Chapter 12: Rotation of a Rigid Body Notes

12.1 Rotational Motion

  • Rigid body: size and shape remain constant during movement.

  • Rigid bodies can undergo translational, rotational, or combined motion.

12.2 Rotation About the Center of Mass

  • Center of mass: mass-weighted center of an object.

  • For symmetrical objects with uniform density, the center of mass is at the physical center.

  • Center of mass equations:

    • x<em>cm=1M</em>im<em>ix</em>i=m<em>1x</em>1+m<em>2x</em>2+m<em>3x</em>3+m<em>1+m</em>2+m3+x<em>{cm} = \frac{1}{M} \sum</em>{i} m<em>{i}x</em>{i} = \frac{m<em>1x</em>1 + m<em>2x</em>2 + m<em>3x</em>3 + \cdots}{m<em>1 + m</em>2 + m_3 + \cdots}

    • y<em>cm=1M</em>im<em>iy</em>i=m<em>1y</em>1+m<em>2y</em>2+m<em>3y</em>3+m<em>1+m</em>2+m3+y<em>{cm} = \frac{1}{M} \sum</em>{i} m<em>{i}y</em>{i} = \frac{m<em>1y</em>1 + m<em>2y</em>2 + m<em>3y</em>3 + \cdots}{m<em>1 + m</em>2 + m_3 + \cdots}

  • Unconstrained objects with no net force rotate about their center of mass.

12.3 Rotational Energy

  • Rotational kinetic energy: Krot=12Iω2K_{rot} = \frac{1}{2}I\omega^2

  • Mechanical energy of a system with an object rotating about a stationary axle: E<em>mech=K</em>rot+U<em>G=12Iω2+Mgy</em>cmE<em>{mech} = K</em>{rot} + U<em>G = \frac{1}{2}I\omega^2 + Mgy</em>{cm}

12.4 Calculating Moment of Inertia

  • Moment of inertia (I): measures an object's resistance to changes in rotational motion.

    • Depends on axis location and mass distribution.

    • I=<em>im</em>iri2I = \sum<em>{i} m</em>{i}r_{i}^2 for discrete particles.

    • I=r2dmI = \int r^2 dm for continuous objects.

  • Parallel-axis theorem: I=Icm+Md2I = I_{cm} + Md^2, where dd is the distance from the axis of interest to a parallel axis through the center of mass.

12.5 Torque

  • Torque (τ\tau): rotational equivalent of force, measures the effectiveness of a force to cause rotation.

    • τ=rFsinϕ=rFt=Fd\tau = rF \sin{\phi} = rF_t = Fd

    • SI units: Newton-meters (Nm).

  • Positive torque: counterclockwise rotation.

  • Negative torque: clockwise rotation.

  • Net torque: τ<em>net=</em>iτi\tau<em>{net} = \sum</em>{i} \tau_i

  • Torque due to gravity: τ<em>grav=Mgx</em>cm\tau<em>{grav} = -Mgx</em>{cm}

12.6 Rotational Dynamics

  • Newton’s second law for rotational motion: α=τnetI\alpha = \frac{\tau_{net}}{I}

12.7 Rotation About a Fixed Axis

  • Ropes and Pulleys

12.8 Static Equilibrium

  • Static equilibrium: object is stationary with no net force and no net torque.

    • Fi=0\sum \vec{F}_i = 0

    • τi=0\sum \tau_i = 0

  • Critical Angle: θc=tan1t2h\theta_c = tan^{-1} {\frac{t}{2h}}

    • tt is track width, hh is the the height of center of mass

12.9 Rolling Motion

  • Rolling without slipping condition: vcm=Rωv_{cm} = R\omega

  • Kinetic energy of a rolling object: K<em>rolling=K</em>rot+K<em>cm=12I</em>cmω2+12Mvcm2K<em>{rolling} = K</em>{rot} + K<em>{cm} = \frac{1}{2}I</em>{cm}\omega^2 + \frac{1}{2}Mv_{cm}^2

12.10 The Vector Description of Rotational Motion

  • Angular velocity vector (ω\vec{\omega}): magnitude is angular speed, direction is along the axis of rotation (right-hand rule).

  • Torque vector: τ=r×F\vec{\tau} = \vec{r} \times \vec{F}

12.11 Angular Momentum

  • Angular momentum of a particle: L=r×p=mrνsinβ\vec{L} = \vec{r} \times \vec{p} = mr \nu \sin{\beta}

  • Angular momentum for an extended object: L=IωL = I\omega

  • Conservation Laws: If the net external torque on a system is zero, the total angular momentum is conserved.

12.12 Precession of a Gyroscope