Vector Components and Positive Direction Conventions (2, -3)

Positive Direction and Components

  • The transcript describes moving “two in the positive direction of x and then negative three in y,” which corresponds to a displacement described by its x- and y-components.
  • Core idea: A vector in a 2D Cartesian plane is described by its components along the x-axis and y-axis.

Positive direction of x

  • The transcript asks: “What is the positive direction of x? Well, it's not right. Does it need to be?”
    • In standard Cartesian coordinates, the positive x-direction is conventionally to the right, but the exact orientation of axes on a diagram can vary.
    • The sign of the x-component is determined by the axis orientation, not by an inherent physical direction like "+" equals right in all contexts.
  • Takeaway: Positive x is defined by the coordinate system in use; many graphs assume +x to the right and +y upward, but you must rely on the diagram’s axis directions.

Vector from the transcript (component form)

  • Movement described: +2 along the x-axis and -3 along the y-axis.
  • Component form of the vector: v=2,3\vec{v} = \langle 2, -3 \rangle (or (2, -3))
  • Interpretation:
    • Start at the origin (0,0) and move 2 units in the +x direction.
    • Then move 3 units in the -y direction (downward).
    • End position: (2, -3).

Magnitude and direction

  • Magnitude (length) of the vector: <br/>vecv=v<em>x2+v</em>y2=22+(3)2=133.606|<br /> vec{v}| = \sqrt{v<em>x^2 + v</em>y^2} = \sqrt{2^2 + (-3)^2} = \sqrt{13} \approx 3.606
  • Direction relative to the +x axis:
    • θ=tan1(v<em>yv</em>x)=tan1(32)56.31\theta = \tan^{-1}\left(\frac{v<em>y}{v</em>x}\right) = \tan^{-1}\left(\frac{-3}{2}\right) \approx -56.31^\circ
  • Notes about angle:
    • Since vy is negative and vx is positive, the vector lies in the fourth quadrant.
    • A negative angle indicates a clockwise rotation from the +x axis.
  • General relation (optional): θ=atan2(v<em>y,v</em>x)\theta = \operatorname{atan2}(v<em>y, v</em>x) is a robust way to compute angle across all quadrants.

How to draw from the origin

  • Start at (0,0).
  • Move 2 units to the right (along +x).
  • Move 3 units downward (along -y).
  • Draw the arrow from (0,0) to (2,-3).
  • This yields the same as the vector v=2,3\vec{v} = \langle 2, -3 \rangle.

Sign conventions and generalization

  • For a general vector v=v<em>x,v</em>y\vec{v} = \langle v<em>x, v</em>y \rangle:
    • If v<em>x>0v<em>x > 0, move along +x; if vx < 0, move along -x.
    • If v<em>y>0v<em>y > 0, move along +y; if vy < 0, move along -y.
  • Magnitude formula: <br/>vecv=v<em>x2+v</em>y2|<br /> vec{v}| = \sqrt{v<em>x^2 + v</em>y^2}
  • Direction angle toward +x axis: θ=tan1(v<em>yv</em>x)\theta = \tan^{-1}\left(\frac{v<em>y}{v</em>x}\right) with quadrant awareness.

Connections to broader concepts

  • This example illustrates vector decomposition and reconstruction: from components to the full vector.
  • Links to vector addition: adding components corresponds to adding displacements along each axis.
  • Real-world relevance: displacement, velocity, and force in physics are often analyzed via their components.
  • Foundational principles: Cartesian coordinate system conventions, sign interpretation, and geometric interpretation of vectors.

Quick recap and checks

  • Given vector components: v=2,3\vec{v} = \langle 2, -3 \rangle.
  • End position if starting from the origin: (2, -3).
  • Magnitude: 133.606\sqrt{13} \approx 3.606.
  • Direction angle (relative to +x): 56.31.\approx -56.31^\circ.
  • Key conceptual point: Positive x-direction is defined by the coordinate system, not by an intrinsic label of “right” in all contexts.