Mean Value Theorem for Integrals and Applications

The Mean Value Theorem for Integrals

  - Definition: If a function f(x)f(x) is continuous on the closed interval [a,b][a, b], then there exists at least one number cc in the interval such that the following holds:
     f(c) = rac{1}{b-a} imes ext{Area under } f(x) ext{ from } a ext{ to } b

  • Visual Demonstration:
      - Example given where the area under f(x)f(x) from x=0x=0 to x=4x=4 calculated to be approximately 21.321.3.
      - The implication is that there exists a cc such that
       f(c) = rac{1}{4 - 0} imes 21.3 ext{ or } f(c) = rac{21.3}{4} ext{ which gives us the average value of } f(x).

Finding the Average Value of a Function on an Interval

  • Learning Objective: CHA-4.B: Determine the average value of a function using definite integrals.

Average Value Calculation

  • Formula: If f(x)f(x) is integrable on a closed interval [a,b][a, b], the average value of f(x)f(x) is given by:
       ext{Average Value} = rac{1}{b-a} imes extstyleigint_{a}^{b} f(x) ext{ dx}

Examples

Example 1: Using Actual Function Values
  • Let ( f(x) = 2\cdot rac{(x^2)}{12} ) over the interval [2,5][2, 5].
  • Step A: Find the average value of f(x)f(x) on the given interval.
  • Step B: Find cc such that the average value of f(x)f(x) equals f(c)f(c).
Example 2: Integrating Function
  • Given function is f(x)=x23f(x) = x^2 - 3 over the interval [1,4][1, 4].
  • Step A: Calculate average value.
  • Step B: Determine value(s) of cc per the Mean Value Theorem for Integrals.

Application of Integration – Estimation of Milk Volume

Example 3: Got Milk?
  • Scenario: Cows are milked over a period of 2 hours. Model milk volume in the tank as a function M(t)M(t), where M(t)M(t) is increasing and M(0)=300M(0) = 300 gallons.
  • Table Data: Given values for M(t)M(t) at specific times:
        - M(0)=300M(0) = 300
        - M(20)=780M(20) = 780
        - M(50)=1640M(50) = 1640
        - M(90)=3360M(90) = 3360
        - M(120)=4250M(120) = 4250
  • Tasks:
      - a. Estimate total volume pumped into the tank over the 2-hour span; explain units.
      - b. Use table data for evaluation.
      - c. Approximate with a right Riemann sum using 4 subintervals from the table, explaining if it overestimates or underestimates.

Particle Motion – Integration Applications

Concept Overview

  • Recall the motion equations for a particle moving on a line: Position s(t)s(t), velocity v(t)v(t), and acceleration a(t)a(t).

Example 1: Using Technology

  • Given velocity v(t)v(t) and the position s(t)s(t).
      - Find times when speed is 5, integral expression for position.
      - Analyze the direction changes and speed increases/decreases.

Expressions and Their Meanings in Motion

ExpressionMathematical Translation
Initial positions(0)s(0)
Particle at restv(t)=0v(t) = 0
Moving to the rightv(t) > 0
Moving to the leftv(t) < 0
Average velocity rac{1}{b-a} extstyleigint_{a}^{b} v(t) ext{ dt}
Displacements(b)s(a)s(b) - s(a)
Position changes directionFinds points where v(t)=0v(t) = 0

Volume Calculations Using Known Cross Sections

Typical Shapes and Volume Formulas

  • Square: Side length=s, Area= s2s^2, Volume= extAreaimesextHeightext{Area} imes ext{Height}.
  • Rectangle: Area= lwlw, Volume= AimeshA imes h.
  • Semi-Circle: Radius rr, Area= rac12imesextareaoffullcirclerac{1}{2} imes ext{area of full circle}, Volume= Area $ imes$ Height.
  • Triangular Cross Sections: Area= rac{1}{2} ase imes height.

Volume of Solids of Revolution

  • Disk Method:
      - For rotation around x-axis:
      V = extstyle igint_{a}^{b} ext{Area}(R(x)) ext{ dx} = extstyle igint_{a}^{b} rac{ ext{Area}(R^2)}{ ext{height}} ext{ dx}
  • Washer Method:
      - Volume expressed as:
      V = extstyle igint_{a}^{b} ig( R(y)^2 - r(y)^2 ig) dy

Applications of Definite Integrals in Accumulation Problems

  - Interpreting integrals to model physical phenomena like snow accumulation or entries in a contest.
  - Careful analysis leads to dealing with continuous functions in practical applications.