Electromagnetic Radiation and Quantum Theory
Wave or Particle?: The Nature of Light
- Physicists debated whether light was particles or waves.
- Evidence suggested light behaved as both particles and electromagnetic waves by 1900.
- However, the wave theory had limitations.
Ultraviolet Catastrophe
- Problem: The light-as-wave theory predicted an "ultraviolet catastrophe."
- Objects emit electromagnetic (EM) radiation due to vibrating electrons.
- Wave theory predicted that as frequency increases (shorter wavelengths), energy increases steadily.
- Observed: This holds true for visible light, but diverges in the ultraviolet range.
- Catastrophe: Very hot objects (stars) would emit all energy instantly if the prediction were true.
Photoelectric Effect
- Certain metallic materials are photosensitive, emitting electrons (photoelectrons) when interacting with EM radiation.
- Electrons gain energy (K), but require work (work function, ϕ) to be freed.
- Wave Theory Prediction: More intensity should eject more electrons with greater energy.
- Experimental Result: Below a threshold frequency, no electrons are ejected, regardless of intensity.
Planck's Quantum Theory
- In 1900, Max Planck proposed a new model to solve these problems.
- EM radiation is not emitted continuously, but in discrete packets of energy (En) called quanta.
- This suggested light was not a wave, confusing scientists.
Einstein and the Photon
- In 1905, Albert Einstein showed that quantum energy packets are particle-like photons.
- Photons are the smallest unit of electromagnetic radiation.
- EM radiation is composed of photons with specific frequencies and quantized energy.
- Photon energy is proportional to frequency: E=hv, where E is energy, v is frequency, and h is Planck’s constant.
- Planck's constant: h=6.63⋅10−34
Wave-Particle Duality
- Light is both a particle and a wave depending on the situation.
- Every particle can also be described as a wave.
- These small units are often called quanta.
Photon Energy Calculation Example
- Problem: Find the energy of a photon with a wavelength of 10 nm.
- Find the frequency (f): 10nm3×108m/s=f=3×1016Hz (note: conversion to meters is implicit in this calculation)
- Use Planck's constant to find energy: E=(6.63×10−34)(3×1016Hz)=1.989×10−17J
- Convert Joules to electron Volts: 1.6×10−19J1.989×10−17J=124eV