • A function FF satisfies F′(x)=f(x).F'(x)=f(x). Not unique ⇒ “+C+C.”

  • Area function

    • Fix a point aa; define F(x)=∫axf(t) dt.F(x)=\int_a^x f(t)\,dt.

    • FTC Part I: F′(x)=f(x)F'(x)=f(x) (differentiation undoes integration).

    • Intuition: changing the upper limit from xx to x+Δxx+\Delta x adds a thin rectangle of height f(x)f(x) and width Δx\Delta x.

  • Significance

    • Gives a constructive way to build one antiderivative even when an explicit formula is unknown.

    • Shows that “instantaneous rate of change of accumulated area” returns the original density function.

  • Role of CC

    • In a definite integral ∫abf(x)dx=F(b)−F(a),\int_a^b f(x)dx=F(b)-F(a), the arbitrary constants cancel.

5.4 Fundamental Theorem of Calculus Part II

  • Computational statement

    • If FF is any antiderivative of f,f, then ∫abf(x) dx=F(b)−F(a).\displaystyle\int_a^b f(x)\,dx = F(b)-F(a).

  • Proof sketch

    • Subdivide [a,b][a,b], apply Mean Value Theorem to F,F, sum telescopes ⇒ limit.

  • Consequences

    • Convert almost every integral-evaluation problem into an algebra problem of finding antiderivatives.

    • Bridges differential calculus (finding FF) with integral calculus (areas, total change).

  • Typical examples

    • ∫0πsin⁡x dx\int0^{\pi}\sin x\,dx = [−cos⁡x]0π=(−cos⁡π)−(−cos⁡0)=2.[-\cos x]0^{\pi}=(-\cos\pi)-(-\cos0)=2.

    • Average value of a function ff on [a,b][a,b]: f=1b−af(x)dx.f{}=\dfrac1{b-a}f(x)dx.

5.6 Substitution Method (uu-Substitution)

  • Motivation

    • Reverse of the Chain Rule: if ddxF(g(x))=F′(g(x))g′(x),\dfrac{d}{dx}F(g(x)) = F'(g(x))g'(x), then ∫f(g(x))g′(x)dx\int f(g(x))g'(x)dx can be simplified by letting u=g(x).u=g(x).

  • Indefinite integral procedure

    1. Identify an inner function u=g(x)u=g(x) whose derivative g′(x)g'(x) appears (up to a constant) in the integrand.

    2. Write du=g′(x)dxdu=g'(x)dx ⇒ replace g′(x)dx⇝dug'(x)dx\rightsquigarrow du.

    3. Rewrite integral in terms of uu; integrate; back-substitute u=g(x).u=g(x).

  • Definite integral version

    • Change the bounds: if x=ax=a ⇒ u=g(a),u=g(a), and x=bx=b ⇒ u=g(b).u=g(b). Never mix xx-bounds with uu-integrand.

  • Examples

    • Indefinite: ∫3(1+3x)2 dx.\int 3(1+3x)^2\,dx.

    • Let u=1+3x ⇒du=3dx.u=1+3x \,\Rightarrow du=3dx.

    • Integral becomes ∫u2 du=u33+C=(1+3x)33+C.\int u^2\,du= \dfrac{u^3}{3}+C = \dfrac{(1+3x)^3}{3}+C.

    • Definite: ∫012xcos⁡(x2) dx.\int_0^1 2x\cos(x^2)\,dx.

    • u=x2,  du=2x dx.u=x^2,\;du=2x\,dx.

    • New bounds: x=0⇒u=0,  x=1⇒u=1.x=0\Rightarrow u=0,\;x=1\Rightarrow u=1.

    • Integral =∫<em>01cos⁡u du=sin⁡u∣</em>01=sin⁡1−0.=\int<em>0^1 \cos u\,du = \sin u\big|</em>0^1 = \sin1-0.

  • Pitfalls & tips

    • If dudu differs by a constant factor, pull that constant outside the integral.

    • When uu-substitution fails, consider algebraic rearrangement, trig identities, or alternative techniques (integration by parts, partial fractions, etc.).

Connections, Implications, and Applications

  • Historical insight

    • Newton & Leibniz discovered FTC in the late 1600s, formalizing the duality between accumulation and rate of change.

  • Real-world relevance

    • Physics: displacement = integral of velocity; work = integral of force; electric charge = integral of current.

    • Economics: consumer surplus = integral between demand curve and price; total cost from marginal cost.

  • Philosophical/ethical reflection

    • The ability to compute “total impact” (area) from “instantaneous effect” (rate) underpins quantitative decision-making, from drug dosage to carbon-emission accounting.

  • Foundation for later topics

    • Techniques of Integration, Numerical Integration (Trapezoid, Simpson), Improper Integrals.

    • Differential equations: antiderivatives serve as solutions to y′=f(x).y'=f(x).

    • Multivariable calculus: Riemann sums generalize to double/triple integrals.