Honors Physics Multiple Choice Review

Net Force and Motion

  • Question 1: A rope attached to a block with a weight of 120 N; rope exerts an upward force of 250 N.

    • Net Force Calculation:
      ext{Net Force} = ext{Upward Force} - ext{Weight}
      = 250 ext{ N} - 120 ext{ N} = 130 ext{ N} ext{ (up)}

    • Answer Choices:

    • a. 130 N up

    • b. 370 N up

    • c. 130 N down

    • d. 370 N down

Graphs and Motion Interpretation

  • Question 2: Graph shows the object’s velocity over time; identify segment showing constant positive acceleration.

    • Answer Choices:

    • a. segment W

    • b. segment X

    • c. segment Y

    • d. segment Z

Friction and Constant Velocity

  • Question 3: Diagram of a block sliding across a table at constant speed; find the magnitude of frictional force (not shown).

    • Answer Choices:

    • a. 0.8 N

    • b. 1.6 N

    • c. 1.7 N

    • d. 2.5 N

Speed Intervals

  • Question 4: Graph shows motion over time intervals W, X, Y, Z; determine fastest interval.

    • Answer Choices:

    • a. interval W

    • b. interval X

    • c. interval Y

    • d. interval Z

Total Distance Travelled

  • Question 5: A person travels from starting point to store and back; calculate total distance.

    • Path: 3 km east, 1 km west, 2 km west

    • Total Distance Calculation:
      ext{Total Distance} = 3 ext{ km} + 1 ext{ km} + 2 ext{ km} = 6 ext{ km}

    • Answer Choices:

    • a. 0 km

    • b. 3 km

    • c. 5 km

    • d. 6 km

Circular Motion

  • Question 6: Ball tied to a string swung in a circle; direction of travel when released.

    • Answer Choices:

    • a. direction W

    • b. direction X

    • c. direction Y

    • d. direction Z

Kinetic Friction

  • Question 7: Toy car at rest pushed and released; identify intervals of kinetic friction.

    • Answer Choices:

    • a. interval X only

    • b. interval Y only

    • c. intervals X and Z

    • d. intervals Y and Z

Car Motion Analysis

  • Question 8: Analyze a car’s position between times 1 and 2 from graph.

    • Answer Choices:

    • a. The car is stopped.

    • b. The car's velocity is decreasing.

    • c. The car’s displacement stays the same.

    • d. The car is traveling at a constant speed.

Motion After Break-off

  • Question 9: Astronaut repairing satellite; behavior of broken part.

    • Answer Choices:

    • a. The part will immediately stop moving.

    • b. The part will accelerate until acted upon.

    • c. The part will move at a constant speed along a straight path.

    • d. The part will move a short distance then stop.

Force Analysis under Equal Conditions

  • Question 10: Two carts on a frictionless surface pushed from rest; explain force conditions.

    • Answer Choices:

    • a. Equal force is required because of frictionless surface.

    • b. Equal force required as they finish simultaneously.

    • c. Greater force on cart Y due to less mass.

    • d. Greater force on cart Z due to more mass.

Free-body Diagrams

  • Question 11: Identify net force from a given free-body diagram.

    • Answer Choices:

    • a. 4 N

    • b. 6 N

    • c. 10 N

    • d. 16 N

Car Acceleration Graph

  • Question 12: Graph representing a car's acceleration from rest; choose correct position-time graph.

    • Answer Choices:

    • a.

    • b.

    • c.

    • d.

Kinetic vs Static Friction

  • Question 13: Difference between kinetic and static friction.

    • Answer Choices:

    • a. One applies to large masses, the other to small masses.

    • b. One applies to accelerating objects; the other to constant speed.

    • c. One applies to objects on surfaces, the other on inclined planes.

    • d. One applies to moving objects; the other to stationary resisting motion.

Parked Car Forces

  • Question 14: Free-body diagram of a parked car on flat surface.

    • Answer Choices:

    • a.

    • b.

    • c.

    • d.

Net Force from Free-body Diagram

  • Question 15: Calculate net force from a given free-body diagram.

    • Answer Choices:

    • a. 0 N up

    • b. 100 N down

    • c. 200 N right

    • d. 300 N right

Constant Velocity and Force Balance

  • Question 16: A toy truck accelerates right; if a child pulls it left, find the force to maintain velocity.

    • Answer Choices:

    • a. 1.0 N

    • b. 1.5 N

    • c. 2.5 N

    • d. 6.0 N

Couch Movement Forces

  • Question 17: Effect of new force on initial forces when couch starts to move.

    • Answer Choices:

    • a. Frictional force changes.

    • b. Gravitational force changes.

    • c. Normal force changes.

    • d. Tension force changes.

Net Force Example

  • Question 18: Identify object with net force greater than zero.

    • Answer Choices:

    • a. Glass on table

    • b. Ladder on wall

    • c. Ball rolling down ramp

    • d. Toy car moving at constant velocity

Car Motion Assessment

  • Question 19: Assess car motion based on a provided graph.

    • Answer Choices:

    • a. Constant speed then stops

    • b. Start from rest, accelerates steadily

    • c. Start from rest, constant speed

    • d. Initial motion followed by acceleration

Object Movement Analysis

  • Question 20: Determine the interval of constant positive speed from motion graph.

    • Answer Choices:

    • a. segment W

    • b. segment X

    • c. segment Y

    • d. segment Z

Block Force Computation

  • Question 21: Calculate net force from multiple student applied forces on a block.

    • Answer Choices:

    • a. 3 N to left

    • b. 8 N to left

    • c. 11 N to right

    • d. 25 N to right

Car Oil Drip

  • Question 22: Assess diagram of car's trail showing continuous slowing down.

    • Answer Choices:

    • a.

    • b.

    • c.

    • d.

Kinetic vs Static Friction Insight

  • Question 23: Explain why sliding is easier than starting movement.

    • Answer Choices:

    • a. Kinetic friction equals static friction.

    • b. Kinetic less than static friction.

    • c. Kinetic prevents starting motion.

    • d. Kinetic opposes sliding.

Constant Acceleration Calculation

  • Question 24: Initial velocity of toy car 5.0 m/s; find final velocity after 6.0 s with constant acceleration 2.0 m/s².

    • Calculation:
      ext{Final Velocity} = ext{Initial Velocity} + ( ext{Acceleration} imes ext{Time})
      = 5.0 ext{ m/s} + (2.0 ext{ m/s}^2 imes 6.0 ext{ s})
      = 5.0 ext{ m/s} + 12.0 ext{ m/s} = 17.0 ext{ m/s}

    • Answer Choices:

    • a. 10.0 m/s

    • b. 12 m/s

    • c. 16 m/s

    • d. 17 m/s

Acceleration of Race Car

  • Question 25: Race car accelerates from 0 m/s to 30.0 m/s over 45.0 m; calculate acceleration.

    • Formula Using Kinematics:
      a = rac{(vf^2 - vi^2)}{2d}
      = rac{(30.0^2 - 0^2)}{2 imes 45.0}
      = rac{900}{90.0} = 10.0 ext{ m/s}^2

    • Answer Choices:

    • a. 2.00 m/s²

    • b. 5.00 m/s²

    • c. 10.0 m/s²

    • d. 15.0 m/s²

Directional Change of Objects

  • Question 26: What causes a moving object to change direction?

    • Answer Choices:

    • a. Acceleration

    • b. Velocity

    • c. Inertia

    • d. Force

Gravitational Force Calculation

  • Question 27: Identify the gravitational force on the balloon from a free-body diagram.

    • Answer Choices:

    • a. 1520 N

    • b. 950 N

    • c. 4050 N

    • d. 5120 N

Equilibrium Forces

  • Question 28: Identify additional force for equilibrium while car goes forward at constant velocity.

    • Answer Choices:

    • a. Greater than normal force times coefficient of static friction.

    • b. Equal to normal force times coefficient of static friction.

    • c. Normal force times coefficient of kinetic friction.

    • d. Zero.

Net Force on Wagon

  • Question 29: Wagon with gravity force of 300.0 N accelerated at 0.5 m/s²; find net force.

    • Calculation:
      ext{Net Force} = m imes a
      m = rac{F_g}{g} = rac{300.0 N}{9.81 m/s^2}
      m imes 0.5 m/s^2 = 15 N

    • Answer Choices:

    • a. 9.0 N

    • b. 15 N

    • c. 150 N

    • d. 610 N

Gravitational Force Between Masses

  • Question 30: Find gravitational force between two trucks with mass 2.0 x 10^4 kg, 2.0 m apart.

    • Formula:
      F = G rac{m1 m2}{r^2}
      F = 6.673 imes 10^{-11} N imes m^2/kg^2 rac{(2.0 imes 10^4 kg)^2}{(2.0 m)^2}

    • Answer Choices:

    • a. 5.7 x 10^-2 N

    • b. 1.3 x 10^-2 N

    • c. 6.7 x 10^-3 N

    • d. 1.2 x 10^-7 N